Note: we don't specify the size of arrays in the declaration. Declaration of Arrays
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AP Chapter 13 Worksheet 4 Arrays continued page 4 of 8. II. Refer to the
following classes for Questions #5-7. public class Ticket. { private String myRow;.
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postcond: the array which is returned has a length equal to the number of Integers in the ArrayList. // and all Integers
Name ___________________ Per ___ Arrays Worksheet - Single Dimension
Homework Try to complete these by hand. Resist the temptation of coding them with a computer and relying on it as a crutch. You need to get used to writing correct code by using careful thought, a drawing, and the tracing techniques modeled for you in class. You do not get a computer for the AP exam. Complete the following methods by hand: 1.
a.
// precond: nums.length >= 1 // returns the index of the largest integer in the nums array (first such index if more than one) public int findPosOfLargest(int[] nums)
b.
// precond: nums.size() >= 1 // postcond: returns the largest Integer object (first such Integer if more than one) public Integer findLargest(ArrayList nums)
c.
// precond: nums.size() >= 1 // postcond: return the location of the largest String object(lexicographically) in words public int findPosOfLargest(ArrayList words)
2. a.
b.
// precond: // postcond: // public int[]
ArrayList contains at least 1 integer the array which is returned has a length equal to the number of Integers in the ArrayList and all Integers(the int values) have been placed into the array createVectorFromArrayList(ArrayList list)
// precond: // postcond: // // // public void
list is not null all elements contained in list are in reverse order – so, for example, if “A”, “B”, “C” were in the list to begin with, then “C”, “B”, “A” would be the elements when done. You may not create more data structures to help you – you may use temporary variables but they may not be arrays or ArrayLists. reverse(ArrayList a)
3. a.
// precond: nums.length >= 1 // postcond: returns the first location where value occurs in the array – if the value // does not occur, return -1 public int posInArray(int[] nums, int value)
b.
// precond: list.size() >= 1 // postcond: returns the index of the first occurrence of s within list, -1 if not in ArrayList // note: after you write this, write down what you’ve learned public int posInArrayList(ArrayList list, SomeObject s)
4.
/* removes all occurrences of s from nums */ public void removeAll(ArrayList nums, SomeObject s)
5.
/*
the function receives a String and a vector whose elements are in ascending order - it returns the vector with the new String inserted into its proper place (e.g., let word = “g”, array = a c c f r s v w and the function returns the vector a c c f g r s v w)
*/ // precond:
words.length >= 2, elements in words are in ascending order, words[words.length-1] is to be considered empty so we have somewhere to insert the element // postcond: word has been placed into the correct location within words and all other elements have been moved accordingly in order to maintain order public void insertIntoVector(String[] words, String word)