Calculating Critical Path & Float for a Network Diagram - FreePMStudy

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(ES). Calculating Critical Path & Float for a Network Diagram. ➢ Find out the length of all the paths in the network diagram. ➢ The longest path is the critical path.
Calculating Critical Path & Float for a Network Diagram Late Start (LS) Early Start (ES)

Task Name, Duration (D)

Late Finish (LF) Early Finish (EF)

 Find out the length of all the paths in the network diagram  The longest path is the critical path  Float = EF - LF = ES - LS

Calculating Critical Path for a Network Diagram Identify tasks, durations & dependencies. 5 days

Task 2

4 days 4 days

Task 1

Task 5

3 days Task 3

7 days Task 4

Step 1: Draw a Network Diagram For forward pass, calculate the Early Start (ES) and Early Finish (EF). Task 2, 5 days 4 Task 1, 4 days 0

9 Task 5, 4 days 14 18

4 Task 3, 3 days 4

7

Task 4, 7 days 7

14

Task 5 is dependent on Task 2 and Task 4 being complete. So, ES for Task 5 is 14 days (dependent on Task 4, which is the longer task.

Step 2: Determine Critical Path To determine critical path, calculate length (durations) of all the paths:

 Length of all tasks: • Task1 → Task2 → Task5 = 4 + 5 + 4 = 13 days • Task1 → Task3 → Task4 → Task5 = 4 + 3 + 7 + 4 = 18 days  The longest path is the critical path

 Critical path = longest path = 18 days  Critical Path = Task1 → Task3 → Task4 → Task5

Step 3: Calculate Float in all tasks – Backward Pass ES = Early Start EF = Early Finish LS = Late Start LF = Late Finish 0

9

14

Task 2, 5 days

4

14 18 Task 5, 4 days 14 18

9

4

Task 1, 4 days 0

4

4 Task 3, 3 days 4

7

7

14

Task 4, 7 days 7

7

14

For all tasks on Critical Path (Task1, Task 3, Task 4, Task 5), EF = LF & ES = LS Thus, float (slack) for tasks on Critical Path = LF – EF = 0 Float for Task 2 = LF – EF = 14 – 9 = 5 days

Step 4: Calculate Project Float  Customer requests an end date of 25 days.  Project Float is the total amount of time that the project can be delayed without delaying the project completion date required by the customer. 25 days – 18 days = 7 days.  Project float can be negative when the date imposed by the customer is before the duration required in the project schedule.  For negative project float, the project must be crashed or fast-tracked.  Crashing is a technique used to decrease the duration of the project by assigning additional resources to tasks and decreasing the duration required for those tasks.

 Fast Tracking is a technique used to shorten project time by scheduling some activities concurrently that were originally scheduled sequentially.