MatSE 280: Introduction to Engineering Materials ©D.D. Johnson 2004, 2006,
2007-08 ... By chemical functionality (e.g. polyacrylates, polyamides, polyethers,
polyeurethanes ... Vinyl polymers (one or more H's of ethylene can be substituted
).
Chapter 4- Polymer Structures
Chapter 4- Polymer Structures ISSUES TO ADDRESS... What are the basic • Classification? • Monomers and chemical groups? • Nomenclature? • Polymerization methods? • Molecular Weight and Degree of Polymerization? • Molecular Structures? • Crystallinity? • Microstructural features?
TEM of spherulite structure in natural rubber(x30,000). • Chain-folded lamellar crystallites (white lines) ~10nm thick extend radially.
MatSE 280: Introduction to Engineering Materials
©D.D. Johnson 2004, 2006, 2007-08
MatSE 280: Introduction to Engineering Materials
Polymer Microstructure
©D.D. Johnson 2004, 2006, 2007-08
Polymer Microstructure
• Polymer = many mers • Covalent chain configurations and strength: More rigid
Van der Waals, H Adapted from Fig. 14.2, Callister 6e.
Polyethylene perspective of molecule Direction of increasing strength Adapted from Fig. 14.7, Callister 6e.
A zig-zag backbone structure with covalent bonds MatSE 280: Introduction to Engineering Materials
©D.D. Johnson 2004, 2006, 2007-08
MatSE 280: Introduction to Engineering Materials
©D.D. Johnson 2004, 2006, 2007-08
1
Common Examples
Common Classification
- Textile fibers: polyester, nylon…
• Thermoplastics: polymers that flow more easily when squeezed, pushed, stretched, etc. by a load (usually at elevated T).
- IC packaging materials.
– Can be reheated to change shape.
- Resists for photolithography/microfabrication.
• Thermosets: polymers that flow and can be molded initially but their shape becomes set upon curing.
- Plastic bottles (polyethylene plastics).
– Reheating will result in irreversible change or decomposition.
- Adhesives and epoxy.
• Other ways to classify polymers. – By chemical functionality (e.g. polyacrylates, polyamides, polyethers, polyeurethanes…). – Vinyl vs. non-vinyl polymers. – By polymerization methods (radical, anionic, cationic…). – Etc…
- High-strength/light-weight fibers: polyamides, polyurethanes, Kevlar… - Biopolymers: DNA, proteins, cellulose… MatSE 280: Introduction to Engineering Materials
MatSE 280: Introduction to Engineering Materials
©D.D. Johnson 2004, 2006, 2007-08
Common Chemical Functional Groups H
Ethylene (ethene)
Methyl alcohols
C C H
H
H
Propylene (propene)
Common Hydrocarbon Monomers Alcohols
H
©D.D. Johnson 2004, 2006, 2007-08
H
=
C C H
H
Ethers
Dimethyl Ether
Acids
Acetic acid
C H H
1-butene 2-butene trans
cis
Aldehydes Acetylene (ethyne) Saturated hydrocarbons (loose H to add atoms) MatSE 280: Introduction to Engineering Materials
Unsaturated hydrocarbons (double and triple bonds) ©D.D. Johnson 2004, 2006, 2007-08
Formaldehyde
H C C H
Aromatic hydrocarbons MatSE 280: Introduction to Engineering Materials
Phenol ©D.D. Johnson 2004, 2006, 2007-08
2
Nomenclature
Some Common Polymers
Monomer-based naming: poly________
Common backbone with substitutions Polyacrylonitrile (PAN)
H
H
C
C
H
C
Monomer name goes here
e.g. ethylene -> polyethylene
N
Vinyl polymers (one or more H’s of ethylene can be substituted) H
H C C
H
X
H
H
C
C
H
X
if monomer name contains more than one word: poly(_____ ____) Monomer name in parentheses
e.g. acrylic acid -> poly(acrylic acid) Note: this may lead to polymers with different names but same structure. H H H H
…
C C C C
H H H H
…
…
H H H H
polyethylene MatSE 280: Introduction to Engineering Materials
polymethylene
MatSE 280: Introduction to Engineering Materials
©D.D. Johnson 2004, 2006, 2007-08
Polymerization Methods
…
C C C C
H H H H
©D.D. Johnson 2004, 2006, 2007-08
Polymerization Methods A. Free Radical Polymerization
A. Free Radical Polymerization 1. Initiation H
R
H
R
C C
Free radical initiator (unpaired electron)
H
H
2. Propagation
H
H
H
C
C
H
monomer
Radical transferred
R
H
H
C
C
H
H
H
H
H
R
C C H
H
H C C
H
H
H
H
C
C
C
C
H
H
H
H
H
H
R
H
H
H
H
H
H
C
C
C
C
C
C
H
H
H
H
H
H
H R
H C
R H C
sp2 carbons
C
C
H
H σ bonds π bond
MatSE 280: Introduction to Engineering Materials
H
H
sp3 carbon
©D.D. Johnson 2004, 2006, 2007-08
H
R
H
H C
H
H C
H H
H
C
C
Both carbon atoms will change from sp 2 to sp 3.
H
MatSE 280: Introduction to Engineering Materials
©D.D. Johnson 2004, 2006, 2007-08
3
Polymerization Methods
Polymerization Methods Loses water (condensation)
B. Stepwise polymerization A. Free Radical Polymerization 3. Termination
O H2N
R
H
H
C
C
H
H
+
R
R
H
H
C
C R
H
H
R
C
O
O
+
H2N
OH
R
C
H2N
OH
R
C
N H
R
C
OH
+
Proteins (polypeptides have similar composition)
R
H
H
C
C
H
H
+
R
H
H
C
C
H
H
R
H
H
H
H
C
C
C
C
H
H
H
H
O H N H C C R
R
Various R groups…
∑N j M j
O
H
€
j
∑N j M j =
Total # of polymer chains
j
∑ N j M€2j
∑W j M j Mw =
j
∑W j
=
j
20 + 16 + 10 M monomer = 15.3M monomer 3
∑N j =
Total weight
Weight average € molecular weight:
€ 10 mers
Mj = jmo mass of polymer chain with length j (mo = monomer molecular weight).
∑N j
j
16 mers
Nj = # of polymer chains with length j
j
=
∑N j j
©D.D. Johnson 2004, 2006, 2007-08
H
n
©D.D. Johnson 2004, 2006, 2007-08
mo ∑ N j j
j
Mn = Note:
MatSE 280: Introduction to Engineering Materials
+ (n-1)
C
Number average molecular weight:
Not only are there different structures (molecular arrangements) …… but there can also be a distribution of molecular weights (i.e. number of monomers per polymer molecule).
This is what is called number average molecular weight.
O R
n
MatSE 280: Introduction to Engineering Materials
Molecular Weights
Average molecular weight =
H N
Anionic polymerization, cationic polymerization, coordination polymerization…
©D.D. Johnson 2004, 2006, 2007-08
20 mers
H
C. Other methods
Intentional or unintentional molecules/impurities can also terminate.
MatSE 280: Introduction to Engineering Materials
O
H
O
In general:
€
j
W j = N jM j
∑N j M j j
+1 ∑ N j M αj €
M=
j
∑ N j M αj
If α = 0 then
Mn
If α = 1 then Mw
j
MatSE 280: Introduction to Engineering Materials
€©D.D. Johnson 2004, 2006, 2007-08 €
€
4
Molecular Weights
Molecular Weight: Different Notations In Callister Textbook
In Lecture Notes
Mn = ∑ x i Mi
∑N j M j Mn =
j
i
∑N j
Ni xi = ∑N j
j
∑ N j M 2j €
Mw =
j
€
j
∑N j M j
Why do we care about weight average MW? -some properties are dependent on MW (larger MW polymer chains can contribute to overall properties more than smaller ones).
Ni M i wi = ∑N j M j j
Mw = ∑w i Mi
€
€
j
MatSE 280: Introduction to Engineering Materials
Distribution of polymer weights
i
©D.D. Johnson 2004, 2006, 2007-08
Examples – Light scattering: larger molecules scatter more light than smaller ones. Infrared absorption properties: larger molecules have more side groups and light absorption (due to vibrational modes of side groups) varies linearly with number of side groups. MatSE 280: Introduction to Engineering Materials
©D.D. Johnson 2004, 2006, 2007-08
€
€
Example 1
Polydispersity and Degree of Polymerization Polydispersity:
Mw ≥1 Mn
Compute the number-average degree of polymerization for polypropylene, given that the number-average molecular weight is 1,000,000 g/mol.
When polydispersity = 1, system is monodisperse.
€
Degree of Polymerization:
Mer molecular weight of PP is
Number avg degree of polymerization
Weight avg degree of polymerization
€ MatSE 280: Introduction to Engineering Materials
€
C3H6
What is “mer” of PP?
nn =
Mn mo
M nw = w mo
©D.D. Johnson 2004, 2006, 2007-08
mo=3AC+6AH =3(12.01 g/mol)+6(1.008 g/mol) = 42.08 g/mol
Number avg degree of polymerization
nn =
Mn 106 g / mol = = 23,700 mo 42.08g / mol
MatSE 280: Introduction to Engineering Materials
©D.D. Johnson 2004, 2006, 2007-08
€
5
Example 2 (a, b, and c)
Example 2 (cont.)
A. Calculate the number and weight average degrees of polymerization and polydispersity for a polymer sample with the following distribution. Avg # of monomers/chain 10 100 500 1000 5000 50,000
nn =
=
j
j
=
j
j
∑ jN ∑N j
j
Relative abundance 5 25 50 30 10 5
Mw if monomer is methylmethacrylate (5C, 2O, and 8H) So m 0= 5(12)+2(16)+8(1)= 100 g/mol
j
2
o
j
j
j
Polydispersity:
2
∑ ( jm ) N ∑ j N = ∑ N ( jm ) ∑ jN j
j
o
j
j
Note: m 0 cancels in all these!
j
©D.D. Johnson 2004, 2006, 2007-08
€ MatSE 280: Introduction to Engineering Materials
Example 2 (cont.) C. If we add polymer chains with avg # of monomers = 10 such that their relative abundance changes from 5 to 10, what are the new number and weight average degrees of polymerization and polydispersity? nn =
Mn = mo =
nw =
∑ jN ∑N j
j
j
Mw 3,580,000 = ~ 12.52 Mn 286,040
€
5 *10 2 + 25 *100 2 + 50 * 500 2 + 30 *1000 2 + 10 * 5000 2 + 5 * 50000 2 = = 35, 800 5 *10 + 25 *100 + 50 * 500 + 30 *1000 + 10 * 5000 + 5 * 50000 MatSE 280: Introduction to Engineering Materials
©D.D. Johnson 2004, 2006, 2007-08
Sequence isomerism For an asymmetric monomer T
Add 5 more monomers of length 10 ….
H
+
T
H
j
10 * 10 + 25 * 100 + 50 * 500 + 30 * 1000 + 10 * 5000 + 5 * 50000 = 2750 10 + 25 + 50 + 30 + 10 + 5
e.g. poly(vinyl fluoride):
2 Mw ∑ j j N j = = 35,800 mo ∑ j jN j
Note: significant change in number average (3.8 %) but no change in weight average!
M w 3, 580, 000 = ~ 13 Mn 275000
MatSE 280: Introduction to Engineering Materials
©D.D. Johnson 2004, 2006, 2007-08
H
T
H
T
H
H
T
H
T
T
H
e.g. PMMA
F
H
H
F
H
H
H
C
C
C
C C
C
C
C
H
H3C H3C H3C O O O O O O O C H C H C H C
H
H
H
F H
H
H
F
C
C
C
C C
C
H
CH3 H
CH3H
CH3 H
T to T H to H
Polydispersity:
T
H
H to T
€
CH3 | -CH2-C| CO2CH3
Mn = nnmo = 2860.4(100g / mol ) = 286,040g / mol Mw = nw mo = 35,800(100g / mol ) = 3,580,000g / mol
j
5 *10 + 25 *100 + 50 * 500 + 30 *1000 + 10 * 5000 + 5 * 50000 = 2860.4 5 + 25 + 50 + 30 + 10 + 5
Mw 1 = mo mo
nw =
∑ jN ∑N
M n m0 = mo m0
B. If the polymer is PMMA, calculate number and weight average molecular weights.
Random arrangement
MatSE 280: Introduction to Engineering Materials
H3C
O
H to T
H to T
C
C CH3
H to T
Exclusive H to T arrangement (Why?) ©D.D. Johnson 2004, 2006, 2007-08
6
Polymer Molecular Configurations • Regularity and symmetry of side groups affect properties
Polymer Geometrical Isomerism • Regularity and symmetry of side groups affect properties
Can it crystallize? Melting T?
Polymerize
H
H
• Stereoisomerism: (can add geometric isomerism too) Syndiotactic Alternating sides Atactic Randomly placed
- Conversion from one stereoisomerism to another is not possible by simple rotation about single chain bond; bonds must be severed first, then reformed!
-Conversion from one isomerism to another is not possible by simple rotation about chain bond because double-bond is too rigid! -See Figure 4.8 for taxonomy of polymer structures MatSE 280: Introduction to Engineering Materials
©D.D. Johnson 2004, 2006, 2007-08
Polymer Structural Isomerism 2 1
H2C
C
C H
• Covalent chain configurations and strength:
4
CH3
©D.D. Johnson 2004, 2006, 2007-08
Polymer Microstructure
Some polymers contain monomers with more than 1 reactive site e.g. isoprene
trans-structure
with R= CH3 to form rubber Cis-polyisoprene trans-polyisoprene
Isotactic On one side
MatSE 280: Introduction to Engineering Materials
cis-structure
More rigid
Van der Waals, H
CH2 3
trans-isoprene
Direction of increasing strength trans-1,4-polyisoprene
CH3 C H2
C
C H
trans-1,2-polyisoprene
H2 C
H2 C n
H2 C H C
n
C H3C
Adapted from Fig. 14.7, Callister 6e.
3,4-polyisoprene
CH H2C
C H2C
Short branching n
CH3
Long branching
Note: there are also cis-1,4- and cis-1,2-polyisoprene MatSE 280: Introduction to Engineering Materials
©D.D. Johnson 2004, 2006, 2007-08
MatSE 280: Introduction to Engineering Materials
Star branching
Dendrimers
©D.D. Johnson 2004, 2006, 2007-08
7
CoPolymers
Molecular Structure
• Random, Alternating, Blocked, and Grafted
How do crosslinking and branching occur in polymerization? 1. Start with or add in monomers that have more than 2 sites that bond with other monomers, e.g. crosslinking polystyrene with divinyl benzene
• Synthetic rubbers are often copolymers.
…
e.g., automobile tires (SBR)
stryene
…
polystyrene
Styrene-Butadiene Rubber random polymer …
Control degree of + crosslinking by styrene-divinyl styrene benzene ratio divinyl benzene
…
crosslinked polystyrene
Monomers with trifunctional groups lead to network polymers. MatSE 280: Introduction to Engineering Materials
MatSE 280: Introduction to Engineering Materials
©D.D. Johnson 2004, 2006, 2007-08
Molecular Structure
Example 3 Nitrile rubber copolymer, co-poly(acrylonitrile-butadiene), has
Branching in polyethylene (back-biting) H2C CH2
R
H2 C
C H2
H2 C
Same as
C H2
H2 C
Mn = 106,740g / mol C H
H
R
CH2
Radical moves to a different carbon
C
CH2
(H transfer)
C H H2
€
H
H H
nn = 2000
Calculate the ratio of (# of acrylonitrile) to (# of butadiene).
H
H C
©D.D. Johnson 2004, 2006, 2007-08
C
H
CH2
C
R
C H H2
3 C = 3 x 12.01 g/mol 3 H = 3 x 1.008 g/mol 1 N = 1 x 14.007 g/mol
€
4 C = 4 x 12.01 g/mol 6 H = 6 x 1.008 g/mol m 0= 54.09 g/mol
m 0= 53.06 g/mol
CH2
1,4-addition product
We need to use an avg. monomer MW:
Polymerization continues from this carbon
mo =
Mn 106,740 = = 53.57g / mol nn 2000
mo = f1m 1 + f2m 2 = f1(m 1 − m 2 ) + m 2 Process is difficult to avoid and leads to (highly branched) low-density PE . When there is small degree of branching you get high-density PE.
MatSE 280: Introduction to Engineering Materials
f1 =
€ m 0 − m 2 53.37 − 54.09 = = 0.7 € − 54.09 m 1 − m 2 53.06
MatSE 280: Introduction to Engineering Materials
©D.D. Johnson 2004, 2006, 2007-08
€
€
f2 = 1− f1 = 0.3
f2 0.7 = →7 :3 f1 0.3
©D.D. Johnson 2004, 2006, 2007-08
€
8
Vulcanization
Molecular Weight and Crystallinity
See also sect. in Chpt. 8
• Crosslinking in elastomers is called vulcanization, and is achieved by irreversible chemical reaction, usually requiring high temperatures.
• Molecular weight, Mw: Mass of a mole of chains.
• Sulfur compounds are added to form chains that bond adjacent polymer backbone chains and crosslinks them. • Unvulcnaized rubber is soft and tacky an poorly resistant to wear.
• Tensile strength (TS):
e.g., cis-isoprene
Single bonds
--often increases with M w. --Why? Longer chains are entangled (anchored) better.
Stress-strain curves
• % Crystallinity: % of material that is crystalline. Double bonds
+ (m+n) S
--TS and E often increase with % crystallinity. --Annealing causes crystalline regions to grow. % crystallinity increases.
(S)m (S)n
crystalline region amorphous region
Adapted from Fig. 14.11, Callister 6e. MatSE 280: Introduction to Engineering Materials
MatSE 280: Introduction to Engineering Materials
©D.D. Johnson 2004, 2006, 2007-08
Polymer Crystallinity polyethylene
Volume fraction of crystalline component.
• Some are amorphous. • Some are partially crystalline (semi-crystalline). • Why is it difficult to have a 100% crystalline polymer?
%crystallinity =
ρc ( ρ s − ρa ) × 100% ρ s ( ρc − ρa )
ρs = density of specimen in question ρa = density of totally amorphous polymer ρc = density of totally crystalline polymer
%crystallinity =
€
Mcrystalline Mtotal
ρ V ρ × 100% = c c × 100% = c fc × 100% ρsVs ρs
Mtotal = Mcrystalline + Mamophous
©D.D. Johnson 2004, 2006, 2007-08
Using definition of volume fractions:
Ms = Mc + Ma ρsVs = ρcVc + ρaVa V V ρs = ρc c + ρa a Vs Vs
V fc = c Vs
V fa = a Vs
= ρc fc + ρa fa = ρc fc + ρa (1− fc ) = fc ( ρc − ρa ) + ρa €
€ ρ − ρa fc = s ρc − ρa
€ Substituting in f c into the original definition:
MatSE 280: Introduction to Engineering Materials
©D.D. Johnson 2004, 2006, 2007-08
MatSE 280: Introduction to Engineering Materials
ρ ( ρ − ρa ) %crystallinity = c s × 100% ρ s ( ρc − ρa ) € ©D.D. Johnson 2004, 2006, 2007-08
9
Polymer Crystallinity Degree of crystallinity depends on processing conditions (e.g. cooling rate) and chain configuration.
Semi-Crystalline Polymers Fringed micelle model: crystalline region embedded in amorphous region. A single chain of polymer may pass through several crystalline regions as well as intervening amorphous regions.
Cooling rate: during crystallization upon cooling through MP, polymers become highly viscous. Requires sufficient time for random & entangled chains to become ordered in viscous liquid. Chemical groups and chain configuration: More Crystalline
Less Crystalline
Smaller/simper side groups
Larger/complex side groups
Linear
ρ − ρa fc = s ρc − ρa
Highly branched
Crystalline volume fractions Important
Crosslinked, network Isotactic or syndiotactic
Random
MatSE 280: Introduction to Engineering Materials
©D.D. Johnson 2004, 2006, 2007-08
Semi-Crystalline Polymers Chain-folded model: regularly shaped platelets (~10 – 20 nm thick) sometimes forming multilayers. Average chain length
€
MatSE 280: Introduction to Engineering Materials
©D.D. Johnson 2004, 2006, 2007-08
Semi-Crystalline Polymers Spherulites: Spherical shape composed of aggregates of chain-folded crystallites.
>> platelet thickness.
Natural rubber
Cross-polarized light through spherulite structure of PE.
MatSE 280: Introduction to Engineering Materials
©D.D. Johnson 2004, 2006, 2007-08
MatSE 280: Introduction to Engineering Materials
©D.D. Johnson 2004, 2006, 2007-08
10
Diblock copolymers
Thermoplastics vs Thermosets • Thermoplastics:
T
--little cross linking --ductile --soften w/heating --polyethylene (#2) polypropylene (#5) polycarbonate polystyrene (#6) Representative polymer-polymer phase behavior with different architectures:
MatSE 280: Introduction to Engineering Materials
Molecular weight
MatSE 280: Introduction to Engineering Materials
©D.D. Johnson 2004, 2006, 2007-08
What Are Expected Properties?
• Packing of “spherical” atoms as in ionic and metallic crystals led to crystalline structures.
• Would you expect melting of nylon 6,6 to be lower than PE ? O H O H || | || | − N − C − N −C − C − N −C − | | | | | H H H H 6 H 4
H H −C− C− H H
nylon 6,6 • How polymers pack depend on many factors: • long or short, e.g. long (-CH 2-)n. • stiff or flexible, e.g. bendy C-C sp 3. • smooth or lumpy, e.g., HDPE. • regular or random • single or branched • slippery or sticky, e.g. C-H covalent (nonpolar) joined via vdW.
+ +
+
O H O H || | || | − N − C − N −C − C − N −C − | | | | | H H H H 6 H 4
€
a) b)
+
polyethylene
+
+ bonds + Waals Van der
+
+ + Hydrogen bonds
€
Analogy: Consider dried (uncooked) spaghetti (crystalline) vs. cooked and buttered spaghetti (amorphous). • pile of long “stiff” spaghetti forms a random arrangement. • cut into short pieces and they align easily.
©D.D. Johnson 2004, 2006, 2007-08
Tg
Tg: from rubbery to rigid as T lowers
Packing of Polymers
MatSE 280: Introduction to Engineering Materials
Tm
--large cross linking (10 to 50% of mers) Adapted from Fig. 15.18, Callister 6e. --hard and brittle Tm: melting over wide range of T --do NOT soften w/heating depends upon history of sample --vulcanized rubber, epoxies, consequence of lamellar structure thicker lamellae, higher T m. polyester resin, phenolic resin
©D.D. Johnson 2004, 2006, 2007-08
Candle wax more crystalline than PE, even though same chemical nature.
Callister, rubber Fig. 16.9 tough plastic
partially crystalline solid
crystalline solid
• Thermosets:
A) Phase separation with mixed LINEAR homopolymers. B) Mixed LINEAR homopolymers and DIBLOCK copolymer gives surfactant-like stabilized state. C) Covalent bond between blocks in DIBLOCK copolymer give microphase segregation.
F. Bates, Science 1991.
viscous liquid
mobile liquid
€
+
+
H
H
−C− C− H H
€ cohesion in Nylon vs PE? What is the source of intermolecular How does the source of linking affect temperature?
With H-bonds vs vdW bonds, nylon is expected to have (and does) higher melting T. MatSE 280: Introduction to Engineering Materials
©D.D. Johnson 2004, 2006, 2007-08
11
What Are Expected Properties?
What Are Expected Properties?
Which polymer more likely to crystallize? Can it be decided?
Which polymer more likely to crystallize? Can it be decided?
Linear syndiotactic polyvinyl chloride
Networked Phenol-Formaldehyde (Bakelite)
Linear isotactic polystyrene
Linear and highly crosslink cis-isoprene
+
H
+ H 20 • For linear polymers, crystallization is more easily accomplished as chain alignment is not prevented. • Crystallization is not favored for polymers that are composed of chemically complex mer structures, e.g. polyisoprene . • Linear and syndiotactic polyvinyl chloride is more likely to crystallize. • The phenyl side-group for PS is bulkier than the Cl side-group for PVC. • Generally, syndiotactic and isotactic isomers are equally likely to crystallize.
MatSE 280: Introduction to Engineering Materials
©D.D. Johnson 2004, 2006, 2007-08
What Are Expected Properties? Which polymer more likely to crystallize? Can it be decided? alternating Poly(Polystyrene-Ethylene) Copolymer
• Networked and highly crosslinked structures are near impossible to reorient to favorable alignment.
• Not possible to decide which might crystallize. Both not likely to do so.
MatSE 280: Introduction to Engineering Materials
©D.D. Johnson 2004, 2006, 2007-08
Detergents • Soap is a detergent based on animal or vegetable product, some contain petrochemicals
water
random poly(vinyl chloride-tetra-fluoroethylne) copolymer
detergent grease
• What properties of soap molecules do you need to remove grease? • “green” end must be “hydrophilic”. Why? • Opposite end must be hydrocarbon. Why?
• Alternating co-polymer more likely to crystallize than random ones, as they are always more easily crystallized as the chains can align more easily.
MatSE 280: Introduction to Engineering Materials
©D.D. Johnson 2004, 2006, 2007-08
Water must be like oxygen (hoard electrons and promote H-bonding)
e.g., oxy-clean® MatSE 280: Introduction to Engineering Materials
grease
©D.D. Johnson 2004, 2006, 2007-08
12
Simple polymer: Elmers glue + Borax SLIME! Chemistry
Elmer’s glue is similar to “poly (vinyl alcohol)” with formula: OH
OH
OH
OH
OH
OH
OH
OH
OH
OH
OH
OH
OH
OH
OH
this is a SHORT, n=15 chain of poly(vinyl alcohol)
Simple polymer: Elmer’s glue + Borax SLIME! Hydrolyzed molecule acts in a condensation reaction with PVA, crosslinking it. B(OH) 3 + 2H 2O B(OH) 4- + H 3O+ pH=9.2
Borax is sodium tetraborate decahydrate (B4Na 2O7 • 10 H 2O). The borax actually dissolves to form boric acid, B(OH) 3. This boric acid-borate solution is a buffer with a pH of about 9 (basic). Boric acid will accept a hydroxide OH- from water.
B(OH) 3 + 2H 2O B(OH) 4- + H 3O+ pH=9.2
Hydrolyzed molecule acts in a condensation reaction with PVA, crosslinking it. MatSE 280: Introduction to Engineering Materials
Crosslinked
©D.D. Johnson 2004, 2006, 2007-08
Range of Bonding and Elastic Properties
Crosslinking ties chains via weak non-covalent (hydrogen) bonds, so it flows slowly. MatSE 280: Introduction to Engineering Materials
©D.D. Johnson 2004, 2006, 2007-08
Summary • Polymers are part crystalline and part amorphous.
Is “slime” a thermoset or thermoplastic, or neither?
Thermoset bonding • Covalent bonds form crosslinks
Slime?
• H-bonds form crosslinks
Thermoplastic bonding • Induced dipolar bonds form crosslinks
Stiffness increases
• The more crosslinking the stiffer the polymer. And, networked polymers are like heavily crosslinked ones. • Many long-chained polymers crystallize with a Spherulite microstructure - radial crystallites separated by amorphous regions. • Optical properties: crystalline -> scatter light (Bragg) amorphous -> transparent. Most covalent molecules absorb light outside visible spectrum , e.g. PMMA (lucite) is a high clarity tranparent materials.
Where is nylon? MatSE 280: Introduction to Engineering Materials
• The more “lumpy” and branched the polymer, the less dense and less crystalline.
©D.D. Johnson 2004, 2006, 2007-08
MatSE 280: Introduction to Engineering Materials
©D.D. Johnson 2004, 2006, 2007-08
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