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Dissipativity and Gevrey Regularity of a Smoluchowski Equation P ETER C ONSTANTIN , E DRISS S. T ITI & J ESENKO V UKADINOVIC A BSTRACT. We investigate a Smoluchowski equation (a nonlinear Fokker-Planck equation on the unit sphere), which arises in modeling of colloidal suspensions. We prove the dissipativity of the equation in 2D and 3D, in certain Gevrey classes of analytic functions.

1. I NTRODUCTION The Smoluchowski equation is an equation describing the temporal evolution of the distribution ψ of directions of rod-like particles in a suspension. The equation has the form of a Fokker-Planck equation ∂t ψ = ∆ψ + div(ψ grad V ),

except that it is nonlinear and it is phrased on the unit sphere (so the Laplacian, divergence and gradient are suitably modified). One thinks of ψ dσ as the proportion of particles whose directions belong to the area element dσ on the unit sphere. The equation is nonlinear because the mean field potential V depends on ψ. If this dependence is linear, then the equation has an energy functional, and its steady solutions are solutions of nonlinear (and typically non-local) equations. Historically, the steady equation arose first, in the work of Onsager ([14]) concerning the effect of the shape of particles in a suspension on their distribution. The time dependent kinetic theory ([7]), and the particular type of potential (MaierSaupe) we study in this paper are a further development. There are relatively few 949 c , Vol. 54, No. 4 (2005) Indiana University Mathematics Journal

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P. C ONSTANTIN , E.S. T ITI & J. V UKADINOVIC

rigorous mathematical papers concerning this equation. In two previous works ([4] and [5]) mostly questions regarding the steady states were discussed. The Smoluchowski equation is dissipative. This means that the solutions, viewed as trajectories in a phase space, after a transient time, enter and remain in a bounded region of phase space. The dissipativity of the Smoluchowski equation is however a subtle matter. The energy functional is not positive definite in general, and it cannot be used directly. Z Instead, the conservation law associated to the equation, namely the fact that ψ does not change in time, needs to be used in order to prove dissipativity. In [4] dissipativity was proved in 2D in a weak phase space, (a phase space in which it is not clear that the equation is well posed), using a cancellation special to 2D. The dissipativity in three dimensions was until now an open problem. In this paper we prove among other things dissipativity in very strong analytic spaces both in two and three dimensions. The proof of Gevrey regularity and dissipativity in three dimensions uses a slightly different approach than the classical method of [9] (see also [1], [2], [8], [10], and [12]) making use of the special nature of the Fokker-Planck nonlinearity. 2. P RELIMINARIES We consider the Smoluchowski equation written in local coordinates φ = (φ1 , φ2 , . . . , φn−1 ) on the unit sphere S n−1 in Rn as: (2.1)

p 1 ∂t ψ = √ ∂i (e−V gg ij ∂j (eV ψ)). g

The potential V is given by V (x, t) = −bxi xj S ij (t), Z (2.2) 1 S ij (t) := xi (φ)xj (φ)ψ(φ, t) σ (dφ) − δij , n S n−1 √ where xi are Cartesian coordinates in Rn , σ (dφ) = g dφ the surface area, and b > 0 is a given parameter representing the intensity of the potential. As a result

of applying the product rule, (2.1) can be written in the form of a Fokker-Planck equation (2.3)

∂t ψ + Aψ = B(ψ, V ),

where

1

A = −∆g = − √

g

p ∂i ( gg ij ∂j )

is the Laplace-Beltrami operator, and p 1 B(ψ, V ) := divg (ψ∇g V ) = √ ∂i ( gg ij (∂j V )ψ). g

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Because of the dependence of V on ψ, the Smoluchowski equation is nonlinear (quadratic) in ψ. Regarding the existence, uniqueness and regularity of solutions of (2.3), it is easy to prove the following theorem (see [4], [5] for the same claim). Theorem 2.1. Let ψ0 be a nonnegative continuous function on S n−1 . The solutions of (2.3) with initial data ψ(·, 0) = ψ0 exist for all nonnegative times, are smooth, nonnegative and normalized Z

Z S n−1

ψ(φ, t) σ (dφ) =

S n−1

ψ0 (φ) σ (dφ).

In addition, they are analytic for all positive times. From now on we will choose the normalization Z S n−1

ψ(φ, t) σ (dφ) = 1.

The normalization yields that the matrix S is trace-free (Tr (S) = 0), which implies that the homogeneous quadratic polynomial V (x, t) is harmonic. This, in turn, implies that V , restricted to the sphere, is an eigenvector of A corresponding to the eigenvalue 2n: AV = 2nV . Moreover, one has the following inequality:   1 b ≤ V (x, t) ≤ . −b 1 − n n

In particular, |V (x, t)| ≤ b. The following nontrivial property of the FokkerPlanck bilinear form B will be crucial in the sequel. Lemma 2.2. For ψ, χ , V ∈ D(A) (2.4)

(B(ψ, V ), χ)g =

1 2

Z S n−1

[V (χAψ − ψAχ) − ψχAV ] σ (dφ),

where

Z (u, v)g =

is the scalar product on L2 (S n−1 ).

S n−1

uv σ (dφ)

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Proof. Assuming first that ψ, χ , V ∈ C ∞ (S n−1 ) and applying integration by parts, one has (B(ψ), χ) = Z p 1 = √ ∂i ( gg ij ∂j V ψ)χ σ (dφ) n− 1 g S Z p ij = ∂i ( gg ∂j V ψ)χ dφn−1 Z =− Z =

p V ∂j ψ gg ij ∂i χ dφn−1 +

=− Z

Z =

S n−1

 g ij ∂j V ψ∂i χ σ (dφ)

p V ψ∂j ( gg ij ∂i χ) dφn−1

Z S n−1

V g ij ∂j ψ∂i χ σ (dφ) +

S n−1

Z

=− Z =

Z



p ij gg ∂j V ψ∂i χ dφn−1

Z

S n−1

S n−1

V ψ∆g χ σ (dφ)

g ij ∂i V ∂j ψχ σ (dφ) − Z

g ij ∂i V ψ∂j χ σ (dφ) +

S n−1

S n−1

Z S n−1

S n−1

V ψ∆g χ σ (dφ)

∆g V ψχ σ (dφ)

Z

− = −(B(ψ), χ) +

Z V χ∆g ψ σ (dφ) +

S n−1

Z V χ∆g ψ σ (dφ) +

S n−1

V ψ∆g χ σ (dφ)

V (ψ∆g χ − χ∆g ψ − 2nψχ) σ (dφ),

and the statement of the lemma follows by the above and the density of C ∞ (S n−1 ) in D(A). A similar proof is obtained using ∇V ·g ∇ω =

1 (∆ (V ω) − ω∆g V − V ∆g ω) 2 g ❐

and integration by parts. 3. T HE 2D C ASE

When n = 2, the unit circle has one local coordinate φ ∈ [0, π ], and x1 (φ) = cos φ, x2 (φ) = sin φ, and g 11 = g = 1. Thus, in two dimensions, the equation can be rewritten as (3.1)

2 ∂t ψ − ∂φ ψ = ∂φ (∂φ V ψ).

The potential V can be written as a function of the local coordinate φ as: (3.2)

V (φ) = −

b

Z 2π

2

0

˜ ˜ t) dφ. ˜ cos(2(φ − φ))ψ( φ,

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In the following sections, we will use the Fourier Transform to rewrite (3.1) as a system of ODEs for which we will prove that the solutions belong to certain Gevrey classes, in which they dissipate, and are real-entire. 3.1. 2D Smoluchowski as an infinite system of ODEs. We expand ψ in Fourier series as 1 X b ψ(j, t)eijφ , ψ(φ, t) = 2π j∈Z where b ψ(j, t) =

Z 2π

e−ijφ ψ(φ, t) dφ

0

b b t) = ψ(j, t)∗ will insure that ψ is a are the Fourier coefficients. Requiring ψ(−j, real-valued function. The system (3.1) becomes a system of ODEs  b bj dψ b − 2, t)ψ( b b 2, t) − ψ(j b + 2, t)ψ(− b 2, t) , ψ(j t) = (j, t) + j 2 ψ(j, dt 2 b 0, t) = 1 in this setting. and the normalization is equivalent to ψ( One can easily verify that the evenness of the initial datum will be preserved b b t) = ψ(j, t) for by the flow. In terms of Fourier coefficients, this means ψ(−j, b 2j + 1, t) = 0, for j ∈ Z is preserved by the flow, as well. j ∈ Z. Moreover, ψ( Therefore, we can restrict our study to solutions that have the above symmetries, i.e., solutions of the form ψ(φ, t) =

∞ 1 1 X + y (t) cos(2kφ), 2π π k=1 k

where b 2k, t) = yk (t) = ψ(

Z 2π 0

cos(2kφ)ψ(φ, t) dφ.

The normalization implies y0 = 1 and |yk | ≤ 1. Notice that for such ψ the potential becomes b V (φ, t) = − y1 (t) cos(2φ).

2

In this new setting, the 2D Smoluchowski equation can be written in terms of the Fourier coefficients as an infinite system of ODEs: (3.3)

y0 = 1 yk0 + 4k2 yk = bky1 (yk−1 − yk+1 ),

k = 1, 2, . . . .

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In [4] the authors have proven that the solutions of the 2D Smoluchowski equation with nonnegative continuous initial data of the form ψ0 (φ) =

(3.4)

∞ 1 1 X y (0) cos(2kφ) + 2π π k=1 k

dissipate in the space H −1/2 (S 1 ) according to the inequality



ψ(t) 2 −1/2 ≤ b + e−8t ψ0 2 −1/2 . H H

4

Also, the existence of one determining mode was proven: If for two solutions lim |V (1) (0, t) − V (2) (0, t)| = 0,

t→∞

then

lim kψ(1) (t) − ψ(2) (t)kH −1/2 = 0.

t→∞

By S(t) we will denote the semi-group of solution operators, i.e., ψ(t) = S(t)ψ0 . The 2D Smoluchowski equation has a compact global attractor A, the maximal bounded set which satisfies S(t)A = A for all t ∈ R. Thanks to the existence of one determining mode, or the Gevrey regularity which we will prove in the next section, one can easily show that the global attractor A is finite dimensional. 3.2. Gevrey regularity and dissipativity in 2D. Let us denote the uniform state by ψu = 1/2π . Also denote ∞ X

2

ψ 2 := π ψ − ψu 2 2 1 = yk2 , L L (S ) k=1 ∞ X

2

ψ ∗ := 2−2s π ψ − ψu 2 s 1 = k2s yk2 . H H (S ) k=1

For a positive function f defined on positive integers let us define the following classes of functions:   ∞ ∞ X 1 1 X f (k) 2 + yk < ∞ Hf := ψ(φ) = yk cos(2kφ) | 2π π k=1 k k=1

and



 ∞ ∞ X 1 1 X 2 + Vf := ψ(φ) = y cos(2kφ) | kf (k)yk < ∞ , 2π π k=1 k k=1

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endowed with the ‘norms’ |ψ|f =

X  ∞ f (k) 2 1/2 yk k k=1

and

kψkf =

X ∞

kf (k)yk2

1/2 ,

k=1

respectively. For f that grows at least exponentially with k it is well known that Hf and Vf are subsets of the set of real analytic functions. Also, for each n ∈ N there exists a combinatorial constant Mn ∈ (0, ∞) depending on f , such that n k∂φ ψkL∞ ≤ Mn |ψ|f ,

ψ ∈ Hf .

Theorem 3.1. Consider the equation (3.1) for b > 4 with nonnegative continuous initial data of the form (3.4). Let h(t) = min{t, 1}, and let f (k, t) = a2kh(t) , 1 < a2 ≤ 1 + b−1 , or alternatively f (k, t) = [(k − 1)!]2h(t) /b2(k−1) . In either case, a solution ψ dissipates according to the inequality

ψ(t) 2 ≤ b + 1 + e−4t ψ0 2 −1/2 , f H

(3.5)

2

t ≥ 0, √

and is real-entire for t > 0. In particular, the ball of radius b in Hf centered at the uniform state ψu absorbs all trajectories in finite time. Proof. Multiplying (3.3) by f (k, t)yk /k and summing over k = 1, 2, 3, . . . , we obtain the following a priori estimate. The computations are formal, and can be made rigorous by considering Galerkin approximations (see [3]). ∞ ∞ ∞ X d X f (k, t) 2 1 X f 0 (k, t) 2 yk − yk + 4 kf (k, t)yk2 2dt k=1 k 2 k=1 k k=1

= f (1)by12 + by1

∞ X

(f (k + 1) − f (k))yk yk+1

k=1



f (1)by12

v v uX uX u∞ u ∞ f (k + 1) 2 2 + b|y1 |t kf (k + 1)yk+1 t yk . k k=1 k=1

For f (k, t) = a2kh(t) , 1 < a2 ≤ 1 + b−1 , we have f (k + 1) − f (k) = (a2h(t) − 1)f (k), and

d ψ 2 + 2 ψ 2 ≤ b + 1. f f 2dt

For

" f (k, t) =

(k − 1)!h(t) bk−1

#2 ,

P. C ONSTANTIN , E.S. T ITI & J. V UKADINOVIC

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one has b2 f (k + 1) = k2h(t) f (k) ≤ k2 f (k), and therefore

d ψ 2 + 2 ψ 2 ≤ b. f f

2dt



In both cases, (3.5) follows.

Remark 3.2. Observe that from yk2 ≤ 1, k = 1, 2, . . . , the dissipativity follows in Hf for any f for which f (k) ≤ [(k − 1)!/bk−1 ]2 ,

k = k0 , k0 + 1, . . . ,

for some k0 ∈ Z. In particular, this is true for f (k) = a2k for any a > 1. Moreover, the dissipativity in Gevrey classes implies the dissipativity of the solution and all its derivatives in L∞ :

n





∂ ψ(t) 2 2 ≤ M 2 b + e−4t ψ0 2 1/2 , n L H φ

In particular

t > 0.

p

sup k∂φn ψkL∞ ≤ Mn b,

ψ∈A

and

lim inf k∂φn S(t)ψ0 − ∂φn ψkL∞ = 0.

t→∞ ψ∈A

The Fourier coefficients of the elements of the global attractor A decay according to:  #  " 2



yk ≤ min 1, bk(1 + b 

−1 −k

)

bk−1 , bk (k − 1)!

2



.

Remark 3.3. The quotient zk = yk /y1 satisfies the following ODE: zk0 + 4(k2 − 1)zk = bky1 (zk−1 − zk+1 ) − bzk (1 − y2 ),

k = 2, 3, 4, . . . ,

and therefore d (z2 ) + 4(k2 − 1)zk2 = bky1 (zk−1 zk − zk zk+1 ) − bzk2 (1 − y2 ), 2dt k k = 2, 3, 4, . . . .

As before, for the same choice of f as in Theorem 3.1, multiplying by f (k)zk /k and summing over k = 2, 3, . . . gives the following inequality: ∞ ∞ X d X f (k) 2 kf (k)zk2 ≤ b|y2 |. zk + 2 2dt k=2 k k=2

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In particular, |ψ(t)|2f /|V (t, 0)|2 is dissipated in time, until eventually 2

|ψ(t)|f ≤ √ |V (0, t)|, b

t ≥ T.

for some T . In [4] the authors proved the existence of one determining mode. Here we improve the result leading to the convergence in stronger norms. Theorem 3.4. Let ψ(j) (φ, t), j = 1, 2, be two solutions of (3.3) corresponding to nonnegative continuous initial data (j)

ψ0 (φ) =

∞ 1 1 X (j) + y (0) cos(2kφ) 2π π k=1 k

respectively. Let V (j) (φ, t) be the corresponding potential to the solution ψ(j) (φ, t). Assume that lim |V (1) (0, t) − V (2) (0, t)| = 0, t→∞

i.e.,

lim |y1(1) (t) − y1(2) (t)| = 0.

t→∞

Then for f (k) = a2k , 1 < a2 ≤ 1 + b−1 lim |ψ(1) (t) − ψ(2) (t)|f = 0,

t→∞

and for every n = 0, 1, 2, . . . lim k∂φn ψ(1) (t) − ∂φn ψ(2) (t)kL∞ = 0.

t→∞

Proof. Let ψ = ψ(1) −ψ(2) and ψ¯ = 12 (ψ(1) +ψ(2) ). The Fourier coefficients are defined accordingly by yk = yk(1) − yk(2) , and y¯ k = 12 (yk(1) + yk(2) ), k = 0, 1, 2, . . . . The equation for the difference in terms of the Fourier coefficients reads (3.6)

y0 = 0,

¯ 1 (yk−1 − yk+1 ) yk0 + 4k2 yk = bky ¯ k−1 − y¯ k+1 ), + bky1 (y

k = 1, 2, . . . .

Multiplying (3.6) by f (k)yk /k and summing over k = 1, 2, . . . , we obtain ∞ X

d ψ 2 + 4 ψ 2 = by ¯ (f (k + 1) − f (k))yk yk+1 1 f f 2dt k=1

+ by1

∞ X k=1

¯ k−1 − y¯ k+1 )yk . f (k)(y

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P. C ONSTANTIN , E.S. T ITI & J. V UKADINOVIC

Similarly as before, and using a Schwartz inequality we obtain v uX

2 2 u ∞ f (k) d ψ + 3 ψ ≤ b|y1 | kψkf t ¯ k−1 − y¯ k+1 )2 . (y f f 2dt k k=1

Using Young’s inequality, 

d ψ 2 + ψ 2 ≤ 16b2 y 2 1 + ψ(1) 2 + ψ(2) 2 . 1 f f f f dt

There exists T > 0 so that for t ≥ T



d ψ(t) 2 + ψ(t) 2 ≤ 16b2 y 2 (1 + 2b). 1 f f dt

Therefore y1 (t) = −2V (0, t)/b → 0 when t → ∞ will imply lim |ψ(t)|f = 0 and

t→∞

lim k∂φn ψ(t)kL∞ = 0.

t→∞



This completes the proof.

The following theorem shows that there is a finite number of determining nodes for the 2D Smoluchowski equation. Theorem 3.5. There exists n = n(b), so that for any n equidistant points φ0
2π 2 , 2 4d 2

we obtain d 2dt

Z φi +d φi

|ψ|2 + 2π 2

Z φi +d φi

|ψ|2

Z 2π  φi +d  φ +d d 1 2 ¯ 1 sin(2φ)ψ2 φ ≤ ψφ ψ φii + by + )| + π |ψ|2 . |ψ(φ i i 2d 2 0

Summing the above equations for i = 0, 1, 2, . . . , n − 1, we obtain Z 2π Z n−1 n X d 2π 2 2 |ψ| + 2π |ψ|2 ≤ |ψ(φi )|2 . dt 0 2π i=0 0

P. C ONSTANTIN , E.S. T ITI & J. V UKADINOVIC

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lim kψ(1) (t) − ψ(2) (t)kL2 = 0.

t→∞



In particular y1 → 0, and the theorem follows. 4. T HE 3D C ASE

When n = 3, the local coordinates on S 2 are φ = (θ, ϕ), and one has x1 (θ, ϕ) = sin θ cos ϕ, x2 (θ, ϕ) = sin θ sin ϕ, and x2 (θ, ϕ) = cos θ . Also, g 11 = 1, g 22 = √ sin−2 θ , g 12 = g 21 = 0, and g = sin θ . In terms of the local coordinates, 



1 1 ∂2 ψ , ∂ (sin θ∂θ ψ) + sin θ θ sin2 θ ϕ 1 1 B(ψ) = ∂ϕ ((∂ϕ V )ψ), ∂ (sin θ(∂θ V )ψ) + sin θ θ sin2 θ Aψ = −∆g ψ = −

and V (ϕ, θ, t) =

Z π Z 2π 0

0

1 3

˜ 2 ψ(ϕ, ˜ t) dϕ ˜ ˜ cos θ cos θ) ˜ θ, ˜ dθ− (sin θ sin θ˜ cos(ϕ− ϕ)+ .

In the following section, we will use the expansion of solutions in spherical harmonics in order to prove the regularity and dissipativity of solutions in certain Gevrey classes. 4.1. Spherical harmonics. Let Pk denote the Legendre polynomial of degree k. For k = 0, 1, 2, . . . and j = 0, ±1, ±2, . . . , ±k let us define j

j

j

Yk (θ, ϕ) = Ck eijϕ Pk (cos θ),

where " j

Ck =

2k + 1 (k − |j|)! 4π (k + |j|)!

j

Pk (x) = (1 − x 2 )j/2

dj Pk (x), dx j

#1/2 ,

j = 0, 1, 2, . . . , k,

and j

−j

Pk = Pk ,

j = −1, −2, . . . , −k.

The following are well known facts about the operator A = −∆g (see [13]): (1) Each Ykj is an eigenvector of A corresponding to the eigenvalue λk = k2 + k: j

j

AYk = λk Yk .

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(2) The set {Ykj | k = 0, 1, 2, . . . ; j = 0, ±1, ±2, . . . , ±k} forms an orthonormal basis in L2 (S 2 ); in particular, for each ψ ∈ L2 (S 2 ) there is a representation ψ=

∞ X k X

j

j

where ψkj =

ψk Yk ,

Z

k=0 j=−k

−j

S2

ψYk σ (dφ).

Observe that ψ is a real-valued function if and only if ψk−j = ψ¯ kj , and ψ is an even function in variable ϕ, if and only if ψk−j = ψkj . For the simplicity of notation, let us also denote Ykj = 0 and ψkj = 0 for |j| > k. (3) For each k = 0, 1, 2, . . . , we have the point-wise identity k X

(4.1)

j

|Yk (θ, ϕ)|2 =

j=−k

Z

(4) If (a) (b) (c) (d) (e)

j

S2

2k + 1 . 4π

−β

Ynm Yk Yα 6= 0, then all of the following must hold:

β = m + j, α ≤ n + k, k ≤ n + α, n ≤ α + k, α + n + k is even.

4.2. Gevrey regularity. Let (ψ, V ) be a solution of (2.3) for n = 3. Let P∞ Pk j j ψ = k=0 j=−k ψk Yk be the expansion of ψ in spherical harmonics. The normalization yields 1 ψ00 = √ 4π and j |ψk |

(4.2)

Z ≤

s −j ψ|Yk | σ (dφ) 2 S



2k + 1 . 4π

Since V is an eigenvector corresponding to the eigenvalue λ2 = 6, 2 X

V =

V m Y2m ,

m=−2

Z

where V m =

S2

V Y2−m σ (dφ). Also Z

(4.3)

m

|V | ≤ b

S2

p |Y2−m | σ (dφ) ≤ b 20π .

P. C ONSTANTIN , E.S. T ITI & J. V UKADINOVIC

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Observe also that the equation (2.3) for n = 3 preserves the evenness in ϕ. We will only consider solutions with this symmetry, i.e., solutions for which ψk−j = j ψk , and V −j = V j . Lemma 4.1. Let F = f (A) = f (−∆g ) and G = g(A) = g(−∆g ) be two spectral operators defined by Fψ =

∞ X

f (λk )

k=0

Gψ =

∞ X

k X

j

j

j

j

ψk Yk ,

j=−k

g(λk )

k=0

k X

ψk Yk ,

j=−k

where f and g are positive functions defined on the set of eigenvalues of A. Then for ψ ∈ D(F ) ∩ D(G) Z S2

V F ψGψ σ (dφ) = 2 ∞ X k X X

=

−(m+j)

j

f (λk )g(λk )V m ψk ψk +

−(m+j)

j

S2

m=−2 k=0 j=−k

2 ∞ X k X X

Z

Y2m Yk Yk

σ (dφ)

[f (λk )g(λk+2 ) + f (λk+2 )g(λk )]

m=−2 k=0 j=−k −(m+j)

j

× V m ψk ψk+2

Z

j

S2

−(m+j)

Y2m Yk Yk+2

σ (dφ).

Proof. Since Z S2

V F ψGψ σ (dφ) = =

2 ∞ X k α ∞ X X X X

j

m=−2 k=0 j=−k α=0 β=−α

and since

Z

j

S2

−β

V m f (λk )ψk g(λα )ψα

Z

j

S2

−β

Y2m Yk Yα σ (dφ),

−β

Y2m Yk Yα σ (dφ) 6= 0

implies β = m + j , and α = k + 2, or k = α + 2, or α = k, we have

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963

Z S2

=

V F ψGψ σ (dφ) = 2 ∞ X k X X

V

m

j −(m+j) f (λk )ψk g(λk )ψk

Z

m=−2 k=0 j=−k

+

2 ∞ X k X X

V

m

Y2m Yk Yk

j −(m+j) f (λk )ψk g(λk+2 )ψk+2

Z

+

V

m

β−m

σ (dφ)

−β

Y2m Yα+2 Yα σ (dφ).

S2

m=−2 α=0 β=−α

−(m+j)

j

Z

β−m −β f (λα+2 )ψα+2 g(λα )ψα

σ (dφ)

Y2m Yk Yk+2

S2

m=−2 k=0 j=−k

2 ∞ α X X X

−(m+j)

j

S2

Since we assume that V −m = V m , and ψk−j = ψkj , 2 ∞ α X X X

−β

β−m

V m f (λα+2 )ψα+2 g(λα )ψα

m=−2 α=0 β=−α

=

2 ∞ α X X X

Z

−β

β+m

V −m f (λα+2 )ψα+2 g(λα )ψα

2 ∞ α X X X

−(β+m)

V m f (λα+2 )ψα+2

Z

β+m

S2

m=−2 α=0 β=−α

=

−β

β−m

Y2m Yα+2 Yα σ (dφ) =

S2

β

g(λα )ψα

m=−2 α=0 β=−α

−β

Y2−m Yα+2 Yα σ (dφ)

Z

−(β+m)

S2

Y2m Yα+2

β

Yα σ (dφ),



and the proof follows.

The following lemma establishes important estimates regarding the nonlinear term, and it will be used to prove the Gevrey regularity and dissipativity of solutions that are even in the ϕ variable. Lemma 4.2. Let f (λk ) = a2k for a ≥ 1, and Fψ =

∞ X

f (λk )

k=0

k X

j

j

ψk Yk .

j=−k

There exists C > 0, independent of a and b, and Cb > 0 depending on b only, such P P j 2 2 2k k that for any ψ even in ϕ, for which ∞ k=1 k a j=−k |ψk | < ∞, we have 

(4.4) |(B(ψ, V ), F ψ)g | ≤ Ca4 b 1 +

∞ X k=1

ka2k

k X

j

|ψk |2



j=−k

+ C(a4 − 1)b

∞ X k=0

k2 a2k

k X j=−k

j

|ψk |2 ,

P. C ONSTANTIN , E.S. T ITI & J. V UKADINOVIC

964

and if 1 ≤ a4 ≤ 1 + (4Cb)−1 , then also |(B(ψ, V ), F ψ)g | ≤ Cb +

1 (Aψ, F ψ). 2

Proof. Due to Lemma 2.2, 1 (B(ψ, V ), F ψ)g = 2

Z S2

V (F ψAψ − ψAF ψ − 6ψF ψ) σ (dφ).

Therefore, by Lemma 4.1 and the fact that λk+2 − λk = 4k + 6, (B(ψ, V ), F ψ)g = 2 ∞ X k X X

= −3

f (λk )V

m

j −(m+j) ψk ψk

Z

m=−2 k=0 j=−k

−3

2 ∞ X k X X

Y2m Yk Yk

−(m+j)

j

Z ×

−(m+j)

j

S2

Y2m Yk Yk+2

σ (dφ)

2 ∞ X k X 1 X j −(m+j) (λ − λk )(f (λk+2 ) − f (λk ))V m ψk ψk+2 2 m=−2 k=0 j=−k k+2

Z

× = −3

σ (dφ)

(f (λk ) + f (λk+2 ))V m ψk ψk+2

m=−2 k=0 j=−k



−(m+j)

j

S2

2 ∞ X k X X

j

−(m+j)

−6

f (λk+2 )V

m

Y2m Yk Yk

j −(m+j) ψk ψk+2

m=−2 k=0 j=−k

−2

2 ∞ X k X X

−(m+j)

j

S2

m=−2 k=0 j=−k

2 ∞ X k X X

Y2m Yk Yk+2

Z

f (λk )V m ψk ψk

−(m+j)

j

S2

Z

j

S2

σ (dφ)

σ (dφ)

−(m+j)

Y2m Yk Yk+2

σ (dφ)

−(m+j)

j

k(f (λk+2 ) − f (λk ))V m ψk ψk+2

m=−2 k=0 j=−k

Z ×

j

S2

−(m+j)

Y2m Yk Yk+2

σ (dφ) =

Dissipativity and Gevrey Regularity of a Smoluchowski Equation =−

965

2 3a4 X V m ψ2−m 2π m=−2

−3

2 ∞ X k X X

j

Z

m+j

a2k V m ψk ψk

m=−2 k=1 j=−k

−6

2 ∞ X k X X

2k+4

a

V

m

j

S2

j −(m+j) ψk ψk+2

Z

2 ∞ X k X X

j

σ (dφ)

−(m+j)

j

S2

m=−2 k=1 j=−k

− 2(a4 − 1)

−(m+j)

Y2m Yk Yk

Y2m Yk Yk+2

σ (dφ)

m+j

ka2k V m ψk ψk+2

m=−2 k=1 j=−k

Z ×

−(m+j)

j

S2

Y2m Yk Yk+2

σ (dφ).

The following estimates are obtained using (4.2), (4.1), and (4.3). We have Z 2 ∞ X k X X 2k m j m+j −3 a V ψk ψk m=−2 k=1 j=−k

≤ 15b

2 ∞ X k X X

2k

a

j −(m+j) Y2 Yk Yk 2 S m

j m+j |ψk ψk |

Z

≤ 15b

∞ X

k X

(2k + 1)a2k

k=0

j

S2

m=−2 k=1 j=−k

σ (dφ) −(m+j)

|Yk Yk

j

|ψk |2 ≤ 60b

∞ X

ka2k

k=0

j=−k

| σ (dφ)

k X

j

|ψk |2 ,

j=−k

and Z 2 ∞ X k X X 2k+4 m j −(m+j) −6 a V ψ ψ k k+2

S2

m=−2 k=1 j=−k

≤ 30b

2 ∞ X k X X

j

m+j

a2k+4 |ψk ψk+2 |

m=−2 k=1 j=−k

≤ 60b

∞ X

k X

(k + 2)a2k+4

k=1

≤ 60b(3a4 + 1)

j

j

|ψk |2 +

k=1

ka2k

k X j=−k

Z

j

S2

j

|ψk |2 ,

−(m+j)

|Yk Yk+2

∞ X k=1

j=−k ∞ X

−(m+j)

Y2m Yk Yk+2

σ (dφ)

| σ (dφ)

(k + 2)a2k+4

k X j=−k

j

|ψk+2 |2



P. C ONSTANTIN , E.S. T ITI & J. V UKADINOVIC

966 and also

Z 2 ∞ X k X X 2k m j m+j − 2(a4 − 1) ka V ψk ψk+2 m=−2 k=1 j=−k

4

≤ 10b(a − 1)

2 ∞ X k X X

2k

ka



j −(m+j) Y2 Yk Yk+2 σ (dφ) 2 S m

j m+j |ψk ψk+2 |

Z

m=−2 k=1 j=−k

−(m+j)

j

S2

|Yk Yk+2



| σ (dφ)

∞ ∞ k k X  X X X j j ≤ 20b(a4 − 1) k(k+ 2)a2k |ψk |2 + k(k+ 2)a2k |ψk+2 |2 k=1

k=0

j=−k

j=−k

k ∞ ∞ k  X  X X 1 X j j ≤ 20b(a4 −1) 3 k2 a2k |ψk |2 + 4 (k+2)2 a2k+4 |ψk+2 |2 a k=0 k=1 j=−k j=−k

≤ 80b(a4 − 1)

∞ X

k2 a2k

k=1

k X

j

|ψk |2 .

j=−k

The estimate (4.4) follows. For any a, which satisfies 1 ≤ a4 ≤ 1 + (4Cb)−1 , and an integer k0 such that 4Ca4 b ≤ k0 < 4Ca4 b + 1, and by virtue of (4.2), one has 1 (Aψ, F ψ)g ≤ 2

≤ Ca4 b + Ca4 b

∞ X k=1

≤ Ca4 b + Ca4 b

∞ X

j

|ψk |2 −

j=−k k X

ka2k

k=1

= Ca4 b + Ca4 b

k X

ka2k

kX 0 −1

k ∞ X 1X j k2 a2k |ψk |2 4 k=1 j=−k

j

|ψk |2 − Ca4 b

j=−k

ka2k

(2k + 1)2

k=1



∞ X

ka2k

k=k0

≤ Cb .

k X

j

|ψk |2

j=−k



|(B(ψ), F ψ)g | −

The next theorem is an application of Lemma 4.2 for the choice of a = 1, and establishes the dissipation of solutions in L2 (S 2 ). Theorem 4.3. Let ψ0 be a nonnegative continuous function on S 2 . Then the unique solution ψ(φ, t) of (2.3) for n = 3 with initial datum ψ0 dissipates in L2 (S 2 ) according to the inequality

ψ(t) 2 2 ≤ C1 b5 + e−t kψ0 kL2 , L

where C1 is a constant independent of b.

t > 0,

Dissipativity and Gevrey Regularity of a Smoluchowski Equation

967

Proof. Applying Lemma 4.2 for a = 1 one obtains d 1 (ψ, ψ)g + (Aψ, ψ)g = (B(ψ), ψ)g ≤ Cb + (Aψ, ψ)g , 2dt 2

thus

d

ψ 2 2 + 1 kψkL2 ≤ Cb . L 2dt 2



One can easily see that Cb = C1 b5 for a constant C1 independent of b, and the theorem follows.

The following theorem establishes the regularity and the dissipativity of solutions in a Gevrey class. The idea of the proof is inspired by the work of [9] and its generalization in [1], [2] and [8]. The proof presented here is formal and can be easily made rigorous by applying the Galerkin procedure. Theorem 4.4. Let ψ0 be a nonnegative continuous function on S 2 , and ψ(φ, t) the unique solution of (2.3) (n = 3) corresponding to that initial datum. Let a be such that 1 < a4 ≤ min{e, 1 + (4Cb)−1 }, and let h(t) = min{t, 1}. Then ∞ X

a2kh(t)

k=1

k X

j

|ψk |2 ≤ 4Cb + e−t/2 kψ0 kL2 ,

t ≥ 0.

j=−k

Proof. Let F (t)ψ(t) =

∞ X

k X

a2kh(t)

k=0

j

j

ψk (t)Yk ,

j=−k

F 0 (t)ψ(t) = 2 ln a h0 (t)

∞ X

ka2kh(t)

k=0

k X

j

j

ψk (t)Yk .

j=−k

Multiplying the equation (2.3) by F (t)ψ and integrating over S 2 one obtains d

2dt

(ψ, F (·)ψ)g −

1 (ψ, F 0 (·)ψ)g + (Aψ, F (·)ψ)g = (B(ψ), F (·)ψ)g , 2

which together with Lemma 4.2 yields ∞ ∞ k k X X d X 2kh(t) X j j a |ψk |2 − ln a h0 (t) ka2kh(t) |ψk |2 2dt k=0 j=−k k=0 j=−k

+

k ∞ X 1X j k2 a2kh(t) |ψk |2 ≤ Cb , 2 k=0 j=−k

968 thus

P. C ONSTANTIN , E.S. T ITI & J. V UKADINOVIC ∞ ∞ k k X d X 2kh(t) X 1X j j a |ψk |2 + k2 a2kh(t) |ψk |2 ≤ Cb , 2dt k=0 4 j=−k k=0 j=−k



and the theorem follows.

Remark 4.5. As in the 2D case, the dissipativity in Gevrey classes implies the dissipativity of ψ and its partial derivatives in L∞ (S 2 ). In particular, the global attractor A exists in this case as well, it is finite-dimensional, and there are constants ˜ M(n, b), depending on n and b only, such that ˜ b), sup k∇ng ψkL∞ ≤ M(n, ψ∈A

and

lim inf k∇ng S(t)ψ0 − ∇ng ψkL∞ = 0.

t→∞ ψ∈A

Remark 4.6. As a result of the Gevrey regularity one can easily prove that the Galerkin scheme, based on the eigenfunctions of the Laplacian (in the 2D case) and the Laplace-Beltrami operator (in the 3D case), converges exponentially fast to the exact solution of the underlying equation (see, e.g., [6] and [11]). Acknowledgments. We would like to thank I.G. Kevrekidis for stimulating and inspiring discussions. The work of P.C. was supported in part by the NSF grant DMS-0202531. The work of E.S.T. was supported in part by the NSF grant DMS-0204794, the MAOF Fellowship of the Israeli Council of Higher Education, and the US Civilian Research and Development Foundation, grant RM1-2343-MO-02.

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P ETER C ONSTANTIN : Department of Mathematics The University of Chicago Chicago, IL 60637, U. S. A. E- MAIL: [email protected] E DRISS S. T ITI : Department of Mathematics and Department of Mechanical and Aerospace Engineering University of California Irvine, CA 92697, U. S. A. Department of Computer Science and Applied Mathematics Weizmann Institute of Science Rehovot 76100, Israel. E- MAIL: [email protected]., [email protected] J ESENKO V UKADINOVIC : Department of Mathematics University of Wisconsin Madison, WI 53705, U. S. A. E- MAIL: [email protected] K EY WORDS AND PHRASES: Smoluchowski equations, dissipativity, Maier-Saupe potential, nonlinear Fokker-Planck equations. 2000 M ATHEMATICS S UBJECT C LASSIFICATION: 35Kxx, 70Kxx Received : May 13th, 2004.