Divergent targets of glycolysis and oxidative phosphorylation result in additive effects of metformin and starvation in colon and breast cancer
*Cecilia Marini1, *Giovanna Bianchi2, Ambra Buschiazzo3, Silvia Ravera4; Roberto Martella2; Gianluca Bottoni3; Andrea Petretto5; Laura Emionite6; Elena Monteverde3; Selene Capitanio3, Elvira Inglese5; Marina Fabbi7; Francesca Bongioanni3; Lucia Garaboldi3; Paolo Bruzzi8, Anna Maria Orengo3; Lizzia Raffaghello2; Gianmario Sambuceti3.
1
CNR Institute of Molecular Bioimaging and Physiology (IBFM), Milan, Section of Genoa, Genoa, Italy
2
Oncology lab, Istituto Giannina Gaslini, Genoa, Italy
3
Nuclear Medicine, Department of Health Sciences, University of Genoa and IRCCS AOU San Martino-IST,
Genoa, Italy 4
Biochemistry Lab, Department of Pharmacy, University of Genoa, Genoa, Italy
5
Core facility, Istituto Giannina Gaslini, Genoa, Italy
6
Animal facility, IRCCS AOU San Martino-IST, Genoa, Italy
7
Integrated oncological therapies, IRCCS AOU San Martino-IST, Genoa, Italy
8
Statistics and Epidemiology Unit, IRCCS AOU San Martino-IST, Genoa, Italy
Keywords: cancer metabolism, metformin, starvation, glycolysis, oxidative phosphorylation. The authors have no potential conflicts of interest to disclose. * Both CM and GB acted as first author. Address for correspondence: Cecilia Marini, MD, PhD, C/o Nuclear Medicine IRCCS AOU San Martino-IST, 160143- Genoa, Italy
Email:
[email protected]
Suppl. Table 1: Body weight in grams and serum glucose level in each study group at the two different scan times Weight (grams) PET 1 PET 2
CTR
STS
MTF
MTF + STS
Serum glucose (mmol/L) PET 1 PET 2
CT26 (n=7)
18,60 ± 1,48
17,71 ± 1,23
4,26 ± 1,22
3,50 ± 2,59
4T1 (n=7)
16,17 ± 0,75
17,55 ± 0,56
4,71 ± 0,74
4,74 ± 0,88
CT26 (n=7)
16,20 ± 0,47
15,40 ± 1,94
3,58 ± 0,87
3,13 ± 1,00
4T1 (n=7)
13,45 ± 0,27
14,34 ± 0,58
4,19 ± 1,18
4,80 ± 2,55
CT26 (n=7)
15,91 ± 0,61
17,31 ± 1,05
4,24 ± 1,42
3,50 ± 1,21
4T1 (n=7)
16,36 ± 0,78
17,66 ± 0,78
4,40 ± 1,20
5,14 ± 1,48
CT26 (n=7)
13,08 ± 0.76
*
14,75 ± 0.94
4T1 (n=7)
13,74 ± 0.36
*
13,45 ± 0.59
*=p
