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In general, the number of degrees of freedom associated with a finite element is equal to the product of the number of nodes and the number of values of the ...
The Finite Element Analysis (FEA) is a numerical method for solving problems of
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and buckling of a car structure during first 50 to 100 ms of a crash test. ⢠Solutions .... safer cars and trucks in less time without a .... ac oss eee e bou da es ...
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Sep 13, 2018 - Figure 1.2.3: Simple fixed-free bar with distributed load. The force displacement relation is given by: EA d2u. d x2 +f (x)=0. Subject to the ...
Jun 11, 2014 - Once more e can be turned into an immer product on a ... Vu e H, -p(u, v) = | fu ..... Babuška, Ivo; Banerjee, Uday; Osborn, John E. (June 2004).
approach and thus, the finite element approach, to automotive crash simulations to a ... Vectorization of the software (PAMCRASH and CRASHMAS. ( for ESI and IABG, ...... This element is free of hourglass modes and has a bending response ...
a finite element analysis. Felix Eckstein ~, Beat Merz 2 , Peter Schmid 2 , Reinhard Putz ~ ..... 1992). Investigations with the finite element method by Hayes et al.
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Virtual Displacements, and an Introduction to the Finite Element Solution, 124 ... 6.3. l Linearization of the Principle
Modeling and analysis of composite slabs using the finite element (FE) method ...
In the following sections, composite slab analysis using the FE method is first.
This chapter introduces fundamental finite element principles. The basic theory ...
in section 2.4 the finite element method in an abstract setting. In particular, we ...
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PED – 118
*PED118*
Second Semester M.E. (Civil) Degree Examination, January 2015 2K8 SE 201 : FINITE ELEMENT METHOD (Common to Structural Engineering/PSC/Earth Quake) Time : 3 Hours
Max. Marks : 100
Note : Answer any five full question. Assume missing data suitably and numerical. 1. a) Derive the general expression for the stiffness of an element based on the principle of virtual displacement.[K] =
∫∫∫ [B ] [D][B ]dv T
.
10
b) Enumerate the convergence requirements for the selection of a displacement function element analysis with example. 10 2. For the plane truss consisting of three elements as shown in Fig.1, determine the displacements at node 1 and the stress in each element using finite element 20 approach, take E = 2.20 x 105 N/mm2 and A = 1250 mm2 for all members.
Fig.1 3. a) Derive the shape function for linear strain triangle element using natural co-ordinate system. b) Using serendipity concept find the shape function for quadratic serendipity family element.
10 10
4. Constant strain triangles in a finite element model the nodal coordinates are given as, i(15.00, - 8.00), j(10.00, 5.00) and k (2.00, 0.00), respectively. The element is 2 mm thick and is of a material with properties E = 70 Gpa, and μ = 0.30. Upon loading of the model the deflections of given element were found to be Ui = 100 μm ,Uj = – 50 μm ,Uk = 75 μm ,Vi = – 40 μm , Vj = 80 μm , Vk = – 45 μ m. P.T.O.
PED – 118
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*PED118*
Determine : a) The element stiffeness matrix, b) Nodal force vector, and the stresses in the element. 5. a) Derive the stiffness matrix for a constant strain triangle CST element by direct approach. b) A set of springs connected together as shown in Fig (2). Determine the displacements at node 1, 2 and 4.
20 10 10
Fig. 2 6. a) Obtain the strain displacement matrix for Linear strain triangle LST element. 10 b) By degrading technique develop shape function for seven nodded rectangular element from eight nodded rectangular element. 10 7. a) Obtain the Jacobian matrix for quadrilateral element.
10
b) The element shown in Fig (3) assemble the Jacobian and strain displacement matrix for the Gaussian point. (0.57735, 0.57735) 10
Fig. 3
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8. Explain the following terms. a) Stress due to lack of fit b) Uniqueness of mapping of isoparametric elements c) Jacobian matrix and d) Axi-symetric element.