f(x) changes in x for PDF post [PDF]

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y = mx + b = f(x) x f(x). 10. 0. 10. -10. -10. 3. 2. 4. 5. 6. Page 2. y y x x x f(x) = x + 2 f(x) = x + 2 f(x) = x + 2 y = 2 + 2 x = 2 y = 1 + 2 x = 1 x = 0 y = 0 + 2 f(2) = 4 f(1) = 3.
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y

-10

x

-10 3

x = real number y=x+2 5

y

f(x) = x + 2 ( 7, 9)

0

10

10 Paula Beardell Krieg 2015

x

y = mx + b = f(x) 2

x=7 y = 7+ 2 6

y

f(x) = x + 2 f(7)= 9 ( 6, 8)

x

x=6 y=6+2

f(x) = x + 2 f(6)= 8

f(x)

x

x=3 y=3+2

10

y ( 2, 4)

x

f(x) = x + 2 f(3) = 5

x ( 3, 5) 9

x=2 y=2+2

x=4 y=4+2

11

y

( 1, 3)

x

y

f(x) = x + 2 f(4) = 6

x 8

x=1 y=1+2

x=5 y=5+2

12

x

y

( 4, 6) f(x) = x + 2 f(5) = 7

x 7

f(x) = x + 2 f(2) = 4

x=0 y=0+2

y

f(x) = x + 2 f(1) = 3

( 0, 2)

f(x) = x + 2 f(0) = 2

y

( 5, 7)

x = -3 y = -3 + 2

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y

x

(-4, -2)

15

x = -2 y = -2 + 2

17

x

y

f(x) = x + 2 f(-2) = 0

( -2, 0)

x 14

x = -1 y = -1 + 2

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13

y

f(x) = x + 2 f(-4) = -2

( -5, -3)

x = -5 y = -5 + 2

x

x

f(x) = x + 2 f(-3) = -1 ( -3, -1)

x

x = -4 y = -4 + 2

y

f(x) = x + 2 f(-5) = -3

( -6, -4)

x = -6 y = -6 + 2

f(x) = x + 2 f(-6) = -4

y

f(x) = x + 2 f(-1) = 1

(-1, 1) y

x = real number y = -3x − 3

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y (-4, 9)

x

f(x) = -3x − 3

x 21

x = -4 y = -3(-4)− 3

x = -8 y = -8 + 2

23

y

f(x) = -3x − 3 f(-4) = 9

(-3, 6)

y

f(x) = x + 2 f(-8) = -6

( -8, -6) x

x 20

x = -3 y = -3(-3)− 3

x = -7 y = -7 + 2

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y

(-7, -5)

x

x 19

y

f(x) = -3x − 3 f(-3) = 6

(-2, 3)

x = -2 y = -3(-2)− 3

f(x) = -3x − 3 f(-2) = 3

y

f(x) = x + 2 f(-7) = -5

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x=1 y=3

y

x

x

x = -1 y = -3(-1)− 3

30

(1, 3)

26

x=1 y=3

(-1, 0)

y

x

x

f(1) = 3 (f(1), 3)

y

f(x) = -3x − 3 f(-1) = 0

(0, -3)

x=0 y = -3(0)− 3

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(1, 3)

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x=2 y = -3(2)− 3

y

f(x) = -3x − 3 f(2) = -3 (2, -3)

y

f(x) = -3x − 3 f(0) = -3

x

x

(1, -6) x=1 y = -3(1)− 3

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y

f(x) = -3x − 3 f(1) = -6

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x

x=1 y=3

y (1, 3)

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y (1, 3)

x

x=1 y=3

(1, 1+2) (f(1), 3)

f(x) = x + 2 f(1) = 3

(1, 1+2) (f(1), 3)

f(x) = x + 2 f(1) = 3

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The form f(x) = y tells us that there is a function, somewhere, with an x and y.

If you see f(x) = y with values speci�ied, such as f(2) = 3, it is implied that this point (2, 3) belongs to a function, although you may or may not know what that function is. When you are given just the coordinates of point such as (2,3) you can mark this point on a graph but, without any other information, it’s just a point without a function.