Advances in Mathematical and Computational Methods
Introduction to the General operation of Matrices CLAUDE ZIAD BAYEH1, 2 1
Faculty of Engineering II, Lebanese University 2 EGRDI transaction on mathematics (2004) LEBANON Email:
[email protected]
NIKOS E.MASTORAKIS WSEAS (Research and Development Department) http://www.worldses.org/research/index.html Agiou Ioannou Theologou 17-2315773, Zografou, Athens,GREECE
[email protected] Abstract: - The General operation of Matrices is an original study introduced by the author in the mathematical domain. The basic idea of the General operation of Matrices is similar to the traditional operation of matrices, but moreover the General operation of Matrices is more general and contains many forms and ways of multiplying, adding, subtracting and dividing many matrices. The main goal of introducing the General operation of Matrices is to facilitate the writing of many complicated equations in simple matrices. In this paper a brief study is introduced with the definition of the General operation of Matrices and simple applications are developed in order to give idea about the importance of this new concept of operation between Matrices. Many studies will follow this one in order to find more applications in mathematics and all scientific domains. Key-words:- General operation of Matrices, Matrix, Addition, Multiplication, Subtracting, Dividing, Relation between matrices.
applications in most scientific fields. In physics, matrices are used to study electrical circuits, optics, and quantum mechanics [10-11]. In this paper, the author introduced the General operation of Matrices which is the general case of the traditional operation between matrices. The concept of manipulating the General operation of Matrices is different from the traditional operation between matrices. The general operation of matrices is introduced in order to facilitate the writing of many complicated expressions into matrices and to facilitate the operation between matrices as we want. We can operate the Columns of the first matrix by the columns of the second matrix, or the columns of the first matrix by the Lines (rows) of the second matrix, or Lines of the first matrix by the line of the second matrix, or Lines of the first matrix by the columns of the second matrix. This is not the case of the traditional operation between matrices. Mainly we have two operations between matrices, the first operation is between the elements of the two matrices and the second is the operation between the operated elements. For example: (ππ (ππππ1 )ππ) is the first operation between two elements of the two matrices, with (ππππ1 ) can be replaced by an operator (+, -, *, /), the second operator (ππππ2 ) is the operator
1 Introduction In mathematics, a matrix (plural matrices) is a rectangular array of numbers, symbols, or expressions [1-2]. The individual items in a matrix are called its elements or entries. An example of a matrix with six elements is 1 4 β2 οΏ½ οΏ½ 9 8 4 Matrices of the same size can be added or subtracted element by element [3-4]. The rule for matrix multiplication is more complicated, and two matrices can be multiplied only when the number of columns in the first equals the number of rows in the second [5-7]. A major application of matrices is to represent linear transformations, that is, generalizations of linear functions such as f(x) = 4x. For example, the rotation of vectors in three dimensional space is a linear transformation [8-9]. The product of two matrices is a matrix that represents the composition of two linear transformations. Another application of matrices is in the solution of a system of linear equations. If the matrix is square, it is possible to deduce some of its properties by computing its determinant. For example, a square matrix has an inverse if and only if its determinant is not zero. Eigenvalues and eigenvectors provide insight into the geometry of linear transformations. Matrices find
ISBN: 978-1-61804-117-3
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between the operated elements such as (ππ ππππ1 ππ)ππππ2 (ππ ππππ1 ππ). With (ππππ2 ) can be replaced by an operator (+, -, *, /). Many studies will follow this paper in order to find other applications in many domains as in science, engineering and mathematics. In the second section, a definition of the general operation of matrices is presented. in the section 3, practical examples of the General operation of matrices are presented. and finally, a conclusion is presented in the section 4.
πΆπΆπΆπΆ πΆπΆπΆπΆ ππ ππ ππ ππ οΏ½ οΏ½ππππ1 οΏ½ οΏ½ οΏ½ β’ π΄π΄ οΏ½ππππ1 οΏ½ π΅π΅ = οΏ½ ππ β ππ ππ ππππ ππππ2 2 = (ππ ππππ1 ππ)ππππ2 (ππ ππππ1 ππ) (ππ ππππ1 ππ)ππππ2 (ππ ππππ1 ππ) οΏ½ οΏ½ (ππ ππππ1 ππ)ππππ2 (ππ ππππ1 β) (ππ ππππ1 ππ)ππππ2 (ππ ππππ1 β)
2 Definition of the General operation of matrices
πΏπΏπΏπΏ πΏπΏπΏπΏ ππ ππ ππ ππ ππππ οΏ½ οΏ½ 1οΏ½ οΏ½ οΏ½ β’ π΄π΄ οΏ½ππππ1 οΏ½ π΅π΅ = οΏ½ ππ β ππ ππ ππππ ππππ2 2 (ππ ππππ1 ππ)ππππ2 (ππ ππππ1 ππ) (ππ ππππ1 ππ)ππππ2 (ππ ππππ1 β) οΏ½ =οΏ½ (ππ ππππ1 ππ)ππππ2 (ππ ππππ1 ππ) (ππ ππππ1 ππ)ππππ2 (ππ ππππ1 β)
πΏπΏπΏπΏ πΏπΏπΏπΏ ππ ππ ππ ππ ππππ οΏ½ οΏ½ 1οΏ½ οΏ½ οΏ½ β’ π΄π΄ οΏ½ππππ1 οΏ½ π΅π΅ = οΏ½ ππ β ππ ππ ππππ ππππ2 2 (ππ ππππ1 ππ)ππππ2 (ππ ππππ1 ππ) (ππ ππππ1 ππ)ππππ2 (ππ ππππ1 β) οΏ½ =οΏ½ (ππ ππππ1 ππ)ππππ2 (ππ ππππ1 ππ) (ππ ππππ1 ππ)ππππ2 (ππ ππππ1 β)
The general operation of matrices is denoted by: ππ1 ππ2 οΏ½ ππππ1 οΏ½ (1) ππππ2
2.1 Examples of the general operation of matrices
With β’ ππ1 ππ2 is the form of operation between two matrices for example it is written as following: -πΆπΆπΆπΆ means the operation between the Columns of the first matrix and the Columns of the second matrix. -πΆπΆπΆπΆ means the operation between the Columns of the first matrix and the Lines of the second matrix. -πΏπΏπΏπΏ means the operation between the Lines of the first matrix and the Lines of the second matrix. -πΏπΏπΏπΏ means the operation between the Lines of the first matrix and the Columns of the second matrix.
In this section, we give some examples in order understand the principle of the general operation matrices and how it works. It is very important understand the basis of operation in order understand the whole operations.
to of to to
Suppose the following matrices: ππ ππ ππ ππ οΏ½ and π΅π΅ = οΏ½ οΏ½ π΄π΄ = οΏ½ ππ β ππ ππ
β’ ππππ1, is the first operation between the elements of the first and second matrices. It can be replaced by (+, β,Γ ππππ Γ·).
β’ ππππ2 , is the secondary operation between the elements of the first and second matrices. It can be replaced by (+, β,Γ ππππ Γ·).
2.1.1 The first operation is β*β and the second is β-β πΆπΆπΆπΆ πΆπΆπΆπΆ ππ ππ ππ ππ οΏ½οΏ½ β οΏ½οΏ½ οΏ½ β’ π΄π΄ οΏ½ β οΏ½ π΅π΅ = οΏ½ ππ β ππ ππ β β (ππ β ππ) β (ππ β ππ) (ππ β ππ) β (ππ β ππ) οΏ½ =οΏ½ (ππ β ππ) β (ππ β β) (ππ β ππ) β (ππ β β)
πΆπΆπΆπΆ πΆπΆπΆπΆ ππ ππ ππ ππ ππππ οΏ½ οΏ½ 1οΏ½ οΏ½ οΏ½ β’ π΄π΄ οΏ½ ππππ1 οΏ½ π΅π΅ = οΏ½ ππ β ππ ππ ππππ2 ππππ2 = (ππ ππππ1 ππ)ππππ2 (ππ ππππ1 ππ) (ππ ππππ1 ππ)ππππ2 (ππ ππππ1 ππ) οΏ½ οΏ½ (ππ ππππ1 ππ)ππππ2 (ππ ππππ1 β) (ππ ππππ1 ππ)ππππ2 (ππ ππππ1 β)
πΏπΏπΏπΏ πΏπΏπΏπΏ ππ ππ ππ ππ οΏ½οΏ½ β οΏ½οΏ½ οΏ½ β’ π΄π΄ οΏ½ β οΏ½ π΅π΅ = οΏ½ ππ β ππ ππ β β (ππ β ππ) β (ππ β ππ) (ππ β ππ) β (ππ β β) οΏ½ =οΏ½ (ππ β ππ) β (ππ β ππ) (ππ β ππ) β (ππ β β)
Examples: Suppose the following matrices: ππ ππ ππ ππ οΏ½ and π΅π΅ = οΏ½ οΏ½ π΄π΄ = οΏ½ ππ β ππ ππ
ISBN: 978-1-61804-117-3
πΆπΆπΆπΆ πΆπΆπΆπΆ ππ ππ ππ ππ οΏ½ οΏ½ οΏ½ β’ π΄π΄ οΏ½ β οΏ½ π΅π΅ = οΏ½ β οΏ½οΏ½ ππ β ππ ππ β β (ππ β ππ) β (ππ β ππ) (ππ β ππ) β (ππ β ππ) οΏ½ =οΏ½ (ππ β ππ) β (ππ β β) (ππ β ππ) β (ππ β β)
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πΏπΏπΏπΏ πΏπΏπΏπΏ ππ ππ ππ ππ οΏ½οΏ½+οΏ½οΏ½ οΏ½ β’ π΄π΄ οΏ½ + οΏ½ π΅π΅ = οΏ½ ππ β ππ ππ / / (ππ + ππ)/(ππ + ππ) (ππ + ππ)/(ππ + β) οΏ½ =οΏ½ (ππ + ππ)/(ππ + ππ) (ππ + ππ)/(ππ + β)
πΏπΏπΏπΏ πΏπΏπΏπΏ ππ ππ ππ ππ οΏ½οΏ½ β οΏ½οΏ½ οΏ½ β’ π΄π΄ οΏ½ β οΏ½ π΅π΅ = οΏ½ ππ β ππ ππ β β (ππ β ππ) β (ππ β ππ) (ππ β ππ) β (ππ β β) οΏ½ =οΏ½ (ππ β ππ) β (ππ β ππ) (ππ β ππ) β (ππ β β)
πΏπΏπΏπΏ πΏπΏπΏπΏ ππ ππ ππ ππ οΏ½οΏ½ + οΏ½οΏ½ οΏ½ β’ π΄π΄ οΏ½ + οΏ½ π΅π΅ = οΏ½ ππ β ππ ππ / / (ππ + ππ)/(ππ + ππ) (ππ + ππ)/(ππ + β) οΏ½ =οΏ½ (ππ + ππ)/(ππ + ππ) (ππ + ππ)/(ππ + β)
2.1.2 The first operation is β*β and the second is β+β πΆπΆπΆπΆ πΆπΆπΆπΆ ππ ππ ππ ππ οΏ½οΏ½ β οΏ½οΏ½ οΏ½ β’ π΄π΄ οΏ½ β οΏ½ π΅π΅ = οΏ½ ππ β ππ ππ + + (ππ β ππ) + (ππ β ππ) (ππ β ππ) + (ππ β ππ) οΏ½ =οΏ½ (ππ β ππ) + (ππ β β) (ππ β ππ) + (ππ β β)
2.1.4 The first operation is β*β and the second is β-β with two rectangular matrices (3 columns and 2 lines) Suppose the following matrices: ππ β ππ ππ ππ ππ οΏ½ and π΅π΅ = οΏ½ οΏ½ π΄π΄ = οΏ½ ππ ππ ππ ππ ππ ππ
πΆπΆπΆπΆ πΆπΆπΆπΆ ππ ππ ππ ππ οΏ½οΏ½ β οΏ½οΏ½ οΏ½ β’ π΄π΄ οΏ½ β οΏ½ π΅π΅ = οΏ½ ππ β ππ ππ + + (ππ β ππ) + (ππ β ππ) (ππ β ππ) + (ππ β ππ) οΏ½ =οΏ½ (ππ β ππ) + (ππ β β) (ππ β ππ) + (ππ β β)
πΆπΆπΆπΆ ππ β’ π΄π΄ οΏ½ β οΏ½ π΅π΅ = οΏ½ ππ β
πΏπΏπΏπΏ πΏπΏπΏπΏ ππ ππ ππ ππ οΏ½οΏ½ β οΏ½οΏ½ οΏ½ β’ π΄π΄ οΏ½ β οΏ½ π΅π΅ = οΏ½ ππ β ππ ππ + + (ππ β ππ) + (ππ β ππ) (ππ β ππ) + (ππ β β) οΏ½ =οΏ½ (ππ β ππ) + (ππ β ππ) (ππ β ππ) + (ππ β β)
πΏπΏπΏπΏ πΏπΏπΏπΏ ππ ππ ππ ππ οΏ½οΏ½ β οΏ½οΏ½ οΏ½ β’ π΄π΄ οΏ½ β οΏ½ π΅π΅ = οΏ½ ππ β ππ ππ + + (ππ β ππ) + (ππ β ππ) (ππ β ππ) + (ππ β β) οΏ½ =οΏ½ (ππ β ππ) + (ππ β ππ) (ππ β ππ) + (ππ β β) This equation is similar to the traditional operation between two matrices which gives the same result as following ππ ππ ππ ππ οΏ½βοΏ½ οΏ½ π΄π΄ β π΅π΅ = οΏ½ ππ β ππ ππ (ππ β ππ) + (ππ β ππ) (ππ β ππ) + (ππ β β) οΏ½ =οΏ½ (ππ β ππ) + (ππ β ππ) (ππ β ππ) + (ππ β β)
ππ πΆπΆπΆπΆ ππ οΏ½οΏ½ β οΏ½οΏ½ ππ ππ β
= (ππ β ππ) β (ππ β ππ) οΏ½(ππ β β) β (ππ β ππ) (ππ β ππ) β (ππ β ππ)
(ππ β ππ) β (ππ β ππ) (ππ β β) β (ππ β ππ) (ππ β ππ) β (ππ β ππ)
πΏπΏπΏπΏ ππ β’ π΄π΄ οΏ½ β οΏ½ π΅π΅ = οΏ½ ππ β
πΏπΏπΏπΏ ππ ππ οΏ½οΏ½ β οΏ½οΏ½ ππ ππ β
β ππ
ππ οΏ½ ππ
(ππ β ππ) β (ππ β ππ) (ππ β β) β (ππ β ππ)οΏ½ (ππ β ππ) β (ππ β ππ)
πΆπΆπΆπΆ ππ ππ ππ πΆπΆπΆπΆ ππ β ππ οΏ½οΏ½ β οΏ½οΏ½ οΏ½ β’ π΄π΄ οΏ½ β οΏ½ π΅π΅ = οΏ½ ππ ππ ππ ππ ππ ππ β β This operation canβt be done because the number of lines in the first matrix must be equal to the number of columns in the second matrix.
(ππ β ππ) β (ππ β β) β (ππ β ππ) =οΏ½ (ππ β ππ) β (ππ β β) β (ππ β ππ)
ππ οΏ½ β
(ππ β ππ) β (ππ β ππ) β (ππ β ππ) οΏ½ (ππ β ππ) β (ππ β ππ) β (ππ β ππ)
πΏπΏπΏπΏ πΏπΏπΏπΏ ππ ππ ππ ππ οΏ½οΏ½ β οΏ½οΏ½ οΏ½ β’ π΄π΄ οΏ½ β οΏ½ π΅π΅ = οΏ½ ππ β ππ ππ β β This operation canβt be done because the number of columns in the first matrix must be equal to the number of lines in the second matrix.
2.1.3 The first operation is β+β and the second is β/β πΆπΆπΆπΆ πΆπΆπΆπΆ ππ ππ ππ ππ οΏ½οΏ½ + οΏ½οΏ½ οΏ½ β’ π΄π΄ οΏ½ + οΏ½ π΅π΅ = οΏ½ ππ β ππ ππ / / (ππ + ππ)/(ππ + ππ) (ππ + ππ)/(ππ + ππ) οΏ½ =οΏ½ (ππ + ππ)/(ππ + β) (ππ + ππ)/(ππ + β)
2.1.5 The first operation is β*β and the second is β-β with two rectangular matrices (2 columns and 3 lines) Suppose the following matrices: ππ ππ ππ β π΄π΄ = οΏ½ ππ ππ οΏ½ and π΅π΅ = οΏ½ ππ ππ οΏ½ ππ ππ ππ ππ
πΆπΆπΆπΆ πΆπΆπΆπΆ ππ ππ + ππ ππ οΏ½οΏ½ οΏ½οΏ½ οΏ½ β’ π΄π΄ οΏ½ + οΏ½ π΅π΅ = οΏ½ ππ β ππ ππ / / (ππ + ππ)/(ππ + ππ) (ππ + ππ)/(ππ + ππ) οΏ½ =οΏ½ (ππ + ππ)/(ππ + β) (ππ + ππ)/(ππ + β)
ISBN: 978-1-61804-117-3
ππ ππ
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ππ πΆπΆπΆπΆ β’ π΄π΄ οΏ½ β οΏ½ π΅π΅ = οΏ½ ππ ππ β
ππ πΆπΆπΆπΆ ππ ππ οΏ½ οΏ½ β οΏ½ οΏ½ ππ ππ β ππ
= (ππ β ππ) β (ππ β ππ) β (ππ β ππ) οΏ½ (ππ β β) β (ππ β ππ) β (ππ β ππ)
πΆπΆπΆπΆ β’ οΏ½ππππ1 οΏ½ π΅π΅ππππ = ππππππ (3) ππππ2 With -ππ is the number of lines for the first matrix and it is equal to the number of columns for the second matrix. The number of lines for the first matrix must be equal to the number of columns in the second matrix when the operation between the two matrices is πΆπΆπΆπΆ columns of the first matrix by the lines of the second matrix. - ππ is the number of columns for the first matrix π΄π΄. -ππ is the number of columns for the second matrix π΅π΅. The result matrix has the number of lines equal to ππ and the number of columns equal to ππ. ππ π΄π΄ππ
β ππ οΏ½ ππ
(ππ β ππ) β (ππ β ππ) β (ππ β ππ) οΏ½ (ππ β β) β (ππ β ππ) β (ππ β ππ)
ππ ππ πΆπΆπΆπΆ ππ β πΆπΆπΆπΆ β’ π΄π΄ οΏ½ β οΏ½ π΅π΅ = οΏ½ ππ ππ οΏ½ οΏ½ β οΏ½ οΏ½ ππ ππ οΏ½ ππ ππ β ππ ππ β This operation canβt be done because the number of lines in the first matrix must be equal to the number of columns in the second matrix. ππ πΏπΏπΏπΏ β’ π΄π΄ οΏ½ β οΏ½ π΅π΅ = οΏ½ ππ ππ β
(ππ β ππ) β (ππ β β) = οΏ½(ππ β ππ) β (ππ β β) (ππ β ππ) β (ππ β β)
ππ πΏπΏπΏπΏ ππ ππ οΏ½ οΏ½ β οΏ½ οΏ½ ππ ππ β ππ
β ππ οΏ½ ππ
(ππ β ππ) β (ππ β ππ) (ππ β ππ) β (ππ β ππ) (ππ β ππ) β (ππ β ππ)
(ππ β ππ) β (ππ β ππ) (ππ β ππ) β (ππ β ππ)οΏ½ (ππ β ππ) β (ππ β ππ)
ππ ππ πΏπΏπΏπΏ ππ β πΏπΏπΏπΏ β’ π΄π΄ οΏ½ β οΏ½ π΅π΅ = οΏ½ ππ ππ οΏ½ οΏ½ β οΏ½ οΏ½ ππ ππ οΏ½ ππ ππ β ππ ππ β This operation canβt be done because the number of columns in the first matrix must be equal to the number of lines in the second matrix.
2.2 General Case of operation between matrices
πΆπΆπΆπΆ ππ ππππ β’ οΏ½ 1 οΏ½ π΅π΅ππ = ππππππ (2) ππππ2 With -ππ is the number of lines for the two matrices. The number of lines for the two matrices should be equal when the operation between the two matrices is πΆπΆπΆπΆ columns of the first matrix by the columns of the second matrix. - ππ is the number of columns for the first matrix π΄π΄. -ππ is the number of columns for the second matrix π΅π΅. The result matrix has the number of lines equal to ππ and the number of columns equal to ππ. ππ π΄π΄ππ
Example: πΆπΆπΆπΆ π΄π΄12 οΏ½ππππ1 οΏ½ π΅π΅31 = [β’ ππππ2 β’ β’ οΏ½β’ β’οΏ½ = ππ32 β’ β’
πΆπΆπΆπΆ β’] οΏ½ππππ1 οΏ½ [β’ ππππ2
ISBN: 978-1-61804-117-3
β’
Example: πΆπΆπΆπΆ 1 ππππ π΄π΄2 οΏ½ 1 οΏ½ π΅π΅13 = [β’ ππππ2
πΆπΆπΆπΆ β’ β’ β’] οΏ½ππππ1 οΏ½ οΏ½β’οΏ½ = οΏ½β’ β’ ππππ2 β’
β’ β’οΏ½ = ππ23 β’
πΏπΏπΏπΏ ππ ππ β’ π΄π΄ππ οΏ½ππππ1 οΏ½ π΅π΅ππππ = ππππ (4) ππππ2 With -ππ is the number of lines for the first matrix. - ππ is the number of columns for the first matrix π΄π΄. The number of columns for the first matrix must be equal to the number of columns in the second matrix when the operation between the two matrices is πΏπΏπΏπΏ Lines of the first matrix by the lines of the second matrix. -ππ is the number of lines for the second matrix π΅π΅. The result matrix has the number of lines equal to ππ and the number of columns equal to ππ. Example: πΏπΏπΏπΏ π΄π΄13 οΏ½ππππ1 οΏ½ π΅π΅32 = [β’ ππππ2 [β’ β’] = ππ21
β’
πΏπΏπΏπΏ β’ β’] οΏ½ππππ1 οΏ½ οΏ½ β’ ππππ2
β’ β’
β’ οΏ½= β’
πΏπΏπΏπΏ ππ ππ β’ π΄π΄ππ οΏ½ππππ1 οΏ½ π΅π΅ππππ = ππππ (5) ππππ2 With -ππ is the number of lines for the first matrix. -ππ is the number of columns for the first matrix π΄π΄. The number of columns for the first matrix must be equal to the number of lines in the second matrix when the operation between the two matrices is πΏπΏπΏπΏ Lines of the first matrix by the columns of the second matrix. -ππ is the number of columns for the second matrix π΅π΅.
β’] =
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The result matrix has the number of lines equal to ππ and the number of columns equal to ππ. Example: πΏπΏπΏπΏ β’ πΏπΏπΏπΏ 3 ππππ 1 π΄π΄1 οΏ½ 1 οΏ½ π΅π΅3 = οΏ½β’οΏ½ οΏ½ππππ1 οΏ½ [β’ β’ ππππ2 ππππ2 β’ β’ β’ οΏ½β’ β’ β’οΏ½ = ππ33 β’ β’ β’
β’
about the importance of this new method of operation between matrices.
β’ Example 1
β’] =
Suppose we have three polynomial equations of the second order as following: π¦π¦1 = πππ₯π₯ 2 + ππππ + ππ π¦π¦2 = πππ₯π₯ 2 + ππππ + ππ π¦π¦3 = πππ₯π₯ 2 + βπ₯π₯ + ππ We want to put them into matrices in order to simplify the writing. Therefore,
2.3 The Case when we have only the first operator πΆπΆπΆπΆππ
π¦π¦1 ππ π¦π¦ ππ οΏ½ 2οΏ½ = οΏ½ π¦π¦3 ππ
When we have only one operator we consider it as the first operator. In this case the two matrices must ππ ππ have the same dimensions for example π΄π΄ππ and π΅π΅ππ with ππ is the number of lines and ππ is the number of columns for both matrices. The operation will be only between the elements of two matrices which are located in the same position.
ππ πΏπΏπΏπΏ π₯π₯ 2 πποΏ½ οΏ½ β οΏ½ οΏ½ π₯π₯ οΏ½ ππ + 1
It can be written also in the following form ππ ππ ππ πΆπΆπΆπΆ π₯π₯ 2 [π¦π¦1 π¦π¦2 π¦π¦3 ] = οΏ½ππ ππ β οΏ½ οΏ½ β οΏ½ οΏ½ π₯π₯ οΏ½ ππ ππ ππ + 1
Suppose the following matrices: ππ ππ ππ ππ οΏ½ and π΅π΅ = οΏ½ οΏ½ π΄π΄ = οΏ½ ππ β ππ ππ
β’ Example 2
Suppose we have four polynomial equations as following: π₯π₯ π¦π¦1 =
ππ ππ (ππππ ) ππ ππ οΏ½ οΏ½ 1 οΏ½ ππ β ππ ππ ππ ππππ1 ππ ππ ππππ1 ππ οΏ½ π΄π΄(ππππ1 )π΅π΅ = οΏ½ ππ ππππ1 ππ ππ ππππ1 β For example: consider that the first Operation (ππππ1 ) is replaced respectively by (+, *, -, /). Therefore the operation of two matrices will be as following: β’ π΄π΄(ππππ1 )π΅π΅ = οΏ½
(π₯π₯β1)
1
π¦π¦2 = π₯π₯(1 + ) π₯π₯ π¦π¦3 = π₯π₯ 2 π¦π¦4 = π₯π₯(4π₯π₯ + 3) We want to put them into matrices in order to simplify the writing. Therefore,
Suppose the following matrices: ππ ππ ππ ππ οΏ½ and π΅π΅ = οΏ½ οΏ½ thus π΄π΄ = οΏ½ ππ β ππ ππ ππ + ππ ππ + ππ οΏ½ π΄π΄(+)π΅π΅ = οΏ½ ππ + ππ ππ + β ππ β ππ ππ β ππ οΏ½ π΄π΄(β)π΅π΅ = οΏ½ ππ β ππ ππ β β ππ β ππ ππ β ππ οΏ½ π΄π΄(β)π΅π΅ = οΏ½ ππ β ππ ππ β β ππ/ππ ππ/ππ οΏ½ π΄π΄(/)π΅π΅ = οΏ½ ππ/ππ ππ/β
π¦π¦1 οΏ½π¦π¦
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π¦π¦2 π₯π₯ π¦π¦4 οΏ½ = οΏ½π₯π₯
β’ Example 3
1 π₯π₯ οΏ½ (β) οΏ½π₯π₯β1 π₯π₯ π₯π₯
1+
1
π₯π₯
4π₯π₯ + 3
οΏ½
Suppose we have four polynomial equations as following: π¦π¦1 = (π₯π₯ 2 + π₯π₯)(π₯π₯ + 3) 1 π¦π¦2 = οΏ½π₯π₯ 2 + οΏ½ (π₯π₯ + 2) π₯π₯ π¦π¦3 = (π₯π₯ 3 + π₯π₯)(2 + 3) 1
π¦π¦4 = οΏ½π₯π₯ 3 + οΏ½ (2 + 2)
Remark: The operation between two matrices π΄π΄(β)π΅π΅ is not the same as the traditional operation π΄π΄ β π΅π΅.
π₯π₯
We want to put them into matrices in order to simplify the writing. Therefore, πΏπΏπΏπΏ π₯π₯ 3 2 π¦π¦1 π¦π¦2 οΏ½π¦π¦ π¦π¦ οΏ½ = οΏ½π₯π₯ 3 π₯π₯ οΏ½ οΏ½ + οΏ½ οΏ½ 1 2οΏ½ 3 4 π₯π₯ 2 π₯π₯ β
3 Practical examples of the General operation of matrices In this section we are going to see some practical examples in mathematics in order to give an idea
ISBN: 978-1-61804-117-3
ππ ππ β
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Advances in Mathematical and Computational Methods
β’ Example 4
first operation between two elements of the two matrices, with (ππππ1 ) can be replaced by an operator (+, -, *, /), the second operator (ππππ2 ) is the operator between the operated elements such as (ππ ππππ1 ππ)ππππ2 (ππ ππππ1 ππ). With (ππππ2 ) can be replaced by an operator (+, -, *, /). Many studies will follow this paper in order to find other applications in many domains as in science, engineering and mathematics.
Suppose we have three polynomial equations of the second order as following: π¦π¦1 = πππ₯π₯ 3 + πππ₯π₯ 2 + ππ It can be written in the following form ππ πΆπΆπΆπΆ π₯π₯ 3 [π¦π¦1 ] = οΏ½ππ οΏ½ οΏ½ β οΏ½ οΏ½π₯π₯ 2 οΏ½ ππ + 1
It can be written also in the following form ππ πΆπΆπΆπΆ [π¦π¦1 ] = οΏ½ππ οΏ½ οΏ½ β οΏ½ [π₯π₯ 3 π₯π₯ 2 1] ππ +
References: [1] Arnold Vladimir I.; Cooke Roger, βOrdinary differential equationsβ, Berlin, DE; New York, NY:Springer-Verlag, ISBN 978-3-540-54813-3 (1992). [2] Artin Michael, βAlgebraβ, Prentice Hall, ISBN 978-0-89871-510-1, (1991). [3] Association for Computing Machinery, βComputer Graphicsβ, Tata McGrawβHill, ISBN 978-0-07-059376-3, (1979). [4] Baker Andrew J., βMatrix Groups: An Introduction to Lie Group Theoryβ, Berlin, DE; New York, NY: Springer-Verlag, ISBN 978-185233-470-3, (2003). [5] Bau III David, Trefethen Lloyd N., βNumerical linear algebraβ, Philadelphia, PA: Society for Industrial and Applied Mathematics, ISBN 978-089871-361-9, (1997). [6] Bretscher Otto, βLinear Algebra with Applicationsβ (3rd ed.), Prentice Hall, (2005). [7] Bronson Richard, βSchaum's outline of theory and problems of matrix operationsβ, New York: McGrawβHill, ISBN 978-0-07-007978-6, (1989). [8] Brown William A., βMatrices and vector spacesβ, New York, NY: M. Dekker, ISBN 978-0-82478419-5, (1991). [9] Coburn Nathaniel, βVector and tensor analysisβ, New York, NY: Macmillan, OCLC 1029828, (1955). [10] Conrey J. Brian, βRanks of elliptic curves and random matrix theoryβ, Cambridge University Press, ISBN 978-0-521-69964-8, (2007). [11] Gilbarg David, Trudinger Neil S., βElliptic partial differential equations of second orderβ (2nd ed.), Berlin, DE; New York, NY: SpringerVerlag, ISBN 978-3-540-41160-4, (2001).
β’ Example 5
Suppose we have four polynomial equations as following: π¦π¦1 =
π¦π¦2 = π¦π¦3 = π¦π¦4 =
οΏ½π₯π₯ 2 +π₯π₯οΏ½
π₯π₯ +3 1 οΏ½π₯π₯ 2 + οΏ½ π₯π₯
π₯π₯+2 οΏ½π₯π₯ 3 +π₯π₯οΏ½
2+3 1 οΏ½π₯π₯ 3 + οΏ½ π₯π₯
2+2
We want to put them into matrices in order to simplify the writing. Therefore, πΏπΏπΏπΏ π₯π₯ 3 2 π¦π¦1 π¦π¦2 π₯π₯ π₯π₯ οΏ½π¦π¦ π¦π¦ οΏ½ = οΏ½ 3 οΏ½ οΏ½ + οΏ½ οΏ½ 1 2οΏ½ 3 4 π₯π₯ 2 / π₯π₯
4 Conclusion In this paper, the author introduced a new and original way of operation between matrices. The traditional operation between matrices is just a part of the general operation of matrices. The general operation of matrices is introduced in order to facilitate the writing of many complicated expressions into matrices and to facilitate the operation between matrices as we want. We can operate the Columns of the first matrix by the columns of the second matrix, or the columns of the first matrix by the Lines (rows) of the second matrix, or Lines of the first matrix by the line of the second matrix, or the Lines of the first matrix by the columns of the second matrix. This is not the case of the traditional operation between matrices. Mainly we have two operations between matrices, the first operation is between the elements of the two matrices and the second is the operation between the operated elements. For example: (ππ (ππππ1 )ππ) is the ISBN: 978-1-61804-117-3
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