Lecture 12: Lattice vibrations

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December 06. Lecture 12. 1. Lecture 12: Lattice vibrations. Quantised Lattice vibrations: Diatomic systems in 1-D and in Phonons in 3-D. 6 Aims: ?
Lecture 12: Lattice vibrations Quantised Lattice vibrations: Diatomic systems in 1-D and in Phonons in 3-D Aims: Model systems (continued): Lattice with a basis: Phonons in a diatomic chain origin of optical and acoustic modes

Phonons as quantised vibrations Real, 3-D crystals: Examples of phonon dispersion: Rare gas solids Alkali halides

December 06

Lecture 12

1

Diatomic lattice Technically a lattice with a basis mmAA

mmBB

proceeding as before. Equations of motion are:

m Au2 n = α (u2 n +1 + u2 n −1 − 2u2 n )

mB u2 n +1 = α (u2 n + 2 + u2 n − 2u2 n +1 ) Trial solutions:

u2 n = U1 exp{ i(2nqa − ω t )}

u2 n +1 = U 2 exp{ i(( 2n + 1) qa − ω t )} substituting gives

(m

2 ω − 2α )U1 + (2α cos qa )U 2 = 0 A

(2α cos qa )U1 + (mB ω 2 − 2α )U 2 = 0

homogeneous equations require determinant to be zero giving a quadratic equation for ω2.

ω =

α

2

m A mB

{(m December 06

[(mA + mB ) ±

+ mB ) − 4m A mB sin qa 2

A

2

Lecture 12

}

12

Two Two solutions solutions for for each each qq

] 2

Acoustic and Optic modes Solutions q

0: Optic mode (higher frequency)

ω=

α 2(m A + mB ) m A mB

=



Effective Effective mass mass µµ

µ

Acoustic mode (lower frequency)

ω2 ≈

α

m A mB

[(mA + mB ) −

(mA + mB ) 1 − 4 mA mB 2 (qa )2 (m A + m B )

12

]

2αa 2 ω ≈ q m A + mB ω= ω=√(2α √(2α/m /mBB))

ω= ω=√(2α √(2α/m /mAA))

December 06

Periodic: Periodic: all all distinguishable distinguishable modes modes lie lie in in |q|< |q|