Advanced Nonlinear Studies 5 (2005), 337–350
Non-radial Maximizers For Functionals With Exponential Non-linearity in R2 Marta Calanchi, Elide Terraneo Dipartimento di Matematica ”F. Enriques” Universit` a di Milano, via Saldini, 50, 20133 Milano, Italy e-mail:
[email protected],
[email protected] Received 1 October 2004 Communicated by Jean Mawhin
Abstract We consider the functional F : H01 (B(0, 1)) → R Z γ |x|α (ep|u| − 1 − p|u|γ ) dx F (u) = B(0,1)
where α > 0, p > 0, 1 < γ ≤ 2, and B(0, 1) is the unit ball in R2 . We prove that for any p > 0, 1 < γ < 2 and 0 < p < 4π, γ = 2 no maximizer of F (u) on the unit ball in H01 is radially symmetric provided that α is large enough. This extends a result of Smets, Su and Willem concerning the existence of non-radial ground state solutions for the Rayleigh quotient related to the H´enon equation with Dirichlet boundary conditions. 2000 Mathematics Subject Classification. 35J60. Key words. non-radial solutions, exponential growth.
1
Introduction
The present work is mainly motivated by a paper due to Smets, Su, Willem (see [14]) in which the authors consider the problem of the symmetry of positive solutions for the H´enon equation with Dirichlet boundary conditions 337
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α p−1 in B(0, 1), −∆u = |x| u u > 0 in B(0, 1), u|∂B(0,1) = 0,
(1.1)
where B(0, 1) denotes the unit ball in RN , N ≥ 2, centered at the origin, α > 0, p > 2. The existence of solutions in the Sobolev space H01 for N ≥ 3 was first considered by Ni in 1982 [11]. He realizes that the presence of the weight |x|α widens the range of p for which a solution exists. Ni proves via an application of the Mountain Pass Theorem in the space of radial functions in H01 that problem (1.1) possesses a radial solution for any 2N ∗ p ∈ (2, 2∗ + N2α −2 ), where 2 = N −2 is the critical exponent of the Sobolev embedding if N ≥ 3. Moreover thanks to the Pohozaev identity, one can show that there are no solution if p ≥ 2∗ + N2α −2 . In contrast with the case in which the weight is a non-increasing radial function (see [8]), (1.1) has not only radial solutions. Indeed in [14] Smets, Su, Willem prove that for any p ∈ (2, 2∗ ), there exists at least a non-radial solution of (1.1) provided that α is large enough. This result also holds in the case of dimension N = 2 where 2∗ = +∞. They study the ground state solutions of (1.1), i.e. functions which minimize the Rayleigh quotient R |∇u|2 dx B(0,1) p Rα (u) = u ∈ H01 , u 6= 0. (1.2) p2 , R α |u|p dx |x| B(0,1) Under suitable rescalings, the minimizers of (1.2) are solutions of (1.1). Then they establish that for α sufficiently large the infimum of (1.2) is attained by a non-radial function. Theorem [Smets, Su, Willem [14]]. Assume N ≥ 2. For any p ∈ (2, 2∗ ) there exists α∗ such that any minimizer of (1.2) is non-radial provided α > α∗ . They also give some information about the behaviour of α∗ as p goes to 2 or to 2∗ . In particular they show that α∗ goes to 0 when p tends to 2∗ and α∗ goes to +∞ if p tends to 2. In [13] Serra investigates the existence of non-radial solutions to (1.1) in the critical case p = 2∗ when the spatial dimension N is greater than or equal to 4. He proves the following theorem: Theorem [Serra [13]]. Let N ≥ 4. Then for every α > 0 large enough, the problem α 2∗ −1 in B(0, 1), −∆u = |x| u u > 0 in B(0, 1), u|∂B(0,1) = 0, admits at least one non-radial solution.
(1.3)
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Of course this solution is not a ground state of the Rayleigh quotient. The idea of the author is to find it as a critical point of the Rayleigh quotient (1.2) restricted to a wellchosen subspace of H01 invariant under the action of some subgroup of O(N ). In this paper we are interested in the critical case when the spatial dimension N is equal to 2. In this case any polynomial growth is allowed and the critical growth is given by the Trudinger-Moser inequality (see [16], [10]), namely Z 2 sup eβu dx ≤ C(β) ≤ C(4π) < +∞ for β ≤ 4π, (1.4) kukH 1 ≤1 0
B(0,1)
Z
2
eβu dx = +∞
sup kukH 1 ≤1 0
for
β > 4π.
(1.5)
B(0,1)
The second relation (1.5) can be easily established by testing the functional Z 2 eβu dx B(0,1)
on a family of functions called Moser’s sequence defined as follows: p log k
|x|
0, p > 0 and 1 < γ ≤ 2. We are interested in understanding for which values of γ, p and α the supremum of F (u) on the set S1 = {u ∈ H01 : kukH01 ≤ 1} is finite
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and attained. Then, as in the polynomial case, the natural question is to know whether it is achieved by a radial or by a non-radial function. We denote by Tα,p,γ = sup F (u) u∈ S1
and by R Tα,p,γ =
sup
F (u),
u∈ S1 , u rad
namely the supremum considered only over the sub-space of radial functions. Thanks to the Trudinger-Moser inequality, Tα,p,γ is finite in the subcritical cases 1 < γ < 2, p > 0 and γ = 2, 0 < p < 4π, and in the critical case γ = 2 and p = 4π. For these cases we prove R that the supremum Tα,p,γ on radial functions differs from that on non-radial functions, provided that α is large enough. Indeed we establish the theorem: Theorem 1.1 For p > 0, 1 < γ < 2 and for 0 < p ≤ 4π, γ = 2, there exists α∗ > 0 such R for any α > α∗ . that Tα,p,γ > Tα,p,γ By an argument similar to that used in Lemma 2.1 in [6] one can prove that in the subcritical R are cases p > 0, 1 < γ < 2 and 0 < p < 4π, γ = 2, both suprema Tα,p,γ and Tα,p,γ achieved. Then in these cases an analogue of the result of Smets, Su and Willem holds: Corollary 1.1 For p > 0, 1 < γ < 2 and 0 < p < 4π, γ = 2 there exists α∗ > 0 such that no maximizer of F (u) on S1 is radial provided that α > α∗ . Then we analyse the supercritical case, namely γ = 2 and p > 4π, and we show that the supremum over the whole space H01 is not finite. In order to prove this it is enough to evaluate the functional F on a suitable family of Moser’s type functions supported in balls of radius tending to zero and centered at points approaching the boundary. In this way the action of the weight |x|α becomes negligible and we are in the same situation described by the Trudinger-Moser inequality (1.5). Moreover, in analogy with the result due to Ni in [11], we can prove that for 4π < p ≤ 4π + 2πα the supremum over the subspace of radial functions in H01 is finite. In fact we establish the following result: Proposition 1.1 i) Tα,p,2 = +∞ if p > 4π; R R ii) Tα,p,2 < +∞ if 0 < p ≤ 4π + 2πα and Tα,p,2 = +∞
if p > 4π + 2πα.
Finally we propose for γ = 2 a sort of generalization of the result described in Theorem 1.1. We consider the functional: Z 2 Gλ (u) = |x|α (epu − 1 − λpu2 )dx (1.9) B(0,1)
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where λ ∈ [0, 1], α > 0 and 0 < p ≤ 4π and denote Tα,λ =
sup kukH1 ≤1 0
Gλ (u) =
sup
Gλ (u)
(1.10)
kukH1 =1 0
(where the last equality is due to the monotonicity properties of the functional Gλ ). We prove the following: Theorem 1.2 Let 0 < p ≤ 4π. Then there exists 0 ≤ λ∗ < 1 such that for any R λ ∈ [λ∗ , 1], Tα,λ > Tα,λ , for large values of α. The presence of the term λpu2 in the functional (1.9) seems to us to be in a certain way necessary: in fact we do not know if λ∗ can be equal to zero. R For the subcritical case we also prove that both suprema Tα,λ and Tα,λ are achieved and so we obtain: Corollary 1.2 For any 0 < p < 4π, there exists 0 ≤ λ∗ < 1 such that for any λ ∈ [λ∗ , 1] no maximizer of Gλ (u) on S1 is radial for large value of α. Finally we point out that any maximizer of (1.10) satisfies for some constant c the following elliptic problem 2 −∆u = c|x|α u(epu − λ) in B(0, 1), u > 0 in B(0, 1), u| ∂B(0,1) = 0.
(1.11)
Of course the constant c cannot be computed explicitly because of the non-homogeneity of the exponential function. So there is no direct correspondence between equation and ground state solutions (as it happens for the H´enon equation). The question of existence of non-symmetric solutions for symmetric problems has been widely investigated (we refer the reader to the survey of Brezis ([2]) for a complete bibliography). Here we only mention the paper of Brezis and Nirenberg [3], in which the authors prove that if the domain is an annulus there exists a non-radial solution for (1.1) in the autonomous case (i.e α = 0). The results of existence for the H´enon equation in [14] and [13] and in Theorem 1.1 above suggest that the coefficient |x|α has a similar effect to the presence of a ”hole” in B(0, 1), when α is large enough. We also want to remark that in spite of these ”simmetry breaking phenomena” the maximizers may still present a weaker symmetry, as suggested in the paper of Smets and Willem [15].
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Proof of Theorem 1.1
In the present section we consider the subcritical cases 1 < γ < 2, p > 0 and γ = 2, 0 < p < 4π, and the critical case γ = 2 and p = 4π and we prove that the supremum on R non-radial functions Tα,p,γ is greater than the supremum on radial functions Tα,p,γ at least R for α large enough. Our first result is an asymptotic estimate of Tα,p,γ for α → +∞. Lemma 2.1 (Asymptotic estimate). For p > 0, 1 < γ < 2 and 0 < p ≤ 4π, γ 2 R γ = 2, then Tα,p,γ ∼ 2 S(2γ)p , for α → +∞ where S(2γ) is the Sobolev constant R α1+γ 2γ S(2γ) = supkukH 1 ≤1 B(0,1) |u| dx. 0
The proof of Lemma 2.1 relies on the following lemma. Lemma 2.2 There exists a positive constant C such that for any u ∈ H10 and any q ≥ 2 the following inequality holds: h q i q1 kukLq ≤ C Γ +1 kukH10 , 2 where Γ(λ) =
R +∞ 0
(2.12)
e−x xλ−1 dx is the Gamma function.
Proof of Lemma 2.2. Since H10 ,→ Leu2 −1 , where Leu2 −1 is the Orlicz space defined 2 via the convex function ϕ(t) = et − 1, t ∈ [0, +∞), the inequality (2.12) is a direct consequence of i q1 h q +1 kukL u2 , (2.13) kukLq ≤ Γ e −1 2 established in [12]. For the convenience of the reader we recall in the appendix the definition of the Orlicz space Leu2 −1 and the proof of the inequality (2.13). Proof of Lemma 2.1. For a radially symmetric function consider the transformation √ 2 , introduced in the paper of Smets, Su and Willem [14]. u(|x|β ) = β w(|x|) , β = α+2 By an easy computation we have Z Z γ γ γ γ epβ 2 |w| − 1 − pβ 2 |w|γ dx; |x|α ep|u| − 1 − p|u|γ dx = β B(0,1)
B(0,1)
and
Z
|∇w(x)|2 dx ≤ 1.
B(0,1)
So we obtain R Tα,p,γ =
Z sup kwkH1 ≤1, w rad 0
β B(0,1)
γ γ γ epβ 2 |w| − 1 − pβ 2 |w|γ dx.
(2.14)
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The control from below of the integral in (2.14) comes from the following inequality: R Tα,p,γ ≥
β 1+γ p2 2 kwkH 1 ≤1
Z
|w|2γ dx =
sup 0
B(0,1)
β 1+γ p2 S(2γ). 2
R In order to obtain an estimate from above of Tα,p,γ we expand the exponential function in series to get:
Z
β
+∞ Z γ X γ γ epβ 2 |w| − 1 − pβ 2 |w|γ dx = β
B(0,1)
=
k=2
β 1+γ p2 2
Z
|w|2γ dx + β
B(0,1)
+∞ Z X k=3
X β 1+γ p2 S(2γ) + β 2
k=3
B(0,1)
B(0,1)
k
k
γ
B(0,1)
+∞ Z
≤
γ
(pβ 2 |w|γ ) dx k!
(pβ 2 |w|γ ) dx k!
γ
k
(pβ 2 |w|γ ) dx. k!
Now we estimate the series: thanks to Lemma 2.2 we have γk kukγk γk ≤ C Γ(
γk + 1)kukγk H10 2
so in order to control the integral in (2.14) from above it is enough to show that the series γ k +∞ X (pβ 2 ) γk Γ + 1 C γk k! 2
k=3
converges, since kukH10 ≤ 1. We recall that the Gamma function has a minimum localized between 1 and 2 and it is increasing afterwards. So the last series is controlled by γ +∞ X pβ 2
k=3
k
C γk Γ(k + 1) 3γ = O(β 2 ) k!
(2.15)
for β small enough. So we obtain the estimate from above R Tα,p,γ ≤
3γ β 1+γ p2 S(2γ) + O(β 1+ 2 ). 2
Now we are able to prove Theorem 1.1. Proof of Theorem 1.1. Let u be a positive smooth function with support in B(0, 1) and such that kukH10 = 1. Following Smets, Su and Willem let us consider uα (x) =
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u(α(x − xα )), where xα = (1 − α1 , 0). Since kuα kH10 = 1 and it has support in the ball B(xα , α1 ), by the change of variables y = α(x − xα ) we obtain: Z γ Tα,p,γ ≥ |x|α ep|uα | − 1 − p|uα |γ dx B(0,1) Z γ |x|α ep|uα | − 1 − p|uα |γ dx = 1 ) B(xα , α
≥
2 α
1−
α
1 α2
Z
γ
ep|u| − 1 − p|u|γ
dy
B(0,1) 2γ S(2γ)p2 , α1+γ
R ∼ and so Tα,p,γ ≥ αC2 , for α → +∞. Since, by Lemma 2.1, Tα,p,γ R we are able to conclude that Tα,p,γ > Tα,p,γ for α large enough.
as α → +∞
Proof of Corollary 1.1. In view of Theorem 1.1 it is enough to show that both suprema R Tα,p,γ and Tα,p,γ are achieved. For simplicity we only consider the case of the supremum Tα,p,γ for γ = 2, 0 < p < 4π. Let {un } be a maximizing sequence such that kun kH01 ≤ 1. Then, up to a subsequence, there exists u ∈ H01 such that un * u weakly in H01 and strongly in Lq , ∀q ≥ 1 and un (x) → u(x) a.e. in B(0, 1). By using Lemma 2.1 in [6] in order to prove that Z Z 2 2 α pun 2 |x| e − 1 − pun dx → |x|α epu − 1 − pu2 dx as n → +∞ B(0,1)
B(0,1)
it is enough to show that Z
2
|x|α epun |un |dx ≤ C.
(2.16)
B(0,1)
Since p < 4π, there exists q > 1 such that pq < 4π. By the H¨older inequality, if q 0 is the conjugate exponent of q, one has Z
α pu2n
|x| e B(0,1)
! 10 q
Z |un |dx ≤
|un | B(0,1)
q0
! q1
Z
pqu2n
e
≤C
B(0,1)
which is a direct a consequence of the Trudinger-Moser inequality.
Remark. We do not know if Corollary 1.1 holds in the case p = 4π and γ = 2. In fact ´ and Ruf below, it is thanks to equality (2.14) and to the Theorem of de Figueiredo, do O R easy to show that the supremum Tα,4π,2 is achieved. On the other hand it is not clear if the supremum Tα,4π,2 is attained or not. ´ Ruf [5]] Suppose that g satisfies: Theorem [de Figueiredo, do O, 1 i) g ∈ C (R); ii) g is increasing on R+ and g(s) = g(|s|);
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Non-radial maximizers
2
iii) 0 ≤ g(s) ≤ e4πs − 1, for any s ≥ 0; iv) g(s) has subcritical growth. Then Z sup kukH 1 ≤1 0
g(u)dx
B(0,1)
is attained.
3
A remark on the supercritical case
In the present section we prove that in the supercritical case γ = 2, p > 4π the supremum Tα,p,2 is not finite. In order to prove this we evaluate the functional F (u) on some particular functions obtained by a suitable translation and dilation of Moser’s functions in a region of B(0, 1) far from the origin where the presence of |x|α can be neglected. Proof of Proposition 1.1 (Case i). Consider the following family of functions p log k 1 ) 1 log( α|x−x α| wk,α (x) = √ √ 2π log k 0
|x − xα |
2, k > 2. We observe that kwk,α kH01 = 1. Moreover, Z
2 2 |x|α epwk,α − 1 − pwk,α dx
Tα,p,2 ≥ B(0,1)
Z
2 2 |x|α epwk,α − 1 − pwk,α dx
≥
1 ) B(xα , kα α
≥
1−
=
1−
2 α
Z
2 α
α
p
e 2π log k − 1 −
1 B(xα , kα ) p
k 2π − 1 −
p log k dx 2π
π p log k 2π α2 k 2
and the last term tends to +∞ when k → +∞ since p > 4π.
If we restrict our attention to the supremum on radial functions the situation is different. In this case the factor |x|α , α > 0 improves the convergence properties of the integral and we have the following result: Proof of Proposition 1.1 (Case ii). For a radially symmetric function, using the same
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change of variables as in Proposition 2: u(|x|β ) = R Tα,p,2 =
Z sup
β
||w||H 1 ≤1, w rad
√
βw(|x|) , β =
2 α+2 ,
we get
2 epβw − 1 − pβw2 dx.
(3.18)
B(0,1)
0
Thanks to the Trudinger-Moser inequality quoted above this quantity is finite if and only if p verifies 0 < p ≤ 4π β = 2πα + 4π. R Remark. We point out that the supremum on radial functions Tα,p,2 is attained for any 0 < p < 4π + 2πα, α > 0. Indeed, this result is a direct consequence of equality (3.18) ´ Ruf [5] quoted at the end of the second section. and of the Theorem of de Figueiredo, do O, In the limit case p = 4π + 2πα, α > 0 it is not known if the supremum is achieved (see Theorem 5 in [5]).
4
A generalization
In the present section we consider Z Tα,λ =
2 |x|α epu − 1 − pλu2 dx
sup kukH1 ≤1 0
(4.19)
B(0,1)
where α > 0, 0 < p ≤ 4π and 0 ≤ λ ≤ 1 and we prove Theorem 1.2, which generalizes Theorem 1.1 for γ = 2. Proof of Theorem 1.2. The case λ = 1 was treated in Theorem 1.1; so here we only analyse the case λ < 1. At first, in a similar way as in Lemma 2.1, we establish the following asymptotic estimate for the supremum on radial functions in the unit ball of H01 : R Tα,λ ∼
4p(1 − λ) α 2 λ1
as α → +∞,
where λ1 is the first eigenvalue of the Laplacian in H01 (B(0, 1)). Indeed, thanks to the √ 2 , we obtain transformation u(|x|β ) = β w(|x|), β = α+2 R Ta,λ
Z =
sup kwkH 1 ≤1,w rad 0
β
2 epβw − 1 − pβλw2 dx.
B(0,1)
Now the estimate from below comes from the inequality: R Ta,λ ≥
sup kwkH 1 ≤1 0
β 2 p(1 − λ)
Z B(0,1)
w2 dx =
pβ 2 (1 − λ) . λ1
(4.20)
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Non-radial maximizers
On the other hand we control the supremum from above by using a Taylor expansion of the exponential term, namely Z 2 β epβw − 1 − pβλw2 dx = B(0,1)
Z
2
2
= β p(1 − λ)
w dx + β B(0,1)
+∞ k k Z X p β k=2
k!
(4.21) w
2k
dx.
B(0,1)
Then, thanks to Lemma 2.2, there exists a constant C > 0 independent of w such that 2k 2k kwk2k 2k ≤ C Γ(k + 1)kwkH 1 , 0
so, since kwkH01 ≤ 1, we get +∞
X (pβC 2 )k β 2 p(1 − λ) +β Γ(k + 1) λ1 k!
R Tα,λ ≤
k=2
(4.22)
β 2 p(1 − λ) p2 C 4 = + β3 λ1 1 − pβC 2 2 for β = α+2 small enough. For the supremum on the whole unit ball in H01 , since λ ≤ 1, one has
Z Tα,λ =
2 |x|α epu − 1 − pλu2 dx
sup kukH1 ≤1 0
B(0,1)
Z ≥
sup kukH1 ≤1 0
2 |x|α epu − 1 − pu2 dx
B(0,1)
and as in the proof of Theorem 1.1 we can show that there exists C > 0 independent of λ such that Tα,λ ≥ αC2 , for α large enough. The conclusion of the theorem follows by ∗ ) choosing λ∗ such that 4p(1−λ < C. λ1 Proof of Corollary 1.2. The proof follows the same lines of Corollary 1.1.
As mentioned in the introduction we are not able to establish Theorem 1.2 if λ = 0. Indeed in this case we obtain that R Tα,0 ∼
4p , as α → +∞; α 2 λ1
on the other hand for the supremum on all functions Tα,0 we give an estimate from below, namely Tα,0 ≥ αC2 for α big enough with a constant C < λ4p1 . So the same argument as in Theorem 1.2 cannot apply.
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Appendix
In this last section we recall the definition of the Orlicz space Leu2 −1 and we give the proof of equality (2.13) established in [12]. We refer to [1] and [9] for a wide presentation of the Orlicz spaces. Let ϕ : [0, +∞[→ [0, +∞[ be a convex, strictly increasing function such that lim+ ϕ(s) = s→0
ϕ(0) = 0 and lim ϕ(s) = +∞. s→+∞
Definition 5.1 The Orlicz space Lϕ is defined by Lϕ = {u measurable on B(0, 1) such that ∃ K > 0 ) u(x) dx < +∞ . with ϕ K B(0,1) Z
It can be proven that Lϕ is a vector space (see [9]). For every u ∈ Lϕ , let us define the functional ( ) Z u(x) kukϕ = inf K > 0 such that ϕ dx ≤ 1 K B(0,1) One can prove that k · kϕ is a norm on Lϕ and (Lϕ , k · kϕ ) is a Banach space (see [9]). It is easy to verify that the function ϕ(u) = |u|p , 1 < p < +∞ defines the Lp space. 2 In the following we will consider the Orlicz space defined by ϕ(u) = eu − 1. For this particular space we have: Lemma 5.1 For every p ≥ 2 we have Leu2 −1 ,→ Lp and i p1 h p +1 kukL 2 . kukLp ≤ Γ eu −1 2 where Γ(λ) =
R +∞ 0
(5.23)
e−x xλ−1 dx.
Proof. Let K = kukL
2 eu −1
> 0, otherwise inequality (5.23) is obvious. We will use the
property that ex − 1 ≥
xρ , Γ(ρ + 1)
(5.24)
for every ρ ≥ 1 and x ≥ 0. This is easily proven when ρ is an integer. For x ∈ (0, 1] and for every ρ > 1 the inequality follows by using the fact that Γ(ρ + 1) ≥ 1 if ρ ≥ 1, and ex − 1 ≥ xρ . For x ∈ [1, +∞) and 1 < ρ < 2 the inequality (5.24) is implied by the fact that ex − 1 − x2 ≥ 0 and the property Γ(ρ + 1) ≥ 1. The general inequality for x ∈ [1, +∞) and 2 < ρ follows from the case 1 < ρ < 2 by an easy computation, since
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Non-radial maximizers
Γ(ρ + 1) = ρΓ(ρ). By the theorem of monotone convergence for K = kukL
2 eu −1
have
Z
1≥
> 0 we
|u| 2 e( K ) − 1 dx
B(0,1)
and by (5.24) Z 1≥ B(0,1)
for every ρ ≥ 1. Thus we obtain 1 ≥
|u| K
2ρ
Γ(ρ + 1)
kuk2ρ 2ρ 2ρ K Γ(ρ+1)
dx
and we conclude that K ≥
kuk2ρ 1
(Γ(ρ+1)) 2ρ
.
Acknowledgments. The authors would like to thank Bernhard Ruf and Enrico Serra for bringing this problem to their attention and for stimulating discussions.
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