Hindawi Publishing Corporation Journal of Function Spaces Volume 2015, Article ID 598538, 5 pages http://dx.doi.org/10.1155/2015/598538
Research Article Multiplicative Isometries on Classes ππ(π) of Holomorphic Functions Yasuo Iida1 and Kazuhiro Kasuga2 1
Department of Mathematics, Iwate Medical University, Yahaba, Iwate 028-3694, Japan Academic Support Center, Kogakuin University, Tokyo 192-0015, Japan
2
Correspondence should be addressed to Yasuo Iida;
[email protected] Received 19 March 2015; Revised 12 June 2015; Accepted 14 June 2015 Academic Editor: Alberto Fiorenza Copyright Β© 2015 Y. Iida and K. Kasuga. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited. In (Iida and Kasuga 2013), the authors described multiplicative (but not necessarily linear) isometries of ππ (π) onto ππ (π) in the case of positive integer π β N, where ππ (π) (π β₯ 1) is included in the Smirnov class πβ (π). In this paper, we will generalize the result to arbitrary (not necessarily positive integer) value of the exponents 0 < π < β.
1. Introduction Let π be a positive integer. The space of π-complex variables π§ = (π§1 , . . . , π§π ) is denoted by Cπ . The unit polydisk {π§ β Cπ : |π§π | < 1, 1 β€ π β€ π} is denoted by ππ and the distinguished boundary T π is {π§ β Cπ : |π§π | = 1, 1 β€ π β€ π}. The unit ball {π§ β Cπ : βππ=1 |π§π |2 < 1} is denoted by π΅π and ππ is its boundary. In this paper π denotes the unit polydisk or the unit ball for π β₯ 1 and ππ denotes T π for π = ππ or ππ for π = π΅π . The normalized (in the sense that π(ππ) = 1) Lebesgue measure on ππ is denoted by ππ. The Hardy space on π is denoted by π»π (π) (0 < π β€ β) and β β
βπ denotes the norm on π»π (π) (1 β€ π β€ β). The Nevanlinna class π(π) on π is defined as the set of all holomorphic functions π on π such that σ΅¨ σ΅¨ sup β« log (1 + σ΅¨σ΅¨σ΅¨π (ππ§)σ΅¨σ΅¨σ΅¨) ππ (π§) < β
0β€π 0. Lemma 5 (see [8]). If a completely monotone function π(π₯) on (0, +β) can be continued to an infinitely differentiable function on [0, +β), then the inequality (β1)π {π (π₯) β π (0) β πσΈ (0) π₯ β β
β
β
π₯π π(πβ1) (0) πβ1 β π₯ } β₯ 0, (π β 1)!
(14)
π₯ > 0,
holds for any π β N and π(π) (0) =ΜΈ 0 if only π is not constant. Lemma 6. Let πΆ be a cone of measurable functions on a measurable space with a measure (πΊ, π), and let π΄ be a mapping from πΆ to the set of measurable functions. Suppose that π΄ is homogeneous with positive coefficients and σ΅¨ π σ΅¨ β« (log (1 + σ΅¨σ΅¨σ΅¨π΄π (π₯)σ΅¨σ΅¨σ΅¨)) π (ππ₯) πΊ
σ΅¨ π σ΅¨ = β« (log (1 + σ΅¨σ΅¨σ΅¨π (π₯)σ΅¨σ΅¨σ΅¨)) π (ππ₯) , πΊ
(15) π β πΆ,
Journal of Function Spaces
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for some π > 0. Then σ΅¨π σ΅¨π σ΅¨ σ΅¨ β« σ΅¨σ΅¨σ΅¨π΄π (π₯)σ΅¨σ΅¨σ΅¨ π (ππ₯) = β« σ΅¨σ΅¨σ΅¨π (π₯)σ΅¨σ΅¨σ΅¨ π (ππ₯) , πΊ πΊ
π β πΆ,
(16)
for all π = π + π, where π β Z+ .
the celebrated theorem of Mazur and Ulam [10], π΄|π»π (π) is a real-linear isometry in a way similar to [9, Proposition 1]. Next suppose that 0 < π < 1. We define the class π»ππ (π) (0 < π < 1) as the set of all holomorphic functions π on π such that ππ»ππ (π, 0) := β«
Proof. We follow [2, Lemma 2]. π΄ is homogeneous with positive coefficients, so we have, using (15), σ΅¨ π σ΅¨ (log (1 + π‘ σ΅¨σ΅¨σ΅¨π΄π (π₯)σ΅¨σ΅¨σ΅¨)) π (ππ₯) β« π‘π πΊ σ΅¨ π σ΅¨ (log (1 + π‘ σ΅¨σ΅¨σ΅¨π (π₯)σ΅¨σ΅¨σ΅¨)) =β« π (ππ₯) , π‘π πΊ
(17) π β πΆ,
for any π‘ > 0. Letting π‘ β 0+ , we obtain σ΅¨π σ΅¨π σ΅¨ σ΅¨ β« σ΅¨σ΅¨σ΅¨π΄π (π₯)σ΅¨σ΅¨σ΅¨ π (ππ₯) = β« σ΅¨σ΅¨σ΅¨π (π₯)σ΅¨σ΅¨σ΅¨ π (ππ₯) , πΊ πΊ
π β πΆ.
(18)
Next we argue by induction. Let π β N and suppose that (16) holds for π = π + 1, π + 2, . . . , π + π β 1. Then, for any π‘ > 0 and any function π β πΆ, we have β«
πΊ
1 π‘π+π πβ1
σ΅¨ π+π σ΅¨ β β ππ (π‘ σ΅¨σ΅¨σ΅¨π΄π (π₯)σ΅¨σ΅¨σ΅¨) } π (ππ₯) =β«
πΊ
(19) 1 π‘π+π
σ΅¨ π σ΅¨ {(log (1 + π‘ σ΅¨σ΅¨σ΅¨π (π₯)σ΅¨σ΅¨σ΅¨))
πβ1
σ΅¨ π+π σ΅¨ β β ππ (π‘ σ΅¨σ΅¨σ΅¨π (π₯)σ΅¨σ΅¨σ΅¨) } π (ππ₯) , π=0
where ππ are the Taylor coefficients of the function ((log(1 + π₯))/π₯)π at zero. Assume first that π β πΏπ+π (πΊ, π). It is easy to see that the integrand on the right-hand side of (19) converges to ππ |π(π₯)|π+π as π‘ β 0+ ; this integrand is of fixed sign by Lemmas 4 and 5 and is dominated by the function πΆπ |π(π₯)|π+π with some constant πΆπ . By the Lebesgue theorem on dominated convergence, the right-hand side of (19) converges to the integral of ππ |π(π₯)|π+π . Therefore, the lefthand side of (19) has a finite limit and, by the Fatou theorem, the function ππ |π΄π(π₯)|π+π is integrable. Since ππ =ΜΈ 0 for any π by Lemmas 4 and 5, we deduce that π΄π β πΏπ+π (πΊ, π), and repeating the above arguments, we see that the left-hand side of (19) converges to the integral of ππ |π΄π(π₯)|π+π as π‘ β 0+ . Therefore, passing to the limit in (19) as π‘ β 0+ and dividing the result by ππ =ΜΈ 0, we obtain (16) for π = π + π. The case of π΄π β πΏπ+π (πΊ, π) can be considered in a similar way. For π, π΄π β πΏπ+π (πΊ, π), relation (16) with π = π + π is trivial. Proof of Proposition 1. Suppose first that π β₯ 1. Let π, π β π»π (π). We easily confirm that, by utilizing Lemma 2 and
(20)
and define a metric ππ»ππ (π, π) = ππ»ππ (π β π, 0) for π, π β π»ππ (π). If π΄ : ππ (π) β ππ (π) is a surjective isometry and π΄ is 2-homogeneous in the sense that π΄(2π) = 2π΄(π) holds for every π β ππ (π), we confirm that π΄ : π»ππ (π) β π»ππ (π) is also a surjective isometry. For 0 < π < 1, let π, π β π»π (π). We have π΄(π)/2π = π΄(π/2π ) (π β N) since π΄(2π) = 2π΄(π). Then the following equality holds: σ΅¨σ΅¨ π (ππ§) σ΅¨σ΅¨π σ΅¨ σ΅¨ sup σ΅¨σ΅¨σ΅¨ π σ΅¨σ΅¨σ΅¨ ππ (π§) σ΅¨ σ΅¨σ΅¨ 2 ππ 0β€π