kn. Then / given by f(z)=z + £ anz n. (1) n = 2 ... with z = r exp (id),. In. \. Re. dO ^ kn. (2). For fe Vk ... Ifk = 2, the result holds only if co > 0. Received 27 April, 1971.
ON SUCCESSIVE COEFFICIENTS OF FUNCTIONS OF BOUNDED BOUNDARY ROTATION J. W. NOONANf AND D. K. THOMAS 1. Introduction Denote by Vk, for k ^ 2, the class of functions of boundary rotation at most kn. Then / given by
f(z)=z + £ anzn
(1)
n=2
belongs to Vk if and only if/is regular in the open unit disc y, f'(z) # 0 for z e y, and, with z = r exp (id), In \
Re
dO ^ kn.
(2)
For fe Vk we shall be concerned with estimates for \an+J — |flj. We shall prove the following two theorems. THEOREM
1. Let fe Vk and be given by (1). Then, for n^ 1, \\an+1\-\an\\^c(k)n*k-2,
where C(k) is a constant depending only on k. We note that the function f0 defined by fc/2
shows that the index \k—2 in Theorem 1 is best possible. In [4] the first author showed that, for/e Vk, co = lim (1 -r)* fc+1 M(r,f)
(3)
exists, isfinite,and that
lim - g n - .
(4)
With this notation we have THEOREM
2. Letfe Vk and be given by (1). Then
ifk>2
Ifk = 2, the result holds only if co > 0. Received 27 April, 1971. tNRC-NRL Post-doctoral Resident Research Associate. [J. LONDON MATH. SOC. (2), 5 (1972), 656-662]
ON SUCCESSIVE COEFFICIENTS OF FUNCTIONS OF BOUNDED BOUNDARY ROTATION
657
We note that Theorems 1 and 2 are analogues for the class Vk of results of Hayman [3] for circumferentially mean one-valent functions. 2. Proof of Theorem 1 Fom (2), write (z/'(z))' = f'(z)h(z),
with h(0) = 1. Put F(z) = (z(zf (z))\.
F(z)=f'(z)[h2(z)+zh'(z)}.
Then (5)
Since fe Vk) we can write [1]
where st and s2 are normalised starlike functions. Thus, if / is given by (I) and
In Z
~^'|Sl(z)l
|Si(z)|ifc
~* {\h\z)+zH{z)\\dO
(7)
where we have used (5), (6) and the fact that for z ey, |s2(z)|~1 < 4/r for any starlike function. Let 0 < r < 1 be fixed. Then, by a result of Golusin [2], there exists zx such that \zx\ = r and such that Iz-zJIs^z)! < 2r 2 /(l-r 2 ) for all z such that \z\ = r. Thus, in (7) with £, = zu we have
r where we have used the distortion theorem for the function It follows from (2) that In
, w, .
f l+zexp(-i7)
oJ l - z e x p ( - i f ) o where ^ is a function defined on [0,2n] with 271
J \dK0\ < kn. 0
Thus, if
A(z) = l+ f cz-, n= l
(9) gives
2n
1 /• cn = — n J JOUR: 20
...
1 f l+zexp(-i7) 2n , .( dfi(t),
exp(-int)dix(t)
(9) vy
658
J. W. NOONAN AND D. K. THOMAS
and so \cn\ ^ k for n ^ 1. Using this estimate, one easily sees from (9) that 2n
Thus from (8)
Choosing
one obtains for n ^ 1, Ik
+
il-IflJ | < k(k+l)
exp(3)2**(4/3)* fc+1 H**"
We also note that with a suitable choice of |£| = r, we can obtain
for « ^ 5 with C(fc) -> 0 as k -> oo. 3. Proof of
Theorem!
For to > 0, it was shown in [4] that there exists 0O such that
Let ton = (l-pn)ik+1f'{pn exp (i0o)) where p n = 1 - 1/n. We shall need the following lemmas, the first of which was essentially given in [4]. LEMMA
1. Let a> > 0. Then with the above notation,
(i) lim \con\ = co and lim Xn exists, where kn = argo n .
(u)exP(-i0o)fln = — (iii) arg exp ( — i90)an = argco exp(i(An—«0o)) + o(l) as n -> oo. o(l) is uniform in any Stolz angle about the point exp (i0o). LEMMA 2.
Let e > 0 be given. If k > 2 and co > 0, f/iere exists C(e) SMC/J
J(l-rexp(i(0-0o)))/'(r where E = {6 : C(e)(l -r) ^ | 0 - 0 O | < TT}. Proo/. Without loss of generality, we may assume 0O = 0. We denote by A(k) a constant depending only on k. It was shown in [4] that if co > 0, then
ON SUCCESSIVE COEFFICIENTS OF FUNCTIONS OF BOUNDED BOUNDARY ROTATION
659
^z) = z/(l - z ) 2 , where sx is defined in (6). Thus, from (6),
Now with z = r exp (i0), |1 -z\ ^ |0| for r ^ £, and so (11) gives
Let C > 0 be given. Then, from (12) since k > 2,
J
r J \(i-z)f(z)\de^A{k)
r j \e\-*kdd= E E
E
and Lemma 2 now follows on suitably choosing C. LEMMA 3. Ifk>2
and co > 0, then as n -> oo
„„ = ( 1 - 1 W e x p ( - f l o ) a , . 1 + Proo/. Let = co exp (iAn) 2L Cm exp ( — Let e > 0 be given, and choose C(e) and E as in Lemma 2. Then, with z = r exp (id),
1
2n
I* ( 1 -
~2n Jo
-T-f+T-f In J In J ^Ii+I2, say, where £ ' = [0, 27r]\£. It is easily seen that Lemma 2 is valid w i t h / ' replaced by (f)'. Thus, using Lemma 2, we have
Now on E', |1 —z exp (—t0o)| < C(e)(l — r) and so \=r- j \f(z)-cf>'(z)\de.
660
J. W. NOONAN AND D. K. THOMAS
It now follows on using Lemma 1 (iv) that
and so
Choosing r = 1 — 1/n we have from (13), (14), and (15)
Lemma 3 now follows on noting that
C._ 1 -C ll - 2 = YQQ C1 +°0))
as « -> oo.
We now prove Theorem 2 when co > 0. We may assume that A: > 2, since if k = 2 then co > 0 implies that /(2) =
(l-zexP(-i0o))'
in which case |aj = 1 for all n ^ 1 and the result is then trivial. Now, from Lemma 3
n
exp ( -
which on using Lemma 1 (ii) gives
Thus
Also (i) and (iii) of Lemma 1 give argexp(-i0 o )fl n _ 1 = arg exp[i(A n -(«-l)0 o )] + o(l). Combining (16) and (17), we have nik-2
as n -*• oo, which gives Theorem 2 for co > 0
(17)
ON SUCCESSIVE COEFFICIENTS OF FUNCTIONS OF BOUNDED BOUNDARY ROTATION
661
Thus it remains to prove Theorem 2 when co = 0 and k > 2. We first suppose that st defined by (6) is not of the form z/(l - z exp (U))2, A real. Then
where /? < 2. As in the proof of Theorem 1, we obtain from (7) ....
..3 . , .
A{k)
1
Choosing
III = r = we have which gives, since /? < 2 and fc > 2, 0 ri* as « -• oo. We now prove Theorem 2 in the case co = 0, k > 2, and Sl (z)
=
(l-zexp(U))2 *
Without loss of generality, we assume A = 0. Then as in the proof of Lemma 2 we see that, given e > 0, there exists C(e) such that J (1 - r exp (id))f'(r exp (i0))«/0
(18)
where E = {0: C(e)(l - r ) < |0| < n). Let £' = [0,2n]\E. Then for 0 e £' we have |1 - r exp (i0)| < C(e)(l - r ) , and so J |1 -r exp (i0)| \f'(r exp (i0))| d9 ^
2C 2 (E)(1
- r ) 2 M(r,/').
E'
But co = 0 and so, from (3),
M(r,f) = as r -> 1. Thus, I |1—rexp(i0)|
exp
(r "> 1).
Since 1 («+1) a n + ! -»flB = — -
2n
r
(1 - r exp (i0))/'(r exp (i0)) exp (-ind)dd,
(19)
662
ON SUCCESSIVE COEFFICIENTS OF FUNCTIONS OF BOUNDED BOUNDARY ROTATION
(18) and (19) give \(n + \)an + i-nan\
= o(\)n*k-x
as n -> oo. Hence
as n -> oo, and the theorem now follows on using (4). If k = 2 and co = 0, the theorem is false, as is shown by the function fe V2 defined by/'(z) = 1/(1 - z 2 ) . It is clear that co = 0, but (2«-2) | | a 2 n _ 1 | - K , - 2 l | = ~
^
~ "> 1
as n -> oo.
1. D. A. Brannan, "On functions of bounded boundary rotation I ",Proc. Edinburgh Math. Soc, 16 (1968-69), 339-347. 2. G. M. Golusin, " On distortion theorems and coefficients of univalent functions", Mat. Sb., 19 (1946), 183-202. 3. W. K. Hayman, "On successive coefficients of univalent functions ", / . London Math. Soc, 38 (1963), 228-243. 4. J. W. Noonan, " Asymptotic behaviour of functions with bounded boundary rotation ", Trans. Amer. Math. Soc, 164 (1972), 397-410.
U.S. Naval Research Laboratory, Washington, D.C. 20390 University of Maryland, College Park, Maryland, 20742 Present address: Department of Pure Mathematics, University College, Swansea.