Dec 10, 2009 - Paired domination in subdivided star-free graphs. Paired domination in .... connected, cubic, claw-free â γpr(G) ⤠n. 2. (Favaron, Henning 04).
Paired domination in subdivided star-free graphs
Paired domination in subdivided star-free graphs Paul Dorbec Nouveau MdC dans l’´ equipe Combalgo, th` eme Graphes et Applications
December 10th, 2009
Paired domination in subdivided star-free graphs Introduction
Domination: an old problem Problem (middle of 19th century) How many queens are needed to threaten all the squares of a chessboard?
Paired domination in subdivided star-free graphs Introduction
Domination: an old problem Problem (middle of 19th century) How many queens are needed to threaten all the squares of a chessboard?
Paired domination in subdivided star-free graphs Introduction
Definitions How many fire stations must be placed to protect every village?
Paired domination in subdivided star-free graphs Introduction
Definitions How many fire stations must be placed to protect every village? −→ γ
D satisfies : ∀u ∈ V , |N[v ] ∩ D| ≥ 1
set of fire stations = covering = dominating set
Paired domination in subdivided star-free graphs Introduction
Definitions How many tips/recycling centers may be placed without irritating the inhabitants of any village? −→ ρ
D satisfies : ∀u ∈ V , |N[v ] ∩ D| ≥ 1 P satisfies : ∀u ∈ V , |N[v ] ∩ P| ≤ 1
set of tips = packing = error correcting code
Paired domination in subdivided star-free graphs Introduction
Duality : |packing | ≤ |dominating set|
Paired domination in subdivided star-free graphs Introduction
Duality : |packing | ≤ |dominating set|
Paired domination in subdivided star-free graphs Introduction
Duality : |packing | ≤ |dominating set| 1
1
1 1 1
1
1 1
1 1 I
1
1
In particular, max(|packing |) = ρ(G ) ≤ γ(G ) = min(|dominating set|).
I
Therefore, if |packing | = |covering |, then both are best possible: these are perfect codes / efficient dominating sets.
Paired domination in subdivided star-free graphs Introduction
Vizing’s Conjecture Conjecture (Vizing, 1968) Given any graphs G and H, γ(G 2H) ≥ γ(G ) × γ(H) I
The other inequality is generally false: γ(P3 ) = 1 and γ(P3 2 P3 ) = 3.
Paired domination in subdivided star-free graphs Introduction
Vizing’s Conjecture Conjecture (Vizing, 1968) Given any graphs G and H, γ(G 2H) ≥ γ(G ) × γ(H) I
The other inequality is generally false: γ(P3 ) = 1 and γ(P3 2 P3 ) = 3.
I
Proved with a factor 2 by Clark and Suen in 2000 : γ(G 2H) ≥ 21 γ(G ) × γ(H)
I
Proved for many graph classes: trees, cycles, chordal graphs... and in some special cases : G 2 G . . .
I
Many similar inequalities for variants of domination, for different products, etc...
Paired domination in subdivided star-free graphs Paired-domination
Definitions Domination: How many fire stations must be placed to protect every village? I
D satisfies : ∀u ∈ V , |N[v ] ∩ D| ≥ 1 −→ γ
Paired domination in subdivided star-free graphs Paired-domination
Definitions Total domination: What if we also want to protect fire stations? I
D satisfies : ∀u ∈ V , |N[v ] ∩ D| ≥ 1 −→ γ
I
Dt satisfies : ∀u ∈ V , |N(v ) ∩ D| ≥ 1 −→ γt
Paired domination in subdivided star-free graphs Paired-domination
Definitions Paired-domination: What about pairing fire-stations? I
D satisfies : ∀u ∈ V , |N[v ] ∩ D| ≥ 1 −→ γ
I
Dt satisfies : ∀u ∈ V , |N(v ) ∩ D| ≥ 1 −→ γt
I
Dpr dominates G and G [D] has a perfect matching −→ γpr
Paired domination in subdivided star-free graphs Paired-domination Results
Critical case Theorem: [Haynes and Slater (1998)] G connected of order n ≥ 3 ⇒ γpr (G ) ≤ n − 1, with equality iff G = C3 , C5 or a subdivided star ∗ . K1,a c
Paired domination in subdivided star-free graphs Paired-domination Results
Critical case Theorem: [Haynes and Slater (1998)] G connected of order n ≥ 3 ⇒ γpr (G ) ≤ n − 1, with equality iff G = C3 , C5 or a subdivided star ∗ . K1,a I
connected, δ ≥ 2 I I I
I
c
n ≥ 6 ⇒ 32 n (Haynes, Slater 98) n ≥ 10 ⇒ 23 (n − 1) (Henning 07) ` ´ girth ≥ 6 ⇒ 23 n − (δ−1)(δ−2) 2 (Chen, Chee Shiu, Hong Shan 08)
connected, cubic, claw-free ⇒ γpr (G ) ≤ (Favaron, Henning 04)
n 2
Paired domination in subdivided star-free graphs Paired-domination Results
Critical case Theorem: [Haynes and Slater (1998)] G connected of order n ≥ 3 ⇒ γpr (G ) ≤ n − 1, with equality iff G = C3 , C5 or a subdivided star ∗ . K1,a I
connected, δ ≥ 2 I I I
I
c
n ≥ 6 ⇒ 32 n (Haynes, Slater 98) n ≥ 10 ⇒ 23 (n − 1) (Henning 07) ` ´ girth ≥ 6 ⇒ 23 n − (δ−1)(δ−2) 2 (Chen, Chee Shiu, Hong Shan 08)
connected, cubic, claw-free ⇒ γpr (G ) ≤ (Favaron, Henning 04)
n 2
Paired domination in subdivided star-free graphs Paired-domination Results
The bad guys of paired-domination. ∗ A graph G with no induced subdivided star K1,a+2 that satisfies 2(an + 1) γpr (G ) = 2a + 1
Kp+1
a
...
...
...
...
...
...
...
...
...
a
n = p(2a + 1) + 2 γpr (G ) = 2ap + 2
a
Paired domination in subdivided star-free graphs Paired-domination Results
Our results Let G be a connected graph of order n ≥ 2. c
Star-free [D., Gravier, Henning (2006)] : If G contains no star K1,a+2 , (a ≥ 0), then γpr (G ) ≤
All these bounds are tight.
2(an+1) 2a+1
Paired domination in subdivided star-free graphs Paired-domination Results
Our results Let G be a connected graph of order n ≥ 2. c
Star-free [D., Gravier, Henning (2006)] : If G contains no star K1,a+2 , (a ≥ 0), then γpr (G ) ≤
2(an+1) 2a+1
P5 -free [D.,Gravier (2008)] : If G is not C5 and contains no induced P5 , then γpr (G ) ≤
All these bounds are tight.
n 2
+1
Paired domination in subdivided star-free graphs Paired-domination Results
Our results Let G be a connected graph of order n ≥ 2. c
Star-free [D., Gravier, Henning (2006)] : If G contains no star K1,a+2 , (a ≥ 0), then γpr (G ) ≤
2(an+1) 2a+1
P5 -free [D.,Gravier (2008)] : If G is not C5 and contains no induced P5 , then γpr (G ) ≤
n 2
+1
Subdivided star-free [D., Gravier (2009?)] : ∗ If G contains no subdivided star K1,a+2 , (a ≥ 1), then γpr (G ) ≤ All these bounds are tight.
2(an+1) 2a+1
Paired domination in subdivided star-free graphs Paired-domination Proof
Preliminary to the proof
Observation If the vertices of a graph G may be partitioned into 2 sets V1 and V2 in such a way that (|V1 | = n1 , |V2 | = n2 ) 1 +1) γpr (G [V1 ]) ≤ 2(an (induction) 2a+1
γpr (G [V2 ]) ≤
then γpr (G ) ≤
2(an+1) 2a+1 .
2(an2 ) 2a+1
(a little stronger)
Paired domination in subdivided star-free graphs Paired-domination Proof
Proof
( γpr (G ) ≤
2(an+1) 2a+1 )
By minimum counter-example: I
Let a be the smallest integer for which the inequality is false
I
Let G be a minimum counter-example without subd. star of size a + 2.
F
G
u
? ... C1
C2
Ck
Paired domination in subdivided star-free graphs Paired-domination Proof
Proof
( γpr (G ) ≤
2(an+1) 2a+1 )
By minimum counter-example: I
Let a be the smallest integer for which the inequality is false
I
Let G be a minimum counter-example without subd. star of size a + 2.
I
∗ G contains a subdivided star K1,a+1 , let u be its centre.
F
G
u
... C1
C2
Ck
Paired domination in subdivided star-free graphs Paired-domination Proof
Proof
( γpr (G ) ≤
2(an+1) 2a+1 )
By minimum counter-example: I
Let a be the smallest integer for which the inequality is false
I
Let G be a minimum counter-example without subd. star of size a + 2.
I
∗ G contains a subdivided star K1,a+1 , let u be its centre.
I
Let F ⊆ N(u) max s.t. N(F ) = {u}.
u
F
... C1
C2
Ck
Paired domination in subdivided star-free graphs Paired-domination Proof
Proof
( γpr (G ) ≤
2(an+1) 2a+1 )
By minimum counter-example: I
Let a be the smallest integer for which the inequality is false
I
Let G be a minimum counter-example without subd. star of size a + 2.
I
∗ G contains a subdivided star K1,a+1 , let u be its centre.
I
Let F ⊆ N(u) max s.t. N(F ) = {u}.
I
We have |F | ≤ 1
u
F
... C1
C2
Ck
Paired domination in subdivided star-free graphs Paired-domination Proof
Proof
( γpr (G ) ≤
2(an+1) 2a+1 )
By minimum counter-example: I
Let a be the smallest integer for which the inequality is false
I
Let G be a minimum counter-example without subd. star of size a + 2.
I
∗ G contains a subdivided star K1,a+1 , let u be its centre.
I
Let F ⊆ N(u) max s.t. N(F ) = {u}.
I
We have |F | ≤ 1
I
Let C1 , . . . , Ck be the components of G [V \ ({u} ∪ F )]
F
u
... C1
C2
Ck
Paired domination in subdivided star-free graphs Paired-domination Proof
Proof
( γpr (G ) ≤
2(an+1) 2a+1 )
By minimum counter-example: I
Let a be the smallest integer for which the inequality is false
I
Let G be a minimum counter-example without subd. star of size a + 2.
I
∗ G contains a subdivided star K1,a+1 , let u be its centre.
I
Let F ⊆ N(u) max s.t. N(F ) = {u}.
I
We have |F | ≤ 1
I
Let C1 , . . . , Ck be the components of G [V \ ({u} ∪ F )]
I
2 ≤ k ≤ a + 1.
F
u
... C1
C2
Ck
Paired domination in subdivided star-free graphs Paired-domination Proof
Proof
( γpr (G ) ≤
2(an+1) 2a+1 )
By minimum counter-example: I
Let a be the smallest integer for which the inequality is false
I
Let G be a minimum counter-example without subd. star of size a + 2.
I
∗ G contains a subdivided star K1,a+1 , let u be its centre.
I
Let F ⊆ N(u) max s.t. N(F ) = {u}.
I
We have |F | ≤ 1
I
Let C1 , . . . , Ck be the components of G [V \ ({u} ∪ F )]
I
2 ≤ k ≤ a + 1.
F
u
...
I
If ∃ Ci such that γpr (Ci ) ≤
C1 2ani 2a+1
C2
Ck
Paired domination in subdivided star-free graphs Paired-domination Proof
Proof
( γpr (G ) ≤
2(an+1) 2a+1 )
By minimum counter-example: I
Let a be the smallest integer for which the inequality is false
I
Let G be a minimum counter-example without subd. star of size a + 2.
I
∗ G contains a subdivided star K1,a+1 , let u be its centre.
I
Let F ⊆ N(u) max s.t. N(F ) = {u}.
I
We have |F | ≤ 1
I
Let C1 , . . . , Ck be the components of G [V \ ({u} ∪ F )]
I
2 ≤ k ≤ a + 1.
F
u
...
I
If ∃ Ci such that γpr (Ci ) ≤
C1 2ani 2a+1
: OK
C2
Ck
Paired domination in subdivided star-free graphs Paired-domination Proof
Proof
( γpr (G ) ≤
2(an+1) 2a+1 )
By minimum counter-example: I
Let a be the smallest integer for which the inequality is false
I
Let G be a minimum counter-example without subd. star of size a + 2.
I
∗ G contains a subdivided star K1,a+1 , let u be its centre.
I
Let F ⊆ N(u) max s.t. N(F ) = {u}.
I
We have |F | ≤ 1
I
Let C1 , . . . , Ck be the components of G [V \ ({u} ∪ F )]
I
2 ≤ k ≤ a + 1.
F
u
...
I I
If ∃ Ci such that γpr (Ci ) ≤
C1 2ani 2a+1
Ck
: OK
2(a(n−n1 )+1) 2a+1
Otherwise, γpr (G [V \ C1 ]) ≤ 1) → γpr (G [V \ C1 ]) ≤ 2a(n−n 2 2a+1
C2
=
P
γpr (Ci ) + E, with E < 2
Paired domination in subdivided star-free graphs Conclusion Guess what this is!
Thank you for your attention.
Paired domination in subdivided star-free graphs Conclusion Guess what this is!
Thank you for your attention.
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