M1 f (~n)}. We then have Var M1 f
=
d XX
~ n∈Zd
=
|M1 f (~n) − M1 f (~n + ~ej )|
j=1
d X X
X
M1 f (~n) − M1 f (~n + ~ej ) +
d X X
X
Arn~ f (~n) − Arn~ +1 f (~n + ~ej )
j=1 l∈Ij ~ n∈l∩Xj−
≤
d X X
X
M1 f (~n + ~ej ) − M1 f (~n)
j=1 l∈Ij ~ n∈l∩Xj+
j=1 l∈Ij ~ n∈l∩Xj− 6
(3.1)
+
d X X
X
Arn~ +~ej f (~n + ~ej ) − Arn~ +~ej +1 f (~n).
j=1 l∈Ij ~ n∈l∩Xj+
Fixed a point p~ = (p1 , p2 , . . . , pd ) ∈ Zd , we want to evaluate the maximal contribution of f (~ p) to the right-hand side of (3.1). 3.2. Auxiliary results. We now prove the following lemma of arithmetic character, which will be particularly useful in the rest of the proof. Lemma 4. If d ≥ 1, then N1,d (k)2 > N1,d (k + 1)N1,d (k − 1) ∀ k ≥ 1.
(3.2)
Proof. We prove this via induction. For d = 1 we have that N1,1 (k) = 2k + 1, therefore N1,1 (k)2 = 4k 2 + 4k + 1 > (2k + 3)(2k − 1) = N1,1 (k + 1)N1,1 (k − 1). Since N1,d (k) = {(x1 , . . . , xd ) ∈ Zd ; |x1 | + · · · + |xd | ≤ k} , fixing the value of the last variable, we can verify that k−1 X N1,d−1 (j). (3.3) N1,d (k) = N1,d−1 (k) + 2 j=0
Now, let us assume that the result is true for d, i.e.
N1,d (k)2 > N1,d (k + 1)N1,d (k − 1) ∀ k ≥ 1.
(3.4)
We want to prove that this implies that the result is also true for d + 1. For simplicity we denote g(k) := N1,d (k) and f (k) := N1,d+1 (k) for all k ≥ 0. Thus by (3.4) we have that g(2) g(k) g(k + 1) g(1) > > ··· > > > ... g(0) g(1) g(k − 1) g(k) and by (3.3) we have that f (k) = g(k) + 2
k−1 X
g(j)
∀ k ≥ 0.
j=0
The latter implies that
f (k + 1) − f (k) = g(k + 1) + g(k)
∀ k ≥ 0.
Therefore, by (3.5), we obtain that g(k + 1) g(k + 2) + g(k + 1) > g(k) g(k + 1) + g(k) and
Pk g(k + 1) + 2 j=1 g(j) g(k + 1) . > Pk g(k) g(k) + 2 j=1 g(j − 1)
Combining these inequalities we arrive at Pk g(k + 1) + 2 j=1 g(j) f (k + 1) g(k + 2) + g(k + 1) f (k + 2) − f (k + 1) g(k + 1) ≥ > = , > Pk f (k) g(k) g(k + 1) + g(k) f (k + 1) − f (k) g(k) + 2 j=1 g(j − 1)
and hence
f (k + 2) − f (k + 1) f (k + 1) − f (k) > . f (k) f (k + 1) 7
(3.5)
This implies that f (k + 1) f (k + 2) > ∀ k ≥ 0, f (k) f (k + 1) which establishes the desired result.
Corollary 5. If d ≥ 1, we have that 1 1 1 1 − > − ∀ k ≥ 0. N1,d (k) N1,d (k + 1) N1,d (k + 1) N1,d (k + 2)
(3.6)
Proof. We notice that (3.6) is equivalent to N1,d (k + 1) N1,d (k + 1) + > 2. N1,d (k) N1,d (k + 2) This follows from Lemma 4 and the arithmetic mean - geometric mean inequality because N1,d (k + 2) N1,d (k + 1) N1,d (k + 1) N1,d (k + 1) + > + ≥ 2. N1,d (k) N1,d (k + 2) N1,d (k + 1) N1,d (k + 2) 3.3. Proof of Theorem 2. Let us simplify notation by writing N1 (k) := N1,d (k). Given 1 ≤ j ≤ d, using Corollary 5 we make the following observations. Case 1: If ~n ∈ Xj− and nj ≥ pj . In this situation we have that the contribution of f (~ p) to Arn~ f (~n) − 1 Ar~n +1 f (~n + ~ej ) is non-positive (if |~n − ~ p|1 > r~n ) or N1 (r − N1 (r1n~ +1) (if |~n − ~p|1 ≤ r~n ). In the second case n ~) we have 1 1 1 1 − ≤ − N1 (r~n ) N1 (r~n + 1) N1 (|~n − ~p|1 ) N1 (|~n − p~|1 + 1) 1 1 = − . N1 (|~n − ~p|1 ) N (|~n + ~ej − p~|1 )
The equality is attained if and only if r~n = |~n − p~|1 . Case 2: If ~n ∈ Xj+ and nj ≥ pj . Now we have that the contribution of f (~ p) to Arn~ +~ej f (~n +~ej )−Arn~ +~ej +1 f (~n) 1 (if |~ n + ~ej − ~p|1 ≤ r~n+~ej ). In the second is non-positive (if |~n + ~ej − p~|1 > r~n+~ej ) or N1 (r1n~ +~e ) − N1 (rn~ +~ e +1) j
j
case we have 1 1 − N1 (r~n+~ej ) N1 (r~n+~ej + 1)
≤ = < =
1 1 − N1 (|~n + ~ej − ~p|1 ) N1 (|~n + ~ej − p~|1 + 1) 1 1 − N1 (|~n − p~|1 + 1) N1 (|~n − ~p|1 + 2) 1 1 − N1 (|~n − p~|1 ) N1 (|~n − ~p|1 + 1) 1 1 − . N1 (|~n − p~|1 ) N (|~n + ~ej − ~p|1 )
Case 3: If ~n ∈ Xj− and nj < pj . In this situation we have that the contribution of f (~ p) to Arn~ f (~n) − 1 − N1 (r1n~ +1) (if |~n − ~p|1 ≤ r~n ). In the second case Ar~n +1 f (~n + ~ej ) is non-positive (if |~n − ~ p|1 > r~n ) or N1 (r n ~) we have 1 1 1 1 − ≤ − N1 (r~n ) N1 (r~n + 1) N1 (|~ p − ~n|1 ) N1 (|~ p − ~n|1 + 1) 1 1 − . < N1 (|~ p − ~n − ~ej |1 ) N1 (|~ p − ~n|1 ) 8
Case 4: If ~n ∈ Xj+ and nj < pj . Now we have that the contribution of f (~ p) to Arn~ +~ej f (~n +~ej )−Arn~ +~ej +1 f (~n) is non-positive (if |~ p − ~n − ~ej |1 > r~n+~ej ) or
1 N1 (rn ~ +~ ej )
−
1 N1 (rn ~ +~ ej +1)
(if |~ p − ~n − ~ej |1 ≤ r~n+~ej ). In the second
case we have 1 1 − N1 (r~n+~ej ) N1 (r~n+~ej + 1)
≤ =
1 1 − N1 (|~ p − ~n − ~ej |1 ) N1 (~ p − ~n − ~ej |1 + 1) 1 1 − . N1 (|~ p − ~n − ~ej |1 ) N1 (|~ p − ~n|1 )
The equality is achieved if and only if r~n+~ej = |~ p − ~n − ~ej |1 .
Conclusion: Given a line l in the lattice, we define the distance from p~ to l by d(l, p~) = min{|m ~ − p~|1 ; m ~ ∈ l}. If the direction of l is the same as the direction of ~ej , by intersecting l with the hyperplane Hj = {~z ∈ Zd ; zj = pj } we obtain the point that realizes the distance from p to l. By the previous analysis we have that the contribution of f (~ p) to X Ar~n f (~n) − Arn~ +1 f (~n + ~ej ) + ~ n∈l∩Xj−
X
Arn~ +~ej f (~n + ~ej ) − Arn~ +~ej +1 f (~n)
~ n∈l∩Xj+
is less than or equal to
2 . (3.7) N1,d (d(l, p~)) As p belongs to d lines of the lattice, given k ∈ N there exist d(N1,d−1 (k) − N1,d−1 (k − 1)) lines such that
d(l, ~p) = k. Thus the contribution of f (~ p) to the right-hand side of (3.1) is less than or equal to X 2d(N1,d−1 (k) − N1,d−1 (k − 1)) , 2d + N1,d (k) k≥1
and as a consequence of this we obtain the desired inequality.
If f is a delta function, then there exist ~y ∈ Zd and k ∈ R such that f (~y) = k and f (~x) = 0 ∀ ~x ∈ Zd \ {y}. Considering the contribution of |f (~y)| to a line l in the lattice Zd we have equality in (3.7), and hence in (1.13). On the other hand, let us assume that f : Zd → R is a nonnegative function that verifies the equality in (1.13). We define P = {~t ∈ Zd ; f (~t) 6= 0} and then X 2d(N1,d−1 (k) − N1,d−1 (k − 1)) X Var M1 f = 2d + f (~t). N1,d (k) k≥1
~ t∈P
Therefore, given ~s = (s1 , s2 , . . . , sd ) ∈ P and a line l in the lattice, the contribution of f (~s) to l in (3.7) 2 u ∈ P \ {~s}, the contribution of f (~u) to must be N1,d (d(l,~ s)) by the previous analysis. Then, if there exists ~ 2 l in (3.1) must also be N1,d (d(l,~ u)) . Assume without loss of generality that sd > ud and consider the line l = {(s1 , s2 , . . . , sn−1 , x); x ∈ Z}. As we have equality in (1.13), given ~n ∈ l such that nd ≥ sd , we need to
have that ~n ∈ Xj− and |~n − ~s|1 = r~n = |~n − ~u|1 , which gives us a contradiction. Thus f must be a delta function. 9
4. Proof of Theorem 3 4.1. Preliminaries. As before we start noticing that, since f ∈ ℓ1 (Zd ), for each ~n ∈ Zd there exist r~n ∈ R+ ff (~n) = Ar f (c~n ), where Qr = {m ∈ Zd ; |m|∞ ≤ r~n } = and c~n ∈ Rd such that ~n ∈ c~n + Q(r~n ) and M n ~
n ~
{m ∈ Zd , max{|m1 |, . . . , |md |} ≤ r~n }. We now introduce the local maxima and minima of a discrete function g : Z → R.1 We say that an interval [n, m] is a string of local maxima of g if g(n − 1) < g(n) = . . . = g(m) > g(m + 1). If n = −∞ or m = ∞ (but not both simultaneously) we modify the definition accordingly, eliminating one of the inequalities. The rightmost point m of such a string is a right local maximum of g, while the leftmost point n is a left local maximum of g. We define string of local minima, right local minimum and left local minimum analogously. Given a line l in the lattice Zd parallel to ~ed there exists n′ ∈ Zd−1 such that l = {(n′ , m); m ∈ Z}. Let ff (n′ , x) is not constant as function of x (otherwise the variation of the maximal function us assume that M
+ − + over this line will be zero). Let {[a− j , aj ]}j∈Z and {[bj , bj ]}j∈Z be the ordered strings of local maxima and ′ ff (n , x) (we allow the possibilities of a− or b− = −∞ and a+ or b+ = ∞), i.e. local minima of M j
j
j
j
+ − + − + − + − + − + . . . < a− −1 ≤ a−1 < b−1 ≤ b−1 < a0 ≤ a0 < b0 ≤ b0 < a1 ≤ a1 < b1 ≤ b1 < . . .
(4.1)
This sequence may terminate in one or both sides and we adjust the notation and the proof below accordingly. ff (~n) → 0 as |~n|∞ → ∞, therefore, if the Note that we have at least one string of local maxima since M
sequence terminates in one or both sides, it must terminate in a string of local maxima. The variation of the maximal function in l is given by X X ff (n′ , a+ ) − M ff (n′ , b− ) ≤ 2 2 M Ar(n′ ,a+ ) f (c(n′ ,a+ ) ) − Ar j j j∈Z
j
j∈Z
j
+ − + +|aj −bj | (n′ ,a ) j
f (c(n′ ,a+ ) ). j
(4.2)
We now prove an auxiliary lemma.
Lemma 6. Given ~q ∈ Zd and a line l in the lattice Zd . There exists at most one string of local maxima of ff in l such that there exists ~n in the string whose contribution of f (~q) to Ar f (c~n ) is positive. M n ~
Proof. Assume without loss of generality that l = {(m1 , m2 , . . . , md−1 , x); x ∈ Z} = {(m′ , x); x ∈ Z}. ff in l Consider a string of local maxima of M Let
ff (m′ , a − 1) < M ff (m′ , a) = . . . = M ff (m′ , a + n) > M ff (m′ , a + n + 1). M
(4.3)
ff (m′ , a + i) = Ar ′ M f (c(m′ ,a+i) ) ∀ 0 ≤ i ≤ n. (m ,a+i)
Given ~q = (q1 , q2 , . . . , qd ) ∈ Zd , a necessary condition for the contribution of f (~q) to Ar(m′ ,a+i) f (c(m′ ,a+i) ) to be positive for some i is that a − 1 < qd < a + n + 1 (otherwise this would violate one of the endpoint inequalities in (4.3)). The result follows from this observation. 4.2. Proof of Theorem 3. Given p~ ∈ Zd and a line l in the lattice Zd , we define d(l, ~p) = min{|~ p− m| ~ ∞; m ~ ∈ l} and d(l, ~p)+ = max{1, d(l, ~ p)}. As consequence of Lemma 6, given p~ = (p1 , p2 , . . . , pd−1 , pd ) ∈ Zd and a line l = {(n1 , n2 , . . . , nd−1 , x) ∈ Zd ; x ∈ Z} such that {i ∈ {1, 2, . . . , d − 1}; |ni − pi | = d(l, p~)} = j, the 1The local extrema are defined slightly differently in [3, 5], but used with the meaning stated here. 10
contribution of f (~ p) to the right-hand side of (4.2) is less than or equal to 2 (d(l, p~) + 1)j (d(l, ~p))d−j +
.
(4.4)
In fact, if an ℓ∞ -cube contains ~ p and a point in l then it must have side at least d(l, p~), and it must contain (d(l, p~) + 1) lattice points in each direction ~ei for i such that |ni − pi | = d(l, ~p). In the other d − j directions the cube contains at least d(l, p~) lattice points. This leads to (4.4). If equality in (4.4) is attained for a point p~ and a line l, then there is a point ~q ∈ l that realizes the distance to p~, belongs to a string of local maxima of l, and such that p~ ∈ cq~ + Q(rq~). Moreover, this string of local maxima must be unique, otherwise f (~ p) would also have a negative contribution coming from a string ff (~ ff (~n) for all ~n ∈ l. If we fix a point ~p and of minimum in (4.2). In particular this implies that M p) ≥ M ff (~ ff (~n) for all ~n ∈ Zd . assume that equality in (4.4) is attained for all lines l in our lattice, then M p) ≥ M
Therefore, as p~ belong to d lines of the lattice Zd , and given k ∈ N and j ∈ {1, 2, . . . , d − 1} there d−1−j exist 2j d−1 lines l = {(n1 , n2 , . . . , nd−1 , x); x ∈ Z} such that d(l, p~) = k and {i ∈ j (2(k − 1) + 1) {1, 2, d . . . , d − 1}; |ni − pi | = k} = j, the contribution of f (~ p) to the variation of the maximal function in Zd is less than or equal to
2d + d
2 d−1 (2k − 1)d−1−j 2 (k + 1)j k d−j j j=1
X X d−1
k≥1
= 2d +
j
X 2d d−1 X d − 1 2 j 2k − 1 d−1−j k j=1 k+1 k j
k≥1
= 2d +
X 2d
k≥1
k
2 2k − 1 + k+1 k
d−1
−
2k − 1 k
d−1 !
.
This concludes the proof of (1.14). If f is a delta function, with f (~n) = 0 for all n ∈ Zd \ {~ p} for some p ∈ Zd , it is easy to see that we have equality in (4.4) for the contribution of |f (~ p)| to all lines l, which implies equality in (1.14). On the other d hand, let us assume that f : Z → R is a nonnegative function that verifies the equality in (1.14). We define P = {~t ∈ Zd ; f (~t) 6= 0} and thus d−1 d−1 ! X X 2d 2 2k − 1 2k − 1 ff = 2d + Var M − + f (t). k k+1 k k t∈P
k≥1
d
Then, given ~s ∈ P , if there exists ~u ∈ P \ {~s}, we consider a line l in the lattice Z such that ~s ∈ l and ~u ∈ / l. ff (~s) = f (~s) belongs to the unique string of local maxima of M ff The contribution of f (~s) to l must be 2, M
in l and the right-hand side of (4.2) must be 2f (~s), by the previous analysis. Therefore the contribution of f (~u) to the line l is 0 and then f (~u) does not provide the maximum contribution as predicted in (4.4), hence (1.14) cannot attained. We conclude that f must be a delta function. Acknowledgents I am deeply grateful to my advisor Emanuel Carneiro for encouraging me to work on this problem, for all the fruitful discussions and for his guidance throughout the preparation of this paper. I would like to thank Renan Finder and Esteban Arreaga for all the interesting discussions related to the proof of Lemma 4. I 11
also want to thank Mateus Sousa for a careful review of this paper. The author also acknowledges support from CAPES-Brazil. References [1] J. M. Aldaz, L Colzani and J. P´ erez L´ azaro., Optimal bounds on the modulus of continuity of the uncentered HardyLittlewood maximal function, J. Geom. Anal. 22 (2012), 132–167. [2] J. M. Aldaz and J. P´ erez L´ azaro, Functions of bounded variation, the derivative of the one dimensional maximal function, and applications to inequalities, Trans. Amer. Math. Soc. 359 (2007), no. 5, 2443–2461. [3] J. Bober, E. Carneiro, K. Hughes and L. B. Pierce, On a discrete version of Tanaka’s theorem for maximal functions, Proc. Amer. Math. Soc. 140 (2012), 1669–1680. [4] E. Carneiro, R. Finder and M. Sousa, On the variation of maximal operators of convolution type II, preprint at http://arxiv.org/abs/1512.02715v1. [5] E. Carneiro and K. Hughes, On the endpoint regularity of discrete maximal operators, Math. Res. Lett. 19, no. 6 (2012), 1245–1262. [6] E. Carneiro and J. Madrid, Derivative bounds for fractional maximal functions, Trans. Amer. Math. Soc., to appear. [7] E. Carneiro and D. Moreira, On the regularity of maximal operators, Proc. Amer. Math. Soc. 136 (2008), no. 12, 4395–4404. [8] E. Carneiro and B. F. Svaiter, On the variation of maximal operators of convolution type, J. Funct. Anal. 265 (2013), 837–865. [9] P. Hajlasz and J. Maly, On approximate differentiability of the maximal function, Proc. Amer. Math. Soc. 138 (2010), 165–174. [10] P. Hajlasz and J. Onninen, On boundedness of maximal functions in Sobolev spaces, Ann. Acad. Sci. Fenn. Math. 29 (2004), no. 1, 167–176. [11] J. Kinnunen, The Hardy-Littlewood maximal function of a Sobolev function, Israel J. Math. 100 (1997), 117–124. [12] J. Kinnunen and P. Lindqvist, The derivative of the maximal function, J. Reine Angew. Math. 503 (1998), 161–167. [13] J. Kinnunen and E. Saksman, Regularity of the fractional maximal function, Bull. London Math. Soc. 35 (2003), no. 4, 529–535. [14] O. Kurka, On the variation of the Hardy-Littlewood maximal function, Ann. Acad. Sci. Fenn. Math. 40 (2015), 109–133. [15] S. Lang, Algebraic number theory, Addison-Wesley Publishing Co., Inc. (1970). [16] H. Luiro, Continuity of the maximal operator in Sobolev spaces, Proc. Amer. Math. Soc. 135 (2007), no. 1, 243–251. [17] S.
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http://arxiv.org/abs/1410.0588 [18] H. Tanaka, A remark on the derivative of the one-dimensional Hardy-Littlewood maximal function, Bull. Austral. Math. Soc. 65 (2002), no. 2, 253–258. [19] F. Temur, On regularity of the discrete Hardy-Littlewood maximal function, preprint at http://arxiv.org/abs/1303.3993. ´ tica Pura e Aplicada, Estrada Dona Castorina 110, Rio de Janeiro - RJ, Brazil, IMPA - Instituto de Matema 22460-320. E-mail address: [email protected]
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