Skorokhod Embeddings In Bounded Time - Philipp Strack

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Feb 5, 2011 - time for the Brownian motion with drift Xt = κt+Wt: Given a probability measure µ ..... than T < ∞. We can use the reflection principle to get that.
Skorokhod Embeddings In Bounded Time Stefan Ankirchner ∗ Institute for Applied Mathematics University of Bonn Endenicher Allee 60 D-53115 Bonn [email protected] Philipp Strack† Bonn Graduate School of Economics University of Bonn Lenn´estr. 43 D-53115 Bonn [email protected] February 5, 2011

Abstract This article deals with the Skorokhod embedding problem in bounded time for the Brownian motion with drift Xt = κt+Wt : Given a probability measure µ we aim at finding a stopping time τ such that the law of Xτ is µ, and τ is almost surely smaller than some given fixed time horizon T > 0. We provide necessary and sufficient conditions on the distribution µ for the existence of such bounded stopping times.

Introduction The problem of finding a stopping time τ such that a Brownian motion stopped at τ has a given centered probability distribution µ, i.e. µ ∼ Wτ , is known as Skorokhod embedding problem (SEP). After its initial formulation by Skorokhod in 1961 ([7]) many solutions have been derived 1 . This article aims at finding conditions guaranteeing the existence of stopping times τ that are bounded by some real number T < ∞, and embed a given ∗ Financial support by the German Research Foundation (DFG) through the Hausdorff Center for Mathematics is gratefully acknowledged. † Financial support by the German Research Foundation (DFG) through the Bonn Graduate School of Economics is gratefully acknowledged. 1 For an overview we recommend the survey article by Jan Obloj [5].

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distribution in a Brownian motion, possibly with drift. So far this question has not been analyzed in the literature. It is of particular economic interest because it arises naturally in the context of mixed strategy Nash equilibria in dynamic games without observability. To illustrate this point, consider a two player game where both players stop a privately observed Brownian motion. At some fixed time T both players are evaluated and the player who stopped his Brownian motion at a higher value wins a pre-specified prize. A strategy of a player is a stopping time which is bounded by T (see [6]). The approach of solving the Skorokhod embedding problem presented by Bass in [2], and in more detail in the forthcoming book [3], turns out to be extremely suitable for providing conditions under which a distribution can be embedded in bounded time. Bass’s method starts with the representation of a random variable with distribution µ as a stochastic integral with respect to a Brownian motion on the interval [0, 1]. Then the time of the representing integral process is modified such that the resulting process is a Brownian motion up to some stopping time τ solving the SEP in a weak sense. The time change is governed by an ODE dictating the time speed along every integral path. This allows to derive analytic criteria for the rate of time change to be bounded, and hence the SEP to be solvable in bounded time. When dealing with a Brownian motion with drift, Bass’s method can be generalized by appealing to non-linear integral representation as provided by Backward Stochastic Differential Equations (BSDE) (see [1]). The solution process of a BSDE with quadratic growth generator f (z) = −κz 2 , κ ∈ R, can be time-changed in such a way that one obtains a Brownian motion with drift κ. As in the case without drift this allows, in a first step, to derive a solution of the SEP in a weak sense. Again the link between the time-change and the Brownian paths driving the BSDE is established via an ODE. On the one hand this enables one to solve the SEP in the classical sense, and on the other hand it provides analytic criteria for a distribution to be embeddable in bounded time. Here is an outline of the following presentation: We start in Section 1 by showing how the small ball asymptotics of a Brownian motion, possibly with drift, entail necessary conditions for the SEP to be solvable in bounded time. In Section 2 we give a brief description of Bass’s method and its generalization using BSDE techniques. A collection of necessary conditions for the SEP to be solvable in bounded time will be given in Section 3. Finally, in Section 4, we briefly describe a contest game with a Nash equilibrium distribution that, appealing to the results of Section 3, can be embedded in a Brownian motion with drift in bounded time.

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A Necessary Condition on Small Ball Probabilities

Let (Wt )t∈R+ be a Brownian motion on a probability space (Ω, F, P ), and denote by (Ft ) the filtration generated by W and extended by the P -null sets of F.

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We denote by Xt = Wt + κt, κ ∈ R, the Brownian motion with drift. Let µ be R a probability measure on R, of finite variance x2 dµ(x) = v < ∞ which fulfills the condition Z xdµ(x) = 0 if κ = 0 (1) R

or

Z

e−2κx dµ(x) = 1

if κ 6= 0.

(2)

R

The conditions (1) and (2) are necessary for µ to be embeddable in bounded time. To prove this observe first that (Wt )t∈R+ respectively (e−2κXt )t∈R+ is a martingale. If τ embeds µ in bounded time, then, by Doob’s optional stopR ping theorem,R we have 0 = W0 = E(Wτ ) = R xdµ(x) and 1 = e−2κX0 = E(e−2κXτ ) = R e−2κx dµ(x). We denote by F : R → [0, 1], F (x) = µ((−∞, x]), the cumulative distribution function associated with µ. Suppose that a distribution has a hole, i.e. there exists an open interval such that the distribution has mass both to the left and to the right of the interval, but no mass on the interval itself. To embed a distribution with a hole, the process X has to enter the no mass interval with some positive probability. Once in the interval, there is a positive probability that the process will not leave it during a finite time period of fixed length. Therefore, distributions with holes can not be embedded with bounded stopping times. We can develop this argument further. If a distribution can be embedded in bounded time, say before T , then the mass the distribution assigns to each interval can be estimated from below against the probability for the process X to enter the interval and then to stay there up to time T . We can thus derive a necessary condition on the asymptotic small ball probabilities of distributions that are embeddable in bounded time. Theorem 1. If a distribution with distribution function F can be embedded before time T > 0, then for all x ∈ R with F (x) ∈ / {0, 1} it must hold that lim sup −ε2 ln(F (x + ε) − F (x − ε)) ≤ ε↓0

π2 T. 8

(3)

Proof. Throughout we denote by Bε (x) the open ball around x of radius ε > 0. The probability for the absolute value of the Brownian motion W to stay within the ball Bε (0) up to any time t ≥ 0 is given by P ( sup |Ws | < ε) = s∈[0,T ]

∞ (2n+1)2 π 2 4X 1 e− 8ε2 T (−1)n π n=0 2n + 1

(4)

(see Sec. 5, Ch. X in [4]). From (4) we obtain the following lower bound P ( sup |Ws | < ε) ≥ s∈[0,T ]

3

4 − π22 T e 8ε . π

(5)

From (5) we may also derive a lower bound for the absolute value of the Brownian motion with drift to stay within Bε (0). To this end let Q be the probability measure on FT with density dQ dP = E(−κW )T . Girsanov’s theorem implies that Xt = Wt + κt is a Brownian motion with respect to Q. Thus, using (5) under Q, we obtain i h κ2 P ( sup |Xs | < ε) = E Q eκWT + 2 T 1{sups∈[0,T ] |Xs | t}, if t < S, τt = 1, else. By the Dambis-Dubins-Schwarz Theorem the time-changed process Bt = Mτt is a Brownian motion on [0, S]. By extending the probability space if necessary and using a Brownian motion independent of W , one may extend B to a Brownian motion on R+ . From (7) we immediately obtain that the Brownian motion B with drift κ, starting in Y0 and stopped at time S, has the distribution µ. Indeed, Z 1 Z 1 BS + κS + Y0 = Zs dWs + κ Zs2 ds + Y0 = ξ. 0

0

We proceed by recalling how one can explicitly construct solutions of the BSDE (7). To this end we will distinguish between the no-drift case κ = 0, and the case κ 6= 0. For κ = 0, Equation (7) simplifies to the stochastic integral representation of ξ. In particular, if ξ is integrable, then (7) possesses a unique solution and

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it must hold Yt = E[ξ|Ft ]. Moreover, the Markov property of W yields that Yt = G(t, Wt ), where G(t, x) = E[g(x + W1 − Wt )],

t ∈ [0, 1], x ∈ R.

It is straightforward to show that G ∈ C 1,2 ((0, 1) × R). To simplify notation we use in the following the abbreviation Gx (t, x) = ∂G ∂x (t, x). Appealing to Ito’s formula one can show that the control process Z is given by Zt = Gx (t, Wt ). We next turn to the case κ 6= 0. For the construction of a solution of (7) in this case, we need to assume that e−2κξ is integrable. First define Nt = E[e−2κξ |Ft ] and observe that Nt = H(t, Wt ), where h i H(t, x) = E e−2κg(x+W1 −Wt ) , t ∈ [0, 1], x ∈ R. Rt One can show that H ∈ C 1,2 ((0, 1) × R) and that Nt = N0 + 0 Hx (t, Ws )dWs . Straightforward calculations yield that a solution of (7) is given by Yt = −

1 ln H(t, Wt ), 2κ

t ∈ [0, 1],

1 Hx (t, Wt ) , 2κ H(t, Wt )

t ∈ (0, 1),

and Zt = −

(see Lemma 2.2. in [1]). Thus the logarithmic derivative of H, defined by h(t, x) = −

1 Hx (t, x) , 2κ H(t, x)

t ∈ (0, 1), x ∈ R,

determines the speed of the time change and a forteriori whether a distribution 1 is embeddable in bounded time. Finally, observe that Y0 = − 2κ ln E[e−2κξ ]. Therefore, if condition (2) is satisfied, then Y0 = 0.

Strong solution One can establish a functional dependence of the family of stopping times (τt ) and the Brownian motion B. Indeed, if κ = 0, then it holds true that ∂τt 1 = 2 , −1 ∂t Gx (τt , G (τt , Bt ))

0 < t < S,

(8)

(see Proposition 3 in [2]). If κ 6= 0, then ∂τt 1 = 2 , ∂t h (τt , H −1 (τt , exp(−2κ(Bt + κt + Y0 )))) 7

0 < t < S,

(9)

(see Thm 2.3 in [1]). With the functional dependency of the time change on the Brownian paths (8) resp. (9) we may construct an embedding stopping time for any Brownian motion. Take for instance the Brownian motion W and define, for all ω ∈ Ω, σt (ω) as the solution of the differential equation (8) resp. (9) with B(ω) replaced by W (ω), and initial condition σ0 (ω) = 0. Then, T = limt↑1 σt−1 is a stopping time with respect to (Ft ). Moreover, the pair (T, W ) has the same distribution as (S, B), which implies that the distribution of the stopped process WT + κT + Y0 is equal to µ.

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Sufficient criteria for embedding times to be bounded

Throughout this section let µ be a distribution such that (1) resp. (2) is satisfied. Moreover, in view of Corollary 1, it is no restriction to further assume that g = F −1 ◦ Φ is strictly increasing.

3.1

Analytical conditions for the solution to be bounded

The stopping time S of the weak solution constructed in Section 2 satisfies, for κ = 0, Z 1 S= G2x (t, Wt )dt, 0

and for κ 6= 0, Z S=

1

h2 (t, Wt )dt.

0

Thus the stopping time S,Rand hence any strong counterpart, is bounded if and R1 1 only if the functions x 7→ 0 G2x (t, x)dt resp. x 7→ 0 h2 (t, x)dt are bounded in R. In particular, the distribution µ is embeddable in bounded time if Gx resp. h is bounded. Suppose that g is absolutely continuous and denote by g 0 its weak derivative, i.e. Z y g(y) − g(x) = g 0 (z)dz . x

Note that in this case we have Gx (t, x) = Z √ g 0 (z)ϕ1−t (x − z)dz ≤ T , R

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R R

g 0 (z)ϕ1−t (x − z)dz. Therefore, if x ∈ R, t ∈ [0, 1),

then the distribution µ can be embedded before time T in the Brownian motion without drift. Similarly, the derivative of H with respect to x satisfies Z Hx (x, t) = −2κg 0 (z) exp(−2κg(z))ϕ1−t (x − z)dz. R

Consequently, if we have R 0 g (z) exp(−2κg(z))ϕ1−t (x − z)dz √ RR ≤ T, exp(−2κg(z))ϕ1−t (x − z)dz R

x ∈ R, t ∈ [0, 1),

then the distribution µ can be embedded before T in the Brownian motion with drift, Bt = κt + Wt .

3.2

An easy-to-check Lipschitz condition

The next theorem states that a distribution is embeddable in bounded time if the function g = F −1 ◦ Φ is Lipschitz continuous. In particular, the Lipschitz constant provides an upper bound for the stopping time. Theorem 2. Suppose that g is Lipschitz continuous with Lipschitz constant √ T . Then µ can be embedded in Bt = Wt + κt before T . Proof. Because g is Lipschitz continuous it is also absolutely continuous. Due√to the Lipschitz continuity of g, we have that the weak derivative satisfies g 0 ≤ T almost everywhere. We distinguish two cases. In the case of a BM without drift (κ = 0) we have Z √ Z √ g 0 (z)ϕ1−t (x − z)dz ≤ T ϕ1−t (x − z)dz = T , R

R

and in the case of a BM with drift κ 6= 0: R 0 R g (z) exp(−2κg(z))ϕ1−t (x − z)dz √ R exp(−2κg(z))ϕ1−t (x − z)dz √ RR ≤ TR = T. exp(−2κg(z))ϕ1−t (x − z)dz exp(−2κg(z))ϕ1−t (x − z)dz R R

Notice that g is Lipschitz continuous if and only if the ratio of the densities ϕ ◦ Φ−1 (α) f ◦ F −1 (α)

(10)

is bounded at every quantile α ∈ [0, 1]. For every distribution with bounded support this condition is obviously fulfilled if the density f is bounded away from zero.

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3.3

Weaker Conditions

For the rest of the section assume that F is a distribution such that the associated function g is absolutely continuous with weak derivative g 0 . Our next aim is to relax the assumption of Theorem 2 that g 0 is bounded since it is unnecessarily strong. We will next introduce an integrability condition on g 0 that guarantees that a distribution can be embedded in bounded time. To simplify the analysis, throughout this subsection we consider only the Brownian motion without drift. Proposition 2. Let κ = 0. Suppose that there exists a constant p > 1 such that the convolution (g 0 )p ∗ ϕ is bounded, say by C. Then the distribution F is 2 embeddable with a stopping time bounded by C p p/(p − 1). Proof. Let q ∈ (1, ∞) be the conjugate of p, i.e. the real number satisfying 1 1 older’s Inequality yields that p + q = 1. H¨ ϕ1−t (x − z) ϕ(x − z)dz ϕ(x − z) R Z  p1 Z  q1 ϕq1−t (x − z) 0 p ≤ (g (z)) ϕ(x − z)dz dz q−1 (x − z) R R ϕ Z  q1 ϕq1−t (x − z) 1 p dz . ≤ C q−1 (x − z) R ϕ Z

Gx (t, x)

g 0 (z)

=

Note that Z ϕq1−t (x − z) dz q−1 (x − z) R ϕ      q (z − x)2 (z − x)2 = (2π(1 − t)) (2π) exp − + (q − 1) dz 1−t 2 2 R     Z q 1 q (z − x)2 exp − − (q − 1) dz = (2π)− 2 (1 − t)− 2 1−t 2 R   21 1−t − q2 − 21 = (2π) (1 − t) 2π q − (1 − t)(q − 1) q−1 1 = (1 − t)− 2 p . q − (1 − t)(q − 1) − q2

q−1 2

Z

This implies 1

q−1 2q

1

q−1 2q

Gx (t, x) ≤

C p (1 − t)−



C p (1 − t)−

10

1

(q − (1 − t)(q − 1))− 2q ,

and hence Z

1

2

Gx (t, x)2 dt ≤

Z

1

Cp

(1 − t)−

q−1 q

dt  0 1 1 2 C p −q(1 − t) q

0

=

0

2 p

=

C q.

Corollary 2. Suppose κ = 0 and that there exist q ∈ (1, ∞] such that kg 0 kLq (R) < ∞. Then the distribution is embeddable in bounded time. q

Proof. Let r ∈ (1, q). Then (g 0 )r ∈ L r . Observe that Young’s Inequality for convolutions implies that

q q−r

is the conjugate of rq .

q , k(g 0 )r ∗ ϕk∞ ≤ k(g 0 )r k rq kϕk q−r

i.e. (g 0 )r ∗ ϕ is bounded. The claim follows now from Proposition 2. Rx Lemma 1. Suppose F has compact support [x, x]. Let q > 1. If x is finite, then F can be embedded in bounded time. Proof. Notice that Z ∞ |g 0 (z)|q dz −∞

1 f q−1 (z) dz

q ϕ(z) = dz (f ◦ F −1 ◦ Φ)(z) −∞ q Z 1 q−1 1 ≤ (2π)− 2 dx (f ◦ F −1 )(x) 0 Z F −1 (1) 1 − q−1 dz < ∞, = (2π) 2 q−1 (z) F −1 (0) f Z





and hence the result follows from Corollary 2. −1

We next provide an example where ϕ◦Φ f ◦F −1 is not bounded and consequently g is not Lipschitz continuous, but the assumption of Lemma 1 applies. Example 2. Let F be the distribution function with compact support [−1, 1] and density ( −x, for x ∈ [−1, 0], f (x) = x, for x ∈ [0, 1]. −1

)(1/2) Observe that F (0) = Φ(0) = 1/2 and consequently (ϕ◦Φ (f ◦F −1 )(1/2) = ∞. Moreover, for p = 1/2, Z x Z 1 1 1 dz = = 4, p p x f (z) −1 |x|

which shows that the assumption of Lemma 1 is satisfied. 11

4

Application to Contest Games

Consider a model in which n ≥ 2 agents i ∈ {1, 2, . . . , n} face a continuous time stopping problem. Each agent privately observes a Brownian motion Xti = κt + σWti with drift κ. For simplicity of the exposition we restrict ourselves to the case σ = 1 here. Every agent i chooses a stopping time τ i with the restriction that whenever i Xt = −x0 (bankruptcy) he is forced to stop, x0 > 0. The player who stopped at the highest value wins a pre-specified prize (wlog. 1). In case of a tie, the prize is randomly assigned among all players with the highest value. In [6] it is proven that in every Nash-equilibrium the stopped BM Xτi i is distributed according to s n−1 1 exp (−2κ(x + x0 )) − 1 , F (x) = n exp (−2κx0 ) − 1 on the support [−x0 , F −1 (1)]. In the following paragraph we will see that the Lipschitz condition of Theorem 2 applies to the equilibrium distribution F . The density f = F 0 is given by f (x)

= = ≥

  1 −1 1 1 exp (−2κ(x + x0 )) − 1 n−1 1 exp (−2κ(x + x0 )) (−2κ) n−1 n exp (−2κx0 ) − 1 n exp (−2κx0 ) − 1 1 1 1 n−1 −n+2 + F (x) 2|κ| F (x) n−1 n exp (−2κx0 ) − 1 1 1 . 2|κ| (n − 1)n exp (−2κx0 ) − 1

Because for all x ∈ R g 0 (x) =

ϕ(x) 1 | exp (−2κx0 ) − 1| ≤ sup = n(n − 1) , −1 (f ◦ F ◦ Φ)(x) z∈[−x0 ,F −1 (1)] f (z) 2|κ|

it follows that F can be embedded in bounded time. This property is crucial for the economic interpretation of the results as in real world applications contests are always bounded in time.

References [1] S. Ankirchner, G. Heyne, and P. Imkeller. A BSDE approach to the Skorokhod embedding problem for the Brownian motion with drift. Stoch. Dyn. 8 (1) 35–46, 2008. [2] R. F. Bass. Skorokhod imbedding via stochastic integrals. In Seminar on probability, XVII, volume 986 of Lecture Notes in Math., pages 221–224. Springer, Berlin, 1983.

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[3] R. F. Bass. Stochastic Processes. Forthcoming, Cambridge University Press, 2011. [4] W. Feller. An introduction to probability theory and its applications. Vol. II. Second edition. John Wiley & Sons Inc., New York, 1971. [5] J. Obloj. The Skorokhod embedding problem and its offspring. Probability Surveys, 1 (September) 321–392, 2004. [6] C. Seel and P. Strack. Gambling in Dynamic Contests. Technical report, SSRN, 2009. URL http://papers.ssrn.com/sol3/papers.cfm? abstract_id=1472078. [7] A. V. Skorokhod. Studies in the theory of random processes. Translated from the Russian by Scripta Technica, Inc. Addison-Wesley Publishing Co., Inc., Reading, Mass., 1965.

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