Day 11 Snell's Law1 problems and solutions.notebook. May 11, 2013. Snell's
Law. Snell's Law describes how light bends (refracts) when traveling from one ...
Day 11 Snell's Law1 problems and solutions.notebook
Snell's Law Snell's Law describes how light bends (refracts) when traveling from one medium to the next. • We use Snell's law to CALCULATE the angles involved in refraction!
May 11, 2013 Example 1: Light travels from air into a glass prism at an angle of incidence of 60 degrees. Assume the angle of refraction is 35 degrees. a) Draw a labelled diagram of this situation.
Equation: n1 sin θ1= n2 sin θ2 Where: n1 = index of refraction of the first medium θ1 = angle of incidence (to the normal) n2 = index of refraction of the 2nd medium θ2 = angle of refraction (to the normal)
b) Find the index of refraction. Round to 2 dp
n 1 sin θ1= n2 sin θ2 n2 = n1 sin θ1 sin θ2 = (1.00)(sin 60o) (sin 35o) = 1.51 Therefore the index of refraction for this glass is 1.51
Example 2: Light travels from water into air, where the light ray makes a 30o angle with the normal. a) Draw a labelled diagram of this situation.
Example 3: Light rays travel through diamond into silicon. The light ray makes a 65 degree angle with the boundary. a) Draw the ray diagram
b) Identify the angle of refraction. b) Find the angle of refraction.
n1 sin θ1 = n2 sin θ2 (1.33)(sin 30o ) = (1.00) (sinθ2 ) (1.33)(sin 30o ) = (sinθ2 ) 1.00 0.665 = sinθ2 sin
1
(0.665) = θ2
θ2 = 42o o Therefore the angle refraction is 42
Day 11 Snell's Law1 problems and solutions.notebook
May 11, 2013
Example 4: Identify the second medium that the light will travel through. Alcohol
