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Calculate the Network Address, the broadcast address and the host range. Host
in Binary. 11000000. 10101000. 10110100. 01011110. Subnet Mask in Binary.
Student Name
Date
DT021-081/2 COMMUNICATIONS NETWORKS 1 Solutions to Exercises III
Example Given a Host Address = 192.168.180.94/27 Calculate the Network Address, the broadcast address and the host range. Host in Binary
11000000
10101000
10110100
01011110
Subnet Mask in Binary
11111111
11111111
11111111
11100000
Network in Binary
11000000
10101000
10110100
01000000
Network in Decimal
192
168
180
64
Broadca st addr. Bin
11000000
10101000
10110100
01011111
Broadcast addr. Dec
192
168
180
95
Subnet Mask in Decimal = 255.255.255.224 How many host bits? 5 So 2 5 =32 IP Addresses. (25 -2 = 30 Host) Host Address Range = 192.168.180.65 to 192.168.180.94
Question 1 Given a Host Address = 172.23.8.19 /21 Calculate the Network Address, the broadcast address and the host range. Host in Binary
10101100
00010111
00001000
00010011
Subnet Mask in Binary
11111111
11111111
11111000
00000000
Network in Binary
10101100
00010111
00001000
00000000
Network in Decimal
172
23
8
0
Broadcast addr. Bin
10101100
00010111
00001111
11111111
Broadcast addr. Dec
172
23
15
255
Subnet Mask in Decimal = 255.255.248.0 How many host bits? 11 So 2048 IP Addresses. ( 2046 Host Addresses) Host Address Range = 172.23.8.1 to 172.23.15.254
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Question 2 Given a Host Address = 147.252.238.20 255.255.240.0 Calculate the Network Address, the broadcast address and the host range. Host in Binary
10010011
11111100
11101110
00010100
Subnet Mask in Binary
11111111
11111111
11110000
00000000
Network in Binary
10010011
11111100
11100000
00000000
Network in Decimal
147
252
224
0
Broadcast addr. Bin
10010011
11111100
11101111
11111111
Broadcast addr. Dec
147
252
239
255
Network Prefix length = /20? How many host bits? 12 So 4096 IP Addresses. (4094 Host Addresses) Host Address Range = 147.252.224.1 to 147.252.239.254 Short questions Question: Which subnet does host 172.24.97.97/28 belong to? Answer: 172.24.97.96 Question: What is the last valid host on the subnetwork 92.168.184.96, with subnet mask: 255.255.255.240? Answer: 192.168.184.110 Question: How many subnets and hosts per subnet can you get from the network 172.27.0.0/16 using the subnet mask 255.255.255.192? Answer: 1024 subnets and 62 hosts Question: What valid host range is the IP address 192.168.107.64/25 a part of? Answer: 192.168.107.1 through to 192.168.107.126 Question: What is the last valid host on the subnetwork 72.17.225.128 using the subnet mask: 255.255.255.224? Answer: 72.17.225.158 Question: What is the first valid host on the subnetwork that the node 172.31.49.80 255.255.252.0 belongs to? Answer: 172.31.48.1 Question: Which subnet does host 172.16.73.16 255.255.240.0 belong to? Answer: 172.16.64.0 Question: What is the last valid host on the subnetwork 172.22.64.0/20? Answer: 172.22.79.254 Question: What is the last valid host on the subnetwork 192.168.236.0/26? Answer: 192.168.236.62
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