T-79.159 Cryptography and Data Security Spring 2004 Tutorial 4 ...
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T-79.159 Cryptography and Data Security Spring 2004 Tutorial 4 ...
19 Feb 2004 ... void chash(char *dst, const char *src). {. /* salt is set to ".." and we take chars 2..6
of the result */ memcpy(dst, crypt(src, "..") + 2, 4); dst[4] = 0;. }.
T-79.159 Cryptography and Data Security Tutorial 4 Thursday 19.2.2004 14.15, room T3. Markku-Juhani O. Saarinen
Spring 2004
Collision search We define a hash function from 4-character strings to 4-character strings using the UNIX crypt(3) function. This function is available on all UNIX systems (you may have to link it using -lcrypto). Source for the hash function is as follows: #include #include /* hash src and place the result to dst */ void chash(char *dst, const char *src) { /* salt is set to ".." and we take chars 2..6 of the result */ memcpy(dst, crypt(src, "..") + 2, 4); dst[4] = 0; } If your system lacks crypt(3), you can download an implementation from: http://www.tcs.hut.fi/~mjos/src/v7crypt.c A prototype for this implementation is char *v7crypt(char *pw, char *salt); (you will have to change the function name in chash() above). Your task is to devise a program that finds collisions in this hash function. Examples: chash(xanx)=.OHc chash(GoR9)=DtHU chash(nn.T)=WO8. chash(p5Tp)=9np9
See page 17 of fourth lecture slides (“Hashes and Message Digests”) for one possible algorithm. The running time of this algorithm shouldn’t exceed few seconds. Questions: 1. Each character is actually base-64 encoded and thus a 4-character string contains 24∗6 = 224 = 16777216 possibilities. What is the expected running time (in steps) for collision search ? 2. The full crypt(3) takes in 56 bits and produces a 64-bit hash. How difficult would it be to find collisions for this hash ? If you have problems with the programming task, just please show up on Thursday.
