THE HOMEOMORPHISM PROBLEM FOR S3 1 ... - Project Euclid
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THE HOMEOMORPHISM PROBLEM FOR S3 1 ... - Project Euclid
AMERICAN MATHEMATICAL SOCIETY. Volume 79, Number 5, September 1973. THE HOMEOMORPHISM PROBLEM FOR S3. BY JOAN S. BIRMAN1.
BULLETIN OF THE AMERICAN MATHEMATICAL SOCIETY Volume 79, Number 5, September 1973
THE HOMEOMORPHISM PROBLEM FOR S3 BY JOAN S. BIRMAN 1 AND HUGH M. HILDEN 2 Communicated by William Browder, January 22, 1973
1. Introduction. Let M be a closed, orientable 3-manifold which is defined by a Heegaard splitting of genus g. Each such Heegaard splitting may be associated with a self-homeomorphism of a closed, orientable surface of genus g (the surface homeomorphism is used to define a pasting map) and it will be assumed that this surface homeomorphism is given as a product of standard twist maps [3] on the surface. We assert: THEOREM 1. If M is defined by a Heegaard splitting of genus ^ 2 , then an effective algorithm exists to decide whether M is topologically equivalent to the 3-sphere S3. This algorithm also applies to a proper subset of all Heegaard splittings of genus > 2 .
This result is of interest because it had not been known whether such an algorithm was possible for g ^ 2, and also because the algorithm has a possible application in testing candidates for a counterexample to the Poincaré conjecture. In this note we will describe the algorithm, and sketch a brief proof. Related results about the connections between representations of 3manifolds as Heegaard splittings, and as branched coverings of S 3 , are summarized at the end of this paper. A detailed report will appear in another journal. 2. The algorithm. Let Xg be a handlebody of genus g ^ 0 which is imbedded in Euclidean 3-space as illustrated in Figure 1. Let X'g be a Z C
second handlebody, which is so related to Xg that a translation T parallel to the x-axis maps Xg onto X'g. Let $ be a homeomorphism of dXg -* dXg. Let M = XgKj0 Xg be the 3-manifold which is obtained by identifying the boundaries of Xg and Xg according to the rule T 0, then every homeomorphism of dXg -• 5Xff is isotopic to a product of twists yc. about the curves c£, 1 ^ i: ^ 3gf — 1, in Figure l. 3 We will make the assumption that our homeomorphism 2 the class of maps which can be so represented is somewhat restricted. We are now ready to state the algorithm for deciding whether M = XgKj0 Xg is homeomorphic to S3. Step 1. Given the homeomorphism (i) * = fd, ' • • y%r where each st = ± 1 , and each fxt is between 1 and 2g + 1, construct a diagram of the (2g + 2)-string braid