c ESO 2008
Astronomy & Astrophysics manuscript no. titan1 February 2, 2008
Titan’s rotation A 3-dimensional theory
arXiv:0710.4950v2 [astro-ph] 28 Nov 2007
B. Noyelles1,2 , A. Lemaître1 , and A. Vienne2,3 1 2
3
University of Namur - Department of Mathematics - Rempart de la Vierge 8 - 5000 Namur - Belgium IMCCE, Paris Observatory, UPMC, Univ. Lille 1, CNRS UMR 8028 - 77 avenue Denfert Rochereau - 75014 Paris France LAL / University of Lille - 1 impasse de l’Observatoire - 59000 Lille - France
Received / Accepted Abstract Aims. We study the forced rotation of Titan seen as a rigid body at the equilibrium Cassini state, involving the spin-orbit synchronization. Methods. We used both the analytical and the numerical ways. We analytically determined the equilibrium positions and the frequencies of the 3 free librations around it, while a numerical integration associated to frequency analysis gave us a more synthetic, complete theory, where the free solution split from the forced one. Results. We find a mean obliquity of 2.2 arcmin and the fundamental frequencies of the free librations of about 2.0977, 167.4883, and 306.3360 years. Moreover, we bring out the main role played by Titan’s inclination on its rotation, and we suspect a likely resonance involving Titan’s wobble. Key words. Celestial Mechanics – Planets and satellites: individual: Titan
1. Introduction Since the terrestrial observations of Lemmon et al. (1993), the rotation of Titan, Saturn’s main satellite, has been assumed to be synchronous or nearly synchronous. This has been confirmed by Lemmon et al. (1995a) and by Richardson et al. (2004) with the help of Voyager I images. In this last work, Titan’s rotation period is estimated at 15.9458 ± 0.0016 days, whereas its orbital period is 15.945421 ± 0.000005 days. The spin-orbit synchronization of a natural satellite is very common in the solar system (such as for the Moon and the Galilean satellites of Jupiter) and is known as a Cassini state. This is an equilibrium state that has probably been reached after a deceleration of the spin of the involved body under dissipative effects, like tides. Recently, Henrard and Schwanen (2004) have given a 3-dimensional elaborated analytical model of the forced rotation of synchronous triaxial bodies, after studying the librations around the Cassini state. This model has been successfully applied by Henrard on the Galilean satellites Io (2005a) and Europa (2005b), seen as rigid bodies. Such studies require knowing some parameters of the gravitational field of the involved bodies, which cannot be considered as spheres. Another analytical study has been performed for Mercury by D’Hoedt and Lemaître (2004), for the case of a 3 : 2 spin-orbit resonance. Send offprint requests to: B. Noyelles, e-mail:
[email protected]
Since the first fly-bys of Titan by the Cassini spacecraft, we have a first estimation of the useful parameters, more particularly Titan’s J2 and C22 (Tortora et al. 2006), so a similar study of Titan’s rotation can be made. In this paper, we propose a study of Titan’s forced rotation, where Titan is seen as a rigid body. The originality of this study over Henrard’s previous studies is that we use both the analytical and the numerical tools and compare our results.
2. Expressing the problem Titan is here considered as a triaxial rigid body whose principal moments of inertia are written respectively as A, B, and C, with A ≤ B ≤ C. 2.1. The variables Our variables and equations have already been used in previous studies; see for instance Henrard and Schwanen (2004) for the general case of synchronous satellites, Henrard (2005a) for Io, and Henrard (2005b) for Europa. We consider 3 reference frames : the first (e1 , e2 , e3 ) is centered on Titan’s mass barycenter and is in translation with the inertial reference frame used to describe the orbital motion of the Saturnian satellites in the TASS1.6 theory (see Vienne & Duriez 1995). This is a cartesian coordinate system whose origin is the center of Saturn, and it refers to the equatorial plane of Saturn and the node of this plane with the ecliptic at J2000. The second frame (n1 , n2 , n3 ) is linked to Titan’s angular momentum, and the third one
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B. Noyelles et al.: Titan’s rotation
(f1 , f2 , f3 ) is rigidly linked to Titan. In this last frame, Titan’s matrix of inertia is written as ! A 0 0 (1) I= 0 B 0 . 0 0 C
and consequently
We first use Andoyer’s variables (see Andoyer 1926 and Deprit 1967), which are based on two linked sets of Euler’s angles. The first set (h, K, g) locates the position of the angular momentum in the first frame (e1 , e2 , e3 ), while the second (g, J, l) locates the body frame (f1 , f2 , f3 ) in the second frame tied to the angular momentum (see Fig. 1). The canonical set of Andoyer’s variables consists of the three angular variables l, g, h and their conjugated momenta defined by the norm G of the angular momentum and two of its projections:
As a result, the Hamiltonian of the free rotation in the modified Andoyer’s variables is
L = G cos J G H = G cos K
l g h
ξq =
q
2Q nC
ηq =
2Q nC
cos q
where n is Titan’s mean orbital motion , q = −l, and Q = G−L = G(1−cos J) = 2G sin2 J2 . With these new variables, the singularity on l has been dropped. 2.2. The free rotation To describe the dynamics of the system, we should consider the free rotation and the perturbations by other bodies. The Hamiltonian of the free body rotation is also the kinetic energy of the rotation T = 21 (ω|G) where ω is the instantaneous rotation vector, G the angular momentum vector with respect to the center of mass, and (ω|G) the scalar product of the vector ω and G, where ω and G are respectively defined as ω = ω1 f1 + ω2 f2 + ω3 f3
(2)
G = Aω1 f1 + Bω2 f2 + Cω3 f3 .
(3)
and
We also deduce from the definitions of the angles l and J (the wobble): G = G sin J sin lf1 + G sin J cos lf2 + G cos Jf3 ,
(4)
from which we can easily deduce ω=
G G G sin J sin lf1 + sin J cos lf2 + cos Jf3 A B C
" # i γ1 + γ2 γ1 − γ2 nP 2 nP h 2 2 2 2 4−ξq −ηq ξ + η T = + 2 8 1 − γ1 − γ2 q 1 − γ1 + γ2 q (7) with γ1 =
M R2 2C − A − B = J2 2C C
(8)
M R2 B−A = 2C22 . 2C C
(9)
γ2 =
G P = nC G−H R = nC = P (1 − cos K) = 2P q sin2 K 2
sin q
(6)
and
Unfortunately, these variables present two singularities: when J = 0 (i.e., the angular momentum is colinear to f3 , there is no wobble), l and g are undefined, and when K = 0 (i.e., when Titan’s principal axis of inertia is perpendicular to its orbital plane), h and g are undefined. That is why we use the modified Andoyer’s variables: p=l+g+h r = −h
" # 1 L2 G2 − L2 sin2 l cos2 l + (ω|G) = + . 2 2 A B 2C
(5)
2.3. Perturbation by Saturn Considering the parent body Saturn as a point mass MY , the gravitational potential of the perturbation can be written as Z Z Z ρdW (10) V = −GMY d′ W where ρ is the density inside the volume W of the body and d′ the distance between the point mass and a volume element inside the body. Using the usual expansion of the potential in spherical harmonics (see for instance Bertotti and Farinella 1990), we find n X 1 X GMY V =− 1+ P m (sin φ)× d dn m=0 n n≥1 m Cn cos mψ + Snm sin mψ
(11)
where ψ and φ are respectively the longitude and the latitude of Saturn’s barycenter of mass in Titan’s frame, and d the distance between this Saturn’s barycenter of mass and the origin of the frame (Titan’s barycenter of mass). If we limit the expansion of (11) to the second order terms and GM Y drop the term d , which does not produce any effect on the rotation, we have
V =−
3GMY 2d3
h i M R2 J2 (x2 + y 2 ) + 2c22 (x2 − y 2 )
(12)
where x, y, and z are the coordinates of Saturn’s center p of mass in Titan’s frame (f1 , f2 , f3 ) (so we have d = x2 + y 2 + z 2 ). Here, d depends on the time since Titan’s motion around Saturn is not circular, but we can introduce d0 , the mean value of d, since a0 is Saturn’s mean semimajor axis and e0 its mean eccentricity. (They correspond respectively to Titan’s mean semimajor axis and mean eccentricity in a Saturnian frame.)
B. Noyelles et al.: Titan’s rotation
3
Figure 1. The Andoyer variables (reproduced from Henrard 2005a). with
We use the formula e2 d0 = a 1 + 2 coming from the development of Clemence 1961):
(13) r a
(see Brouwer &
r e2 3 3 =1+ + − e + e cos M a 2 8 2 e 3 − cos 2M − e3 cos 3M + O(e4 ) 2 8
3 GMY 2 d30
and we set n
∗2
d0 d
3
h i M R2 J2 (x2 + y 2 ) + 2c22 (x2 − y 2 )
=
d30
3 h i V d δ1 (x2 + y 2 ) + δ2 (x2 − y 2 ) =n nC d0
(16)
δ1 = −
2 3 n∗ γ1 2 n
(17)
δ2 = −
2 3 n∗ γ2 2 n
(18)
and
where M and R are respectively Titan’s mass and radius. As Henrard (2005b) did for Jupiter, we also take Saturn’s oblateness into account. The perturbing potential due to Saturn’s oblateness reads
Vo = δs Cn
2
d0 d
where RY is Saturn’s radius, and J2Y its J2 . Finally, the Hamiltonian of the problem reads
H=
nP 2 2
i γ + γ γ1 − γ2 nP h 1 2 2 2 4 − ξq − ηq ξ2 + η2 + 8 1 − γ1 − γ2 q 1 − γ1 + γ2 q 3 2 ! d0 d0 +n 1 + δs δ1 (x2 + y 2 ) + δ2 (x2 − y 2 ) . d d (21)
3. Analytical study
, so that we can write
with
(20)
(15)
GM
Y
!2
(14)
from which the mean anomaly M disappears after averaging. The perturbing potential V now reads
V =−
RY 5 δs = J2Y 2 d0
5
δ1 (x2 + y 2 ) + δ2 (x2 − y 2 )
(19)
We intend to use the Hamiltonian (21) to analytically determine the equilibrium position of Titan in the Cassini state related to the spin-orbit synchronization and the 3 frequencies of the free librations around this equilibrium, using the method explained in (Henrard & Schwanen 2004). For this analytical study, we consider that Titan has a circular orbit around Saturn, whose inclination on Saturn’s equatorial plane is given by only one periodic term extracted from TASS1.6 ephemerides (Vienne & Duriez 1995). This implies that the ascending node of Titan oscillates around a fixed value, so it cannot disappear after averaging the equations. That is why the analytical solutions of (Henrard and Schwanen 2004) cannot be used directly, and we first must check that they become unchanged without averaging the ascending node. The true orbital eccentricity of Titan is about 0.0289, but the opportunity to neglect it will be discussed later, after comparison with the numerical study. This way, the vector locating Saturn’s barycenter is colinear to xi e1 + yi e2 + zi e3
(22)
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B. Noyelles et al.: Titan’s rotation
with
xi = − cos 6 cos(λ6 − 6 ) − cos I6 sin 6 sin(λ6 − 6 ) (23) yi = − sin 6 cos(λ6 − 6 ) + cos I6 cos 6 sin(λ6 − 6 ) (24) and (25) zi = − sin I6 sin λ6 − 6 where I6 , 6 and λ6 are respectively Titan’s mean inclination, argument of the node and mean longitude in the inertial frame of the ephemerides. (The subscript 6 refers to the fact that Titan is Saturn’s sixth satellite.) To obtain the coordinates x, y, and z of Saturn is the reference frame bound to Titan (f1 , f2 , f3 ), 5 rotations are to be performed: x y z
!
= R3 (−l)R1 (−J)R3 (−g)R1 (−K)R3 (−h)
xi yi zi
! (26)
with R3 (φ) =
cos φ − sin φ 0 sin φ cos φ 0 0 0 1
!
(27)
– The ascending node of the frame (n1 , n2 , n3 ) (associated to the angular momentum) in the inertial frame has the same precession rate as the ascending node of Saturn in the same inertial frame, i.e. r + Y = 0, Y is the argument of the ascending node of Saturn. – There is no wobble, so the angular momentum is colinear with Titan’s axis of highest inertia f3 . This implies J = 0, so ξq = 0 and ηq = 0. We have
R1 (φ) =
Y = 6 ,
(30)
so it is convenient to introduce this new set of canonical variables: σ = p − λ6 + π ρ = r + 6
P R
where σ represents the angle between the axis of least inertia of Titan f1 and the direction Saturn-Titan, and ρ is the difference between the two ascending nodes. At the exact equilibrium, these two angles should be zero. This way, and also assuming d ≈ d0 (i.e., neglecting Titan’s orbital eccentricity), the Hamiltonian (21) becomes nP 2 ˙ − nP + R 2 +nδ1 (1 + δs )[a1 sin2 K + a2 sin K cos K cos ρ +a3 cos 2ρ(1 − cos 2K)] H=
!
.
(28)
+nδ2 (1 + δs )[b1 (1 + cos K)2 cos 2σ +b2 sin K(1 + cos K) cos(2σ + ρ)
Table 1 gives the values of the physical and dynamical parameter that we use, and Table 2 gathers the computed values of the corresponding parameters used in the Hamiltonian (21). Table 2. Values used in the Hamiltonian (21) that have been computed from the physical and orbital parameters given Table 1. Parameter d0 n∗ γ1 γ2 δ1 δ2 δs
(29)
and
and 1 0 0 0 cos φ − sin φ 0 sin φ cos φ
λY = λ6 − π
Numerical value 1222345.284 km 143.8339397847rad.y −1 1.016129 × 10−4 7.248387 × 10−5 −1.522286 × 10−4 −1.085897 × 10−4 9.247193 × 10−5
3.1. Equilibrium We consider here that the system is exactly at the Cassini state. This implies that: – The axis of least inertia, f1 , points to the center of mass of Saturn, so we have p − λY = 0, λY as the mean longitude of Saturn in the frame (f1 , f2 , f3 ).
(31)
+b3 sin2 K cos(2σ + 2ρ) +b4 sin K(1 − cos K) cos(2σ + 3ρ) +b5 (1 − cos K)2 cos(2σ + 4ρ)],
with the mean longitude disappearing after averaging, ex˙ has cept of course in the p variable. The term −nP + R to be added because the canonical transformation we use is time-dependent. The Hamiltonian (31) has been computed with Maple software, and the analytical expressions of the coefficients ai and bi are the same as in Henrard and Schwanen (2004). This means that, assuming that the ascending node of the orbit of the considered body circulates or not does not change the expressions of ai and bi , the formulae given in Henrard and Schwanen (2004) can be applied to bodies whose node does not circulate, e.g. J-4 Callisto, S-6 Titan or S-8 Iapetus. The analytical expressions of these coefficients are recalled in App.A, while Table 3 gives their numerical values in our context. At the exact equilibrium, we have σ = 0, ρ = 0, dσ dt = dρ ∂H ∂H ∂P = 0, and dt = ∂R = 0. These two last equations give h cos K − 1 i =0 E1 (P, K) = n P − 1 + 1 + δs ∆ P sin K
and
(32)
B. Noyelles et al.: Titan’s rotation
5
Table 1. Physical and dynamical parameters. Parameters n e γ = sin I26 RY J2Y M R GMY J2 c22
Values 143.9240478491399rad.y −1 0.0289 5.6024 × 10−3 58232 km 1.6298 × 10−2 2.36638 × 10−4 MY 2575 km 3.77747586645 × 1022 .km3 .y −2 (3.15 ± 0.32) × 10−5 (1.1235 ± 0.0061) × 10−5 0.31
C M R2
References TASS1.6 1995 TASS1.6 1995 TASS1.6 1995 IAU 2000 2002 Pioneer & Voyager 1989 Pioneer & Voyager 1989 IAU 2000 2002 Pioneer, Voyager + IERS 2003 Cassini 2006 Cassini 2006 (. . .)
Note 1. The mean values of Titan’s mean motion n, eccentricity e and inclination γ come from TASS1.6 theory (Vienne & Duriez 1995), the radii come from the IAU 2000 recommendations (Seidelmann et al. 2002), Titan’s mass M and Saturn’s J2 come from the Pioneer and Voyager space missions (Campbell & Anderson 1989). These two values are those used in TASS1.6 theory, we choose to keep them in order to remain coherent. The mass of Saturn has been derived from the fly-bys of the Pioneer and Voyager space missions, but the published value is given in solar masses. That is why we also indicate IERS 2003 as a reference, which gives us the solar mass. Titan’s J2 and C22 come from the fly-by T11 of the Cassini space mission (Tortora et al. 2006), but unfortunately no value for MCR2 is available yet. We can only hypothesize that it should be included between 0.3 and 0.4, as the case for the Galilean satellites of Jupiter.
Table 3. Numerical values of ai and bi . Parameter a1 a2 a3 b1 b2 b3 b4 b5
Numerical Value −4.9990584229813 × 10−1 1.12039208002146 × 10−2 1.56929503117011 × 10−5 2.49984306803404 × 10−1 5.60213623923651 × 10−3 4.70788509351034 × 10−5 1.75839129195533 × 10−7 2.46284149427823 × 10−10
˙ 6 + 1 + δs E2 (P, K) = with
K∗ ≈
n∆ =0 P sin K
(33)
+δ2 − 2b1 sin K(1 + cos K) + b2 (cos K + cos 2K) +b3 sin 2K + b4 (cos K − cos 2K) +2b5 sin K(1 − cos K) .
(34)
Since Titan’s ascending node oscillates around a fixed ˙ 6 = 0. A numerical resolution of (32) and value, we have (33) gives K ∗ = 1.1204858615 × 10−2 rad
(35)
P ∗ = 1;
(36)
= 2311.168arcsec = 38′ 31.168”
hence, ∗
R = 6.2773771522 × 10
δ1 + δ2 ˙ δ1 + δ2 − n
I,
(38)
which becomes K ∗ ≈ I when the mean value of the precession rate of the line of nodes is zero. 3.2. The fundamental frequencies of the free librations
∆ = δ1 a1 sin 2K + a2 cos 2K + 2a3 sin 2K
In the orbital model we use, I6 is constant at 0.011204858615 rad, which is exactly the value of K ∗ we get. Such an accuracy of 11 digits is given to indicate the numerical equality of the two values, but it has no real physical meaning, so Titan’s mean obliquity (measured with respect to its orbital inclination) should be nearly zero. This is confirmed by this formula, given by Henrard and Schwanen (2004):
−5
the asterisk meaning "at the equilibrium".
(37)
Since the equilibrium has been found, the Hamiltonian is centered in order to study the behavior of the system near the equilibrium. We introduce a new set of canonical variables: ξσ = σ ξρ = ρ ξq
ησ = P − P ∗ ηρ = R − R∗ ηq
As a translation, this transformation is canonical. In these variables, the main part of the Hamiltonian of the problem is quadratic. Its quadratic part is named N and we have N = γσσ ξσ2 + 2γσρ ξσ ξρ + γρρ ξρ2 + γqq ξq2 n(1 + δs )
(39)
+µσσ ησ2 + 2µσρ ησ ηρ + µρρ ηρ2 + µqq ηq2 . The analytical expressions of the coefficients µxx and γxx are recalled in App.B, and their numerical values are gathered in Table 4. The reader should be aware that these coefficients are similar to those in Henrard and Schwanen
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B. Noyelles et al.: Titan’s rotation
Table 4. Numerical values of the coefficients µxx and γxx Parameter γσσ γσρ γρρ γqq µσσ µσρ µρρ µqq
Numerical Value 2.1717941364 × 10−4 1.3632529077 × 10−8 1.6372888272 × 10−8 3.4788181236 × 10−4 5.0000000409 × 10−1 −6.5206613577 × 10−5 1.0387557096 1.4564940392 × 10−5
Parameter ζ1 ζ2 ζ3 ψ1 ψ2 ψ3 α β
(2004), but different from the ones used by Henrard for Io (2005a) and Europa (2005b) where other variables are used. We now introduce the following new set of canonical variables: ξσ = x1 − βx2 ξρ = αx1 + (1 − αβ)x2 ξq = x3
Table 5. Numerical values of the coefficients of the Hamiltonian N after the variables have been untangled.
with
ησ = (1 − αβ)y1 − αy2 ηρ = βy1 + y2 ηq = y3
with α and β conveniently chosen so as to untangle the variables ξ and η. It can be easily checked that this transformation is canonical, because it preserves the differential form; i.e. dξσ .ησ + dξρ .ηρ + dξq .ηq = dx1 .y1 + dx2 .y2 + dx3 .y3 . (40) With these new variables, the Hamiltonian (39) can be written as N = ζ1 x21 + ζ2 x22 + ζ3 x23 + ψ1 y12 + ψ2 y22 + ψ3 y32 (41) n(1 + δs )
Numerical Value 2.1717941364 × 10−4 1.6372032547 × 10−8 3.4788181236 × 10−4 0.5000000000 1.0387557096 1.4564940392 × 10−5 −6.1404734778 × 10−9 6.2770815833 × 10−5
U∗ =
s
ψ1 ζ1
(48)
V∗ =
s
ψ2 ζ2
(49)
∗
s
ψ3 . ζ3
(50)
W =
The purpose of this last canonical transformation is to show the free librations around the exact Cassini state. The arguments of these free librations are u, v, and √ w,√and the amplitudes associated are proportional to U, V , and √ W respectively. We can easily check that this transformation is canonical because we have du.U + dv.V + dw.W = dx1 .y1 + dx2 .y2 + dx3 .y3 . We can now write
with
N = ωu U + ωv V + ωw W
(51)
p ψ1 ζ1 (1 + δs )
(52)
p ψ3 ζ3 (1 + δs )
(54)
with ζ1 = γσσ + 2γσρ α + γρρ α2
ωu = 2n6 (42) ωv = 2n6
ζ2 = γσσ β 2 − 2β(1 − αβ)γσρ + γρρ (1 − αβ)2 ψ1 = µσσ (1 − αβ)2 + 2β(1 − αβ)µσρ + β 2 µρρ
(43)
(44)
ψ2 = α2 µσσ − 2αµσρ + µρρ
(45)
ζ3 = γqq
(46)
ψ3 = µqq .
(47)
The numerical values of these coefficients are gathered Table 5. We can now introduce the last following set of polar canonical coordinates: q √ 2U x1 = 2U U ∗ sin u y1 = U ∗ cos u q √ 2V y2 = V ∗ cos v x2 = 2V V ∗ sin v q √ 2W y3 = W x3 = 2W W ∗ sin w ∗ cos w
p ψ2 ζ2 (1 + δs )
ωw = 2n6
(53)
The numerical results are gathered in Table 6, so the periods associated to the 3 free librations around the equilibrium state are respectively 2.09, 167.37, and 306.62 years. Table 7 gives an application of the formulae given in this paper to the Galilean satellites of Jupiter Io and Europa, and we make a comparison with the analytical results of Henrard (2005a and 2005c) and the numerical results of Rambaux and Henrard (2005) obtained with the SONYR model (Rambaux & Bois 2004), which is a relativistic Nbody model. The small differences between our results and Henrard’s analytical results come from Henrard neglecting a3 , b3 , b4 , and b5 for Io, and b4 and b5 for Europa. Table 6. The free librations around the equilibrium state. Proper Modes u v w
ω (rad.y −1 ) 2.9998383244 3.7541492157 × 10−2 2.0491499350 × 10−2
T (period in years) 2.0945079794 167.36642435 306.62399075
B. Noyelles et al.: Titan’s rotation
Table 7. Comparison of the periods of the free librations of Io and Europa given by different models. Proper Modes Io u v w Europa u v w
Henrard
SONYR
this paper
13.25 days 159.39 days 229.85 days
13.18 days 157.66 days
13.31 days 160.20 days 228.53 days
52.70 days 3.60 years 4.84 years
55.39 days 4.01 years
52.98 days 3.65 years 4.86 years
Note 2. The results labelled "Henrard" come from (Henrard 2005a) for Io and (Henrard 2005c) for Europa, while the results labelled "SONYR" come from (Rambaux & Henrard 2005).
Table 8. Initial conditions chosen for the numerical integration, at t=-4500 years. Expression λ60 − π −60 10−4 10−4
Variable p0 r0 ξ0 η0 P0 R0
˙ 1 − n60 (1 − cos K0 ) + 10−4 6 1.0001 × P0 (1 − cos K0 )
Note 3. These conditions have been arbitrarily chosen near the ˙ 60 respectively the values of Cassini state, with λ60 , 60 , and Titan’s mean longitude, argument of the ascending node, and its instantaneous angular rate, at t=-4500 years, given by TASS1.6. K0 is the initial value of the obliquity K on the same date.
4. Numerical study To check the reliability of our previous results and to go further in the study of Titan’s forced rotation, we used the numerical tool. This allowed us first to obtain a solution for the rotation of Titan and then to describe it by frequency analysis and to split the free from the forced solutions. 4.1. Numerical integration We integrated the 6 equations coming from the Hamiltonian (21) over 9000 years, i.e. between -4500 and 4500 years, the time origin being J1980. In these equations, x and y come from TASS1.6 ephemerides. We recall that x, y, and z are the coordinates of the barycenter of mass of Saturn in the frame (f1 , f2 , f3 ) rigidly linked to Titan (see Sect. 2.3). We used the Adams-Bashforth-Moulton 10th -order predictor-corrector integrator, with a constant timestep h = 1.6 × 10−4 year, i.e. 5.844 × 10−2 day. We considered that the shortest significant fundamental period of the system is given by 3λ6 , i.e. ≈ 5.315 days ≈ 90 × h. Table 8 gathers the initial conditions we used. These conditions were arbitrarily chosen near the Cassini state. It implies that, by choosing these initial conditions, we supposed that Titan is at the Cassini state. In these initial conditions, the initial value of K K0 is defined as K0 =
δ1 + δ2 . ˙ δ1 + δ2 − n660
(55)
7
This equation is very similar to (38). We used it to be sure that the system is near the equilibrium. We did not want to start at the exact equilibrium but very close in order to be able to detect the 3 free librations that we studied in the previous section. However, we should keep in mind that the frequencies computed in Table 6 are in fact limits of the frequencies of the free librations when their amplitudes tend to zero. Thus, too high amplitudes of free librations would alter the frequencies too much. In that way, their comparison with the expected fundamental frequencies of the free librations might be difficult, so their identification as these fundamental frequencies could become doubtful. Figure 2 gives plots of some significant data resulting from the numerical integration. Figure 2a shows the beG havior of the variables P = nC (modulus of the plotted value) and σ, and Figure 2b shows the behavior of ρ, i.e. the difference between the two nodes. We can see that this angle is oscillating around 0, as predicted by the theory. We can also visually detect a period of about 700 years, and will see later that it is a forced component due to the behavior of Titan’s orbital ascending node. Figure 2c shows the behavior of the wobble J, we obtained it from the variables ξq and ηq . Finally, Figure 2d shows the “obliquity” K. In this last panel, we can see the same 700-year-periodic contribution detected in ρ. Unfortunately, looking at these plots does not give information on the free and the forced components of the solutions. That is why we used the frequency analysis technique. 4.2. Analysis of the solutions We use the frequency analysis to describe the solutions given by the numerical integration, i.e. to give a quasiperiodic representation of these solutions. Such a technique has already been used often to describe the orbital motion of planets (see Laskar 1988) or natural satellites (cf. for instance Vienne & Duriez 1995 or very recently Lainey et al. 2006). One of the main difficulties with this kind of problem is that we have two timescales for the periods of the terms that appear in the synthetic representations: Titan’s orbital period is roughly 16 days, while the period of its pericenter is about 700 years. In order to correctly detect the longperiod terms, the total time-interval used to analyze the solution should be about as long as the longest period expected, here ≈ 3200 years, and the timestep shorter than half the shortest period expected (about 5 days). Thus, data over 3200 years should be represented with a timestep of 2.5 days, but this would require about 500000 points. This would take a very long computation time, but fortunately some alternative techniques exist to solve this problem. The most common technique is the use of a digital filter that splits the short-period terms from the long-period ones (see Carpino et al. 1987). However, this technique might alter the signal. Another technique has been used here, which consists in using two samples of data with very close timesteps, as explained in Laskar (2004). More precisely, for each variable, we extracted two samples of 65536 data from the results of the numerical integration, one point every 848 for the first sample and one point every 864 for the other one. As a result, the first sample represents the solutions for 8891.7888 years with a timestep h1 = 49.55712 days, and the second represents the solutions for 9059.5584 years with a timestep h2 = 50.49216 days.
8
B. Noyelles et al.: Titan’s rotation
(a)
(b)
(c)
(d)
Figure 2. Numerical simulation of Titan’s obliquity over 9000 years, the time origin being J1980= 2444240 JD. Here the behavior of the variables P , σ, ρ, J and K is being displayed. Explanations are in the text. These two timesteps are far too large to detect contributions with a period of about 16 days. In fact, the shortperiod terms are detected, but with a wrong frequency. When a frequency ν is too high, it is detected as k1 h1 in analyzing the first sample, and as ν1 = ν +
ν2 = ν +
(56)
k2 h2
(57)
in analyzing the second one, where k1 and k2 are (a priori unknown) integers. We have (ν2 − ν1 )h2 = k2 − k1
h2 h1
(58)
and ν2 h2 − ν1 h1 = ν(h2 − h1 ) + k2 − k1 .
(59)
[ν2 h2 − ν1 h1 ] = k2 − k1
(60)
If we now define [x] as the closest integer to the real x (i.e. |[x] − x| < 21 ), we have and finally
h2 ((ν2 − ν1 )h2 − [ν2 h2 − ν1 h1 ]), (61) h1 − h2 where Eq.(60) requires that h1 and h2 are close enough, i.e. |ν(h2 − h1 )| < 12 . In our case, the highest frequency that we can detect with this method is 2(h21−h1 ) ≈ 0.54d−1 , so we can detect every term with a period longer than 11.75 days, while analyzing only one sample would give periods longer than about 100 days (i.e. 2 timesteps). Such accuracy is enough to detect Titan’s orbital period. Table 9 is an example of the decomposition of a variable G , with G the norm of the angular momentum) (here P = nC with the two timesteps. The algorithm used for determining each frequency is taken from (Laskar et al. 1992) and has been iteratively applied to refine each frequency, as described in (Champenois 1998). In this table, term 1 is a constant part, while the second one is clearly the free libration associated to the proper mode u. The slight difference between the obtained and the expected periods should be partly due to the associated amplitude not being null, and partly to the approximations used in our analytical model (i.e. no eccentricity and a constant inclination). However, we can see that the two determinations give very different results for term 3, so we can infer that it is in fact a short-period term. k1 =
B. Noyelles et al.: Titan’s rotation
9
Table 9. Decomposition of the solution for P with the two timesteps, i.e. h1 = 49.55712 days (left) and h2 = 50.49216 days (right). N◦ 1 2 3
Amp. 1.000000002 0.000099514 0.000025104
Phase (◦ ) −4.57 × 10−8 0.76 144.00
T (y) 3.50 × 1013 2.09773 1.25952
Amp. 1.000000002 0.000099514 0.000025104
Phase (◦ ) 8.95 × 10−8 0.77 144.00
T (y) −1.82 × 1013 2.09773 0.83097
Note 4. The origin of phases is here the origin of the frequency analysis, i.e. 4499.99344 years before J1980. The series are given in cosine.
Applying (61) we find T = 15.6612 days. That is very near to Titan’s orbital period, so this term should be an integer combination of Titan’s orbital period and other contribution(s). It is now interesting to identify the periodic terms contained in the solutions associated to the considered variables. Table 10 gives the proper modes that are expected. They should appear in the quasiperiodic decompositions of the solutions as parts of integer combinations, so integer combinations of the frequencies of the proper modes are performed to identify each term of the decompositions. We do not use the phases because they are uncertain in the Titan ephemerides given by Vienne & Duriez (1995). The reason is that the given phases are in fact integer combinations of the phases coming from the identified proper modes and very-long-period arguments due to the solar perturbation that are assumed to be constant on an ephemeridestimescale. Table 10. Proper modes of the system. Proper Mode λ5 λ6 λ8 φ5 Φ5 φ6 Φ6 φ8 Φ8 λ9 φu φv φw
Frequency (rad.y −1 ) 508.00932017 143.92404729 28.92852233 0.17554922 −0.17546762 0.00893386 −0.00893124 0.00197469 −0.00192554 0.21329912 2.995 0.0375 0.0205
terms. Except for two of them, all the components have been clearly identified. The terms whose periods are written in days were determined by comparing the results given by the two analysis. These terms are not clearly identified, the reason probably being that they require a high accuracy in their determination. In (61), two quantities are substracted, so a cancellation problem might appear and complicate the determination. Moreover, an integer combination between a short-period term (like Titan’s mean longitude λ6 ) and a long-period term gives a short-period term very close to the original short period, so the short-period terms that we detected might in fact be sums of several terms with very close frequencies, making them very difficult to split. These short-period terms seem to have a period very close to Titan’s orbital period, except the term 5 in the decomposition of σ. If we consider that the timesteps h1 and h2 are not close enough and that we have in fact [ν(h2 − h1 )] = 1, (61) becomes k1 = 1 +
Period
Cause
4.52 days 15.95 days 79.33 days 35.79 years 35.81 years 703.30 years 703.51 years 3181.86 years 3263.07 years 29.46 years 2.09773 years 167.4883 years 306.3360 years
Rhea Titan Iapetus e5 γ5 e6 γ6 e8 γ8 Sun √ √U √V W
Note 5. The modes λ5 to λ9 (first part of the Table) come from Vienne & Duriez (1995), while the second part contains the free librations around the Cassini state. These terms have been evaluated from the solutions given by our numerical integration. The fourth column gives the orbital parameter to which the proper mode is linked, ei being the eccentricity of the satellite i, and γi the sine of its semiinclination. The subscripts i are 5 for Rhea, 6 for Titan, and 8 for Iapetus.
The results are summarized in Tables 11 to 16, the origin of the phases now being J1980. There, K is given in radians, and the other variables have no unit. The terms with a period T written in years could have been obtained in analyzing only one set of data. In fact, the two sets have been analyzed, and the results are the same for these
h2 ((ν2 − ν1 )h2 − [ν2 h2 − ν1 h1 ]), h1 − h2
(62)
and we obtain a term whose period is 5.22008 days. This is quite close to the period associated to 3λ6 . The quasiperiodic decomposition of the solutions allows us to split the forced solution away from the free one. The free solution around the equilibrium can only be known with observations that could give initial conditions for the numerical integration. However, the forced solution only depends on the equilibrium and can be obtained in dropping, in the solutions given in Tables 11 to 16, the terms depending on the free libration modes φu , φv and φw . Thus, we can for instance see that angle J is not zero at the equilibrium but has a forced motion. This possibility of a forced wobble has already been pointed out by Bouquillon et al. (2003) in a general study of the rotation of the synchronous bodies (i.e. that are in a 1 : 1 spin-orbit resonance).
5. Discussion 5.1. Comparison between the analytical and the numerical results Table 17 gives a comparison between our analytical and numerical results. We recall that, in the analytical model, the orbit of Titan is circular with a constant inclination, whereas the orbital eccentricity of Titan (i.e. 0.0289) is taken into account in the numerical model, along with the variation in its inclination. We can see very good matching for the periods of the free librations around the equilibrium. In contrast, we can see a significant difference in the equilibrium obliquity K ∗ . The line ǫ refers to the equilibrium
10
B. Noyelles et al.: Titan’s rotation
Table 11. Quasiperiodic decomposition of the variable P . N◦ 1 2 3
Amp. 1.000000002 0.000099514 0.000025104
Phase (◦ ) 4.89 × 10−10 63.00 35.44
T (y) −1.82 × 1013 2.09773 15.6612 days
Ident. constant φu unknown
Cause √
U
Note 6. The series are in cosine. The fourth column gives the orbital parameters associated to each identified term.
Table 12. Quasiperiodic decomposition of the variable R. The series are in cosine. N◦ 1 2 3 4 5 6 7 8
Amp. ×105 9.17912502 8.22242693 2.28952572 1.49857669 0.30469561 0.22920477 0.05732146 0.01907471
Phase (◦ ) 2.07 × 10−6 −170.93 174.72 −143.60 −107.54 −61.85 −80.14 163.85
T (y) 6.12 × 1010 703.50790 167.48834 219.82166 3252.81 899.49195 176.5406 14.72857
Table 13. Quasiperiodic decomposition of the complex variable ηq + N◦ 1 2 3 4 5 6
Amp. ×104 9.12391728 6.01688587 5.73033451 3.83212940 0.63642954 0.38395548
Phase (◦ ) −51.69 51.69 158.48 −158.48 −35.86 35.86
obliquity with the normal of Titan’s orbit as its origin. It is computed by substracting the mean inclination of Titan to K ∗ . The mean inclination of Titan is 1.12049 × 10−2 in the analytical model and 1.18985 × 10−2 in the numerical one. The difference in K ∗ partly comes from the difference in the mean inclination of Titan, but probably not only from it. 5.2. Influence of Titan’s inclination and eccentricity Titan’s inclination plays an overwhelming role in its obliquity, as shown in (38). Moreover, the proper modes Φ5 , Φ6 , and Φ8 given in Table 10 can be linked in its inclination, because they consist of the main √ (or at least second) part of the solutions for ζ = sin 2I exp( −1) for Rhea, Titan, and Iapetus in TASS1.6, and they appear in the solution for ζ6 (related to Titan’s inclination). It is striking, for instance in reading Table 15, that the term Φ6 plays a very important role in the forced and in the free solution. We can even figure the period of 703.51 years just in looking at Fig.2b. In contrast, the proper modes φ5 , φ6 , and φ8 √ do not clearly appear, with the exception of φ6 in ηq + −1ξq . These modes are related to the eccentricities of Rhea, Titan, and Iapetus, and their values are respectively 10−3 , 0.0289, and 0.0294. In fact, φ6 might play a more important role than suggested by Tables 11 to 16, because it could be confused with −Φ6 by the algorithm of frequency analysis. The reason is that these two terms have very close periods, i.e. 703.3 and 703.51 years. If we call ν1 and ν2 the associated frequencies and ν0 the Fourier fundamental frequencies (i.e.
Ident. constant −Φ6 φv Φ6 + φv Φ8 Φ8 − Φ6 Φ8 + φv 2λ9
Cause γ6 √ √ V V γ6 γ8 γ6 γ8 √ V γ8 Sun
√ −1ξq .
T (y) 306.33602 −306.33605 351.70284 −351.70284 135.27368 −135.27368
Ident. φw −φw φ6 − Φ6 Φ6 − φ6 φv − Φ6 Φ6 − φv
Cause √ √W W e6 γ6 √e6 γ6 √V γ 6 V γ6
the frequency associated to a term whose period is the interval of study, 9000 years in our cases, it has no link to the fundamental frequencies of the system), the algorithm of frequency analysis can split ν1 from ν2 only if |ν1 − ν2 | > 2ν0 .
(63)
This implies that the interval of study should be longer than 4.712 × 106 yr. Such a timescale is not consistent with the ephemerides and so cannot be considered. It does not mean that the terms identified as Φ6 are in fact φ6 , because the period found is much closer to 703.51 years than to 703.30. It just means that there might be a very small contribution due to φ6 in the identified term. Moreover, we cannot exclude a role played by the eccentricities in the values of the equilibrium obliquity and of the fundamental frequencies of the free librations. 5.3. Uncertainty on Titan’s gravitational field Titan’s gravitational field is not clearly known. We are confident in its mass thanks to the Pioneer and Voyager flybys (see Campbell & Anderson 1989), but we are uncertain about 10% of its J2 , and we have no value for the ratio C MR2 . We can just hypothesize that it is included between 0.3 and 0.4, as it is the case for the Galilean satellites for C Jupiter. We arbitrarily chose MR 2 = 0.31 and also tried C with MR2 = 0.35. Tables 18 and 19 and Figure 3 summarize the result of C the study of Titan’s rotation with MR 2 = 0.35. Except for (c), the plots do not show any evident difference with Figure 2, because the frequencies of the free librations are shifted
B. Noyelles et al.: Titan’s rotation
11
Table 14. Quasiperiodic decomposition of the variable σ. The series are in sine. N◦ 1 2 3 4 5 6 7 8 9
Amp. ×103 4.78176461 0.02510524 0.01147635 0.01014094 0.00961527 0.00896290 0.00891238 0.00744233 0.00566630
Phase (◦ ) 63.00 35.43 −5.61 8.48 −74.09 −56.74 2.47 137.13 165.69
T (y) 2.09773 15.6612 days 167.47831 703.51797 55.1128 days 2.11032 2.08529 15.6602 days 219.75766
Ident. φu unknown φv −Φ6 unknown φu + 2Φ6 φu − 2Φ6 unknown φv + Φ6
Cause √ U √
V γ6
√ 2 √U γ62 U γ6 √
V γ6
Table 15. Quasiperiodic decomposition of the variable ρ. The series are in sine. N◦ 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
Amp. 0.18089837 0.15667339 0.11829380 0.09023900 0.07735641 0.05226443 0.05058400 0.03311443 0.03060799 0.02165111 0.02035272 0.02027563 0.01799820 0.01785634 0.01739585 0.01498249 0.01472909 0.01417957 0.01152268 0.01065513 0.00929051 0.00899501 0.00881939 0.00657942 0.00635299 0.00609640 0.00584381 0.00584403 0.00531164 0.00513296
Phase (◦ ) 175.64 −170.90 −175.17 −161.91 −166.02 −152.60 −156.89 −147.68 −143.30 −138.40 −173.58 −167.25 −132.60 −158.19 163.87 −176.87 −149.81 −128.79 −140.62 −121.56 −148.93 154.97 −131.88 −122.55 −110.18 −109.01 −87.12 −95.53 −19.68 −81.36
T (y) 167.49723 703.52446 135.28724 351.75789 113.46712 234.50407 97.70793 85.79329 175.88361 76.46679 74.84659 67.64828 140.70722 61.71406 14.72858 83.76245 56.73966 68.97041 52.50108 117.25730 62.81242 15.04352 48.85511 45.68121 100.50834 57.66387 109.64279 129.88963 29.44635 317.28640
Ident. φv −Φ6 φv − Φ6 2Φ6 φv − 2Φ6 −3Φ6 φv − 3Φ6 φv − 4Φ6 −4Φ6 φv − 5Φ6 2φv − Φ6 2φv − 2Φ6 −5Φ6 φv − 3Φ6 2λ9 2φv 2φv − 4Φ6 φv − 6Φ6 2φv − 5Φ6 −6Φ6 unknown 2λ9 + Φ6 2φv − 6Φ6 2φv − 7Φ6 −7Φ6 unknown φv − 2Φ6 − Φ8 φv − Φ6 − Φ8 λ9 −2Φ6 − Φ8
Cause √ V √γ6 V γ6 2 γ √ 6 2 V γ6 3 √γ6 3 √V γ64 V γ6 4 √γ6 5 V γ6 V γ6 V γ62 5 √γ6 3 V γ6 Sun V 4 √V γ6 6 V γ6 V γ65 γ66 Sun, γ6 V γ66 V γ67 γ67 √ 2 √V γ6 γ8 V γ6 γ8 Sun γ62 γ8
Table 16. Quasiperiodic decomposition of K. The series are in cosine. N◦ 1 2 3 4 5
Amp. ×102 (rad) 1.25481164 0.68465799 0.17842225 0.10246867 0.07264971
Phase (◦ ) 8.68 × 10−10 −170.92 175.02 −161.88 −15.67
C just a little when MR 2 changes. In contrast, the behavior of the wobble J (Figure 3c) is very interesting, because this angle can be 10 times bigger than in the previous simulation. Table 13 indicates that the most important terms in the solutions of ξq and ηq , on which J depends, are φw and 2Φ6 . In our cases, the periods of these terms are very close, so there might be a resonance between them, which could explain the amplitude of J. The matching on the frequen-
T (y) −2.65 × 1013 703.51272 167.49146 351.76856 219.80041
Ident. constant −Φ6 φv −2Φ6 φv + Φ6
Cause γ6 √ V 2 √γ6 V γ6
cies of the free librations between the analytical and the numerical methods is still good, while a shift on Titan’s mean obliquity still exists.
6. Conclusion This paper offers a first study of Titan’s rotation, where Titan is seen as a rigid body. We obtain a quasiperiodic de-
12
B. Noyelles et al.: Titan’s rotation
Table 17. Comparison between our analytical and numerical results. Parameter K ∗ (rad) ǫ (arcmin) Tu (y) Tv (y) Tw (y)
Analytical 1.1204859 × 10−2 0 2.094508 167.36642 306.62399
Numerical 1.25481164 × 10−2 2.233 2.09773 167.49723 306.33602
Difference 12% (. . .) 0.15% 0.08% 0.09%
(a)
(b)
(c)
(d)
Figure 3. Numerical simulation of Titan’s obliquity over 9000 years, with same as in Fig.2.
C MR2
= 0.35. The displayed variables are the
Table 19. Comparison between our analytical and numerical results, with
C MR2
= 0.35.
Parameter K ∗ (rad) ǫ (arcmin) Tu (y) Tv (y) Tw (y)
Analytical 1.1204859 × 10−2 0 2.225839 188.987571 346.236493
composition of the forced solution, which can be split from the free solution in which Titan’s obliquity plays an overwhelming role. Moreover, we find good matching between the frequencies of the free librations around the equilibrium, analytically and numerically evaluated, despite a model of circular orbit in the analytical study. However, we find a slight difference in the equilibrium obliquity. Finally, we
Numerical 1.272996 × 10−2 2.858 2.22896 189.10854 348.49661
Difference 13.6% (. . .) 0.14% 0.06% 0.65%
cannot exclude a resonance between the proper mode Φ6 and Titan’s wobble. The next fly-bys of Cassini spacecraft should give us more information on Titan’s gravitational field, so we should be able to make a more accurate study on its rotation, that could include direct perturbations on the other Saturnian satellites. These perturbations are supposed to be small (see for instance Henrard 2004) and should be neg-
B. Noyelles et al.: Titan’s rotation
Table 18. The free librations around the equilibrium state, C with MR 2 = 0.35 Proper Modes u v w
ω (rad.y −1 ) 2.822839 3.324655 × 10−2 1.814709 × 10−2
T (period in years) 2.225839 188.987571 346.236493
b1 = b2 =
13
1 − 2γ 2 + γ 4 1 + 2 cos I + cos2 I = 16 4 p 2 sin I + sin 2I = γ(1 − γ 2 ) 1 − γ 2 8 3 3 sin2 I = γ 2 (1 − γ 2 ) 8 2 p 2 sin I − sin 2I b4 = = γ3 1 − γ2 8 b3 =
ligeable compared to the uncertainties we have on Titan’s gravitational parameters. After that, the next step is to consider Titan as a multilayer non-rigid body and to study the consequences of its internal dissipation on the rotation. Acknowledgements. The authors are indebted to J. Henrard and N. Rambaux for fruitful discussions. They also thank P. Tortora for having sent them an electronic copy of his DPS poster. This work has been supported by an FUNDP post-doctoral research grant.
γ4 1 − 2 cos I + cos2 I = 16 4
(A.5) (A.6) (A.7) (A.8)
Appendix B: The coefficients γxx and µxx : γσσ = −2δ2 (b1 (1 + cos K ∗ )2 + b2 sin K ∗ (1 + cos K ∗ )
References Andoyer H., 1926, Mécanique Céleste, Gauthier-Villars, Paris Bertotti B. and Farinella P., 1990, Physics of the Earth and the Solar System, Kluwer, A.P. Bouquillon S., Kinoshita H. and Souchay J., 2003, Celes. Mech. Dyn. Astr., 86, 29 Brouwer D. and Clemence G.M., 1961, Methods of Celestial Mechanics, Academic Press, New-York Campbell J.K. and Anderson J.D., 1989, AJ, 97, 1485 Carpino M., Milani A. and Nobili A.M., 1987, A&A, 181, 182 Champenois S., 1998, Dynamique de la résonance entre Mimas et Téthys, premier et troisième satellites de Saturne, Ph.D thesis, Observatoire de Paris Deprit A., 1967, American Journal of Physics, 35, 424 D’Hoedt S. and Lemaître A., 2004, Cel. Mech. Dyn. Astr., 89, 267 Henrard J. and Schwanen G., 2004, Cel. Mech. Dyn. Astr., 89, 181 Henrard J., 2005a, Icarus, 178, 144 Henrard J., 2005b, Cel. Mech. Dyn. Astr., 91, 131 Henrard J., 2005c, Cel. Mech. Dyn. Astr., 93, 101 Lainey V., Duriez L. and Vienne A., 2006, A&A, 456, 783 Laskar J., 1988, A&A, 198, 341 Laskar J., Froeschlé Cl. and Celletti A., 1992, Physica D, 56, 253 Laskar J., 2004, Frequency analysis, quasiperiodic decompositions, and Nyquist limit in Journées scientifiques 2003 de l’Institut de Mécanique Céleste et de Calcul des Éphémérides, Notes Scientifiques et Techniques de l’Institut de Mécanique Céleste, S081, 29 Lemmon M.T., Karkoschka E. and Tomasko M., 1993, Icarus, 103, 329 Lemmon M.T., Karkoschka E. and Tomasko M., 1995, Icarus, 113, 27 Rambaux N. and Bois E., 2004, A&A, 413, 381 Rambaux N. and Henrard J., 2005, The rotation of the Galilean satellites, in The rotation of celestial bodies, ed. A. Lemaître, Presses Universitaires de Namur, Namur Richardson J., Lorenz R.D. and McEwen A., 2004, Icarus, 170, 113 Seidelmann P.K., Abalakin V.K., Bursa M. et al., 2002, Cel. Mech. Dyn. Astr., 82, 83 Tortora P., Armstrong J.W., Asmar S.W. et al., 2006, The determination of Titan’s gravity field with Cassini, DPS meeting 38, 56.01 Vienne A. and Duriez L., 1995, A&A, 297, 588
Appendix A: The coefficients ai , bi : a1 =
b5 =
(A.4)
1 + cos2 I 1 sin2 I − = − + 3γ 2 − 3γ 4 2 4 2 a2 =
p sin 2I = 2γ 1 − γ 2 (1 − 2γ 2 ) 2 a3 =
γ2 sin2 I = (1 − γ 2 ) 8 2
(A.1) (A.2) (A.3)
+b3 sin2 K ∗ + b4 sin K ∗ (1 − cos K ∗ ) + b5 (1 − cos K ∗ )2 ) (B.1) γσρ = −δ2 (b2 sin K ∗ (1 + cos K ∗ ) + b3 sin2 K ∗
+3b4 sin K ∗ (1 − cos K ∗ ) + 4b5 (1 − cos K ∗ )2 ) a2 γρρ = − δ1 sin 2K ∗ + 4a3 sin2 K ∗ 4 b 2 +δ2 sin K ∗ (1 + cos K ∗ ) + 2b3 sin2 K ∗ + 2 9 ∗ ∗ ∗ 2 b4 sin K (1 − cos K ) + 8b5 (1 − cos K ) 2
(B.2)
(B.3)
1 γ1 + γ2 2 1 − γ1 − γ2 cos(K ∗ − I) 7 5 −(δ1 + δ2 ) + cos(2(K ∗ − I)) + 4 16 16 (B.4) γqq =
1 δ1 + ∗2 (a1 + 2a3 )(1 − cos K ∗ )(3 cos K ∗ − 1) 2 P sin K ∗ a2 (6 cos3 K ∗ + 4 cos2 K ∗ − 5 cos K ∗ − 2) + ∗ 2 2 (1 + cos K ) 3 sin K ∗ cos 2K ∗ δ2 + ∗2 b1 (3 cos K ∗ + 1)(cos K ∗ − 1) + b2 P 2 1 + cos K ∗ ∗ +b3 (1 − cos K )(3 cos K ∗ − 1) b4 1 − cos K ∗ ∗ ∗ 2 ∗ sin K (1 + 8 cos K + 6 cos K ) + 3b + 5 2 1 + cos K ∗ (B.5) µσσ =
δ1 (a1 + 2a3 )(1 − 2 cos K ∗ )+ P ∗2 a2 1 + 4 cos K ∗ − 2 cos2 K ∗ − 4 cos3 K ∗ + 2 sin K ∗ (1 + cos K ∗ ) 4 cos2 K ∗ − cos K ∗ − 2 δ2 ∗ 2b cos K − b 1 2 P ∗2 2 sin K ∗ ∗ ∗ b cos K cos K − 1 4 −b3 (2 cos K ∗ − 1) + (4 cos K ∗ + 5) 2 sin K ∗ cos K ∗ + 1 sin2 K ∗ −2b5 1 + cos K ∗ (B.6) µσρ =
14
B. Noyelles et al.: Titan’s rotation
µρρ = −
δ1 a2 3 cos K ∗ − 2 cos3 K ∗ a + + + 2a 1 3 P ∗2 2 sin3 K ∗ b2 2 cos3 K ∗ − 3 cos K ∗ − 1 δ2 b + 1 P ∗2 2 sin3 K ∗ ∗ b4 1 − 3 cos K + 2 cos3 K ∗ −b3 − + b5 3 ∗ 2 sin K (B.7) µqq =
1 γ1 − γ2 2 1 − γ1 + γ2
(B.8)