Topological classification of oriented cycles of linear mappings

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Jan 11, 2014 - [2] G.E. Bredon, Topology and Geometry, New York: Springer-Verlag,. 1993. [3] T.V. Budnitska, Classification of topological conjugate affine ...
arXiv:1401.2550v1 [math.RT] 11 Jan 2014

Topological classification of oriented cycles of linear mappings˚ Tetiana Rybalkina Vladimir V. Sergeichuk rybalkina [email protected] [email protected] Institute of Mathematics, Tereshchenkivska 3, Kiev, Ukraine

Abstract We consider oriented cycles Fm1 h

A1

/ Fm2

A2

/ ...

At´2

/ Fmt´1

At´1

/ Fmt

At

of linear mappings over F “ C or R, and reduce the problem of their classification up to homeomorphisms in the spaces Fm1 , . . . , Fmt to the case t “ 1, which was studied by N.H. Kuiper and J.W. Robbin [Invent. Math. 19 (no. 2) (1973) 83–106] and by other authors. Keywords: Oriented cycles of linear mappings; Topological equivalence 2000 MSC : 15A21; 37C15

1

Introduction

We consider the problem of topological classification of oriented cycles of linear mappings. Printed in Ukrainian Math. J., 2014. The second author was supported in part by the Foundation for Research Support of the State of S˜ ao Paulo (FAPESP), grant 2012/181392. ˚

1

Let A:

V1 h

A1

/

A2

V2

/

At´2

...

/

Vt´1

At´1

/

Vt

(1)

Wt

(2)

At

and B:

B1

W1 h

/

B2

W2

/

Bt´2

...

/

Wt´1

Bt´1

/

Bt

be two oriented cycles of linear mappings of the same length t over a field F. We say that a system ϕ “ tϕi : Vi Ñ Wi uti“1 of bijections transforms A to B if all squares in the diagram A1

V1 j

/

V2

A2

/

...

At´2

/

Vt´1

At´1

/

Vt

At



W1 j

ϕt´1

ϕ2

ϕ1 B1

/



W2

B2

/

...

Bt´2

/



Wt´1

Bt´1

/

ϕt

(3)



Wt

Bt

are commutative; that is, ϕ2 A1 “ B1 ϕ1 , . . . , ϕt At´1 “ Bt´1 ϕt´1 , ϕ1 At “ Bt ϕt .

(4)

Definition 1. Let A and B be cycles of linear mappings of the form (1) and (2) over a field F. (i) A and B are isomorphic if there exists a system of linear bijections that transforms A to B. (ii) A and B are topologically equivalent if F “ C or R, Vi “ Fmi ,

Wi “ Fni

for all i “ 1, . . . , t,

and there exists a system of homeomorphisms1 that transforms A to B. 1

By [2, Corollary 19.10] or [17, Section 11], m1 “ n1 , . . . , mt “ nt .

2

The direct sum of cycles (1) and (2) is the cycle A‘B :

V1 ‘ W1 j

A1 ‘B1

/

V2 ‘ W2

A2 ‘B2

/

...

At´1 ‘Bt´1

/

Vt ‘ Wt

At ‘Bt

The vector dim A :“ pdim V1 , . . . , dim Vt q is the dimension of A. A cycle A is indecomposable if its dimension is nonzero and A cannot be decomposed into a direct sum of cycles of smaller dimensions. A cycle A is regular if all A1 , . . . , At are bijections, and singular otherwise. Each cycle A possesses a regularizing decomposition A “ Areg ‘ A1 ‘ ¨ ¨ ¨ ‘ Ar ,

(5)

in which Areg is regular and all A1 , . . . , Ar are indecomposable singular. An algorithm that constructs a regularizing decomposition of a nonoriented cycle of linear mappings over C and uses only unitary transformations was given in [21]. The following theorem reduces the problem of topological classification of oriented cycles of linear mappings to the problem of topological classification of linear operators. Theorem 1. (a) Let F “ C or R, and let A:

Fm1 i

A1

Fm2 /

A2

/

...

At´2

/

Fmt´1

At´1

/

Fmt

(6)

At

and B:

Fn 1 h

B1

/

Fn 2

B2

/

...

Bt´2

/

Fnt´1

Bt´1

/

Fn t

(7)

Bt

be topologically equivalent. Let A “ Areg ‘ A1 ‘ ¨ ¨ ¨ ‘ Ar ,

B “ Breg ‘ B1 ‘ ¨ ¨ ¨ ‘ Bs

(8)

be their regularizing decompositions. Then their regular parts Areg and Breg are topologically equivalent, r “ s, and after a suitable renumbering their indecomposable singular summands Ai and Bi are isomorphic for all i “ 1, . . . , r. 3

(b) Each regular cycle A of the form (6) is isomorphic to the cycle A1 :

Fm1 i

1 / m2 1 F /

...

1 / mt´1 F

1 /

Fmt

(9)

At ¨¨¨A2 A1

If cycles (6) and (7) are regular, then they are topologically equivalent if and only if the linear operators At ¨ ¨ ¨ A2 A1 and Bt ¨ ¨ ¨ B2 B1 are topologically equivalent pas the cycles Fm1 ý At ¨ ¨ ¨ A2 A1 and Fn1ý Bt ¨ ¨ ¨ B2 B1 of length 1q. Kuiper and Robbin [18, 16] gave a criterion for topological equivalence of linear operators over R without eigenvalues that are roots of 1. Budnitska [4, Theorem 2.2] found a canonical form with respect to topological equivalence of linear operators over R and C without eigenvalues that are roots of 1. The problem of topological classification of linear operators with an eigenvalue that is a root of 1 was studied by Kuiper and Robbin [18, 16], Cappell and Shaneson [6, 7, 8, 9, 10], and Hsiang and Pardon [15]. The problem of topological classification of affine operators was studied in [4, 12, 1, 3, 5]. The topological classifications of pairs of counter mappins V1 ÝÑ ÐÝ V2 (i.e., oriented cycles of length 2) and of chains of linear mappings were given in [19] and [20].

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Oriented cycles of linear mappings up to isomorphism

This section is not topological; we construct a regularizing decomposition of an oriented cycle of linear mappings over an arbitrary field F. A classification of cycles of length 1 (i.e., linear operators V ý) over any field is given by the Frobenius canonical form of a square matrix under similarity. The oriented cycles of length 2 (i.e., pairs of counter mappins V1 ÝÑ ÐÝ V2 ) are classified in [11, 14]. The classification of cycles of arbitrary length and with arbitrary orientation of its arrows is well known in the theory of representations of quivers; see [13, Section 11.1]. For each c P Z, we denote by rcs the natural number such that 1 ď rcs ď t,

rcs ” c mod t.

4

By the Jordan theorem, for each indecomposable singular cycle V ý A there exists a basis e1 , . . . , en of V in which the matrix of A is a singular Jordan block. This means that the basis vectors form a Jordan chain A

A

A

A

A

e1 Ý Ñ e2 Ý Ñ e3 Ý Ñ ¨¨¨ Ý Ñ en Ý Ñ 0. In the same manner, each indecomposable singular cycle A of an arbitrary length t also can be given by a chain Ap

Arp`1s

Arp`2s

Arq´1s

Arqs

ep ÝÑ ep`1 ÝÝÝÝÑ ep`2 ÝÝÝÝÑ ¨ ¨ ¨ ÝÝÝÝÑ eq ÝÝÑ 0 in which 1 ď p ď q ď t and for each l “ 1, 2, . . . , t the set tei |i ” l mod tu is a basis of Vl ; see [13, Section 11.1]. We say that this chain ends in Vrqs since eq P Vrqs . The number q ´ p is called the length of the chain. For example, the chain e ❞❞/ e5 ❞❞❞❞❞4❞❞ ❞ ❞ ❞ ❞ ❞ ❞ ❞❞❞❞ e6 r❞❞ / e7 / e8 ❡❡❡/ ❡e❡9❡❡❡/ e10 ❡❡❡❡❡ ❡❡/ ❡❡❡❡ / ❡ r 0 e11 e12 of length 8 gives an indecomposable singular cycle on the spaces V1 “ Fe6 ‘ Fe11 , V2 “ Fe7 ‘ Fe12 , V3 “ Fe8 , V4 “ Fe4 ‘ Fe9 , V5 “ Fe5 ‘ Fe10 . Lemma 1. Let A:

V1 h

A1

/

A2

V2

/

At´2

...

/

Vt´1

At´1

/

Vt

At

be an oriented cycle of linear mappings, and let (5) be its regularizing decomposition. (a) Write

Aˆi :“ Ari`t´1s ¨ ¨ ¨ Ari`1s Ai : Vi Ñ Vi

and fix a natural number z such that V˜i :“ Aˆzi Vi “ Aˆz`1 Vi i

for all i “ 1, . . . , t.

Let A˜ :

V˜1 h

˜1 A

/

V˜2

˜2 A

/

... ˜t A

5

˜t´2 A

˜

/

At´1 ˜t /V V˜t´1

(10)

be the cycle formed by the restrictions A˜i : V˜i Ñ V˜ri`1s of Ai : Vi Ñ Vri`1s . Then Areg “ A˜ pand so the regular part is uniquely determined by Aq. (b) The numbers kij :“ dim KerpAri`js ¨ ¨ ¨ Ari`1s Ai q,

i “ 1, . . . , t and j ě 0,

determine the singular summands A1 , . . . , Ar of regularizing decomposition (5) up to isomorphism since the number nlj pl “ 1, . . . , t and j ě 0q of singular summands given by chains of length j that end in Vl can be calculated by the formula nlj “ krl´js,j ´ krl´js,j´1 ´ krl´j´1s,j`1 ` krl´j´1s,j

(11)

in which ki,´1 :“ 0. Proof. (a) Let (5) be a regularizing decomposition of A. Let Vi “ Vi,reg ‘ Vi1 ‘ ¨ ¨ ¨ ‘ Vir ,

i “ 1, . . . , t,

be the corresponding decompositions of its vector spaces. Then Aˆzi Vi,reg “ Vi,reg (since all linear mappings in Areg are bijections) and Aˆzi Vi1 “ ¨ ¨ ¨ “ ˜ Aˆzi Vir “ 0. Hence Vi,reg “ V˜i , and so Areg “ A. (b) Denote by σij :“ nij ` ni,j`1 ` ni,j`2 ` ¨ ¨ ¨ the number of chains of length ě j that end in Vi . Clearly, ki0 “ σi0 , ki1 “ σi0 ` σri`1s,1 , . . . , and kij “ σi0 ` σri`1s,1 ` ¨ ¨ ¨ ` σri`js,j for each 1 ď i ď t and j ě 0. Therefore, σlj “ kij ´ ki,j´1,

l :“ ri ` js

(recall that ki,´1 “ 0). This means that l ” i ` j mod t, i ” l ´ j mod t, i “ rl ´ js, and so σlj “ krl´js,j ´ krl´js,j´1. We get nlj “ σlj ´ σl,j`1 “ krl´js,j ´ krl´js,j´1 ´ krl´j´1s,j`1 ` krl´j´1s,j . 6

3

Proof of Theorem 1

In this section, F “ C or R. (a) Let A and B be cycles (6) and (7). Let them be topologically equivalent; that is, A is transformed to B by a system tϕi : Fmi Ñ Fni uti“1 of homeomorphisms. Let (8) be regularizing decompositions of A and B. First we prove that their regular parts Areg and Breg are topologically equivalent. In notation (10), Aˆi “ Ari`t´1s ¨ ¨ ¨ Ari`1s Ai ,

ˆi “ Bri`t´1s ¨ ¨ ¨ Bri`1s Bi . B

ˆ z Fn i “ Let z be a natural number that satisfies both Aˆzi Fmi “ Aˆz`1 Fmi and B i i z`1 n i ˆ F for all i “ 1, . . . , t. By (3), the diagram B i

Fmi

ˆz A

Fmi /

ϕi

ϕi



Fn i

ˆz B

/



Fn i

ˆ z for all i. Therefore, the restriction is commutative. Then ϕi Im Aˆzi “ Im B i ˆ z is a homeomorphism. The system of homeomorphisms ϕˆi : Im Aˆzi Ñ Im B i ˜ which are the regular parts of A and B by ϕˆ1 , . . . , ϕˆt transforms A˜ to B, Lemma 1(a). Let us prove that r “ s, and, after a suitable renumbering, Ai and Bi are isomorphic for all i “ 1, . . . , r. Since all summands Ai and Bi with i ě 1 can be given by chains of basic vectors, it suffices to prove that nij “ n1ij for all i and j, where n1ij is the number of singular summands B1 , . . . , Bs in (8) given by chains of length j that end in the ith space Fni . Due to (11), it suffices to prove that the numbers kij are invariant with respect to topological equivalence. In the same manner as kij is constructed by A, we construct kij1 by B. Let us fix i and j and prove that kij “ kij1 . Write A :“ Ari`js ¨ ¨ ¨ Ari`1s Ai ,

B :“ Bri`js ¨ ¨ ¨ Bri`1s Bi ,

q :“ ri ` j ` 1s

and consider the commutative diagram Fmi

A

Fmq /

ϕq

ϕi



Fn i

B

7

/



Fn q

(12)

which is a fragment of (3). We have kij1 “ ni ´ dim Im B.

kij “ dim Ker A “ mi ´ dim Im A,

Because ϕi : Fmi Ñ Fni is a homeomorphism, mi “ ni (see [2, Corollary 19.10] or [17, Section 11]). Since the diagram (12) is commutative, ϕq pIm Aq “ Im B. Hence, the vector spaces Im A and Im B are homeomorphic, and so dim Im A “ dim Im B, which proves kij “ kij1 . (b) Each regular cycle A of the form (6) is isomorphic to the cycle A1 of the form (9) since the diagram Fm1 i

1 / m2 F

1 / m3 F

1 / m4 F

1 / ...

1 / mt F

At ¨¨¨A2 A1

1 

Fm1 i

A1

A1

/



Fm2

A2 A1

A2

/



Fm3

A3

At´1 ¨¨¨A2 A1

/

A3 A2 A1



Fm4

A4

/

...

At´1

/

(13)



Fmt

At

is commutative. Let A and B be regular cycles of the form (6) and (7). Let them be topologically equivalent; that is, A is transformed to B by a system ϕ “ pϕ1 , . . . , ϕt q of homeomorphisms; see (3). By (4), ϕ1 At At´1 ¨ ¨ ¨ A1 “ Bt ϕt At´1 ¨ ¨ ¨ A1 “ Bt Bt´1 ϕt´1 At´2 ¨ ¨ ¨ A1 “ ¨ ¨ ¨ “ Bt Bt´1 ¨ ¨ ¨ B1 ϕ1 , and so the cycles Fm1 ý At ¨ ¨ ¨ A2 A1 and Fm1ý Bt ¨ ¨ ¨ B2 B1 are topologically equivalent via ϕ1 . Conversely, let Fm1ý At ¨ ¨ ¨ A2 A1 and Fm1 ý Bt ¨ ¨ ¨ B2 B1 be topologically equivalent via some homeomorphism ϕ1 , and let A1 and B1 be constructed by A and B as in (9). Then A1 and B1 are topologically equivalent via the system of homeomorphisms ϕ “ pϕ1 , ϕ1 , . . . , ϕ1 q. Let ε and δ be systems of linear bijections that transform A1 to A and B1 to B; see (13). Then A and B are topologically equivalent via the system of homeomorphisms δϕε´1 .

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