Modeling of a Three-level Static VAR Compensator

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INTERNATIONAL CONFERENCE ON ELECTRIC POWER ENGINEERING (ICEPENG 2015) OCTOBER ..... [7]Dass, H.K., Advanced Engineering Mathematics,.
INTERNATIONAL CONFERENCE ON ELECTRIC POWER ENGINEERING (ICEPENG 2015) OCTOBER 14-16, 2015

Modeling of a Three-level Static VAR Compensator and Simulation Study of a Universal Power Flow Controller Damian B. Nnadi

Crescent O. Omeje

Christian N. Obetta

Dept. of Electrical Engineering, University of Nigeria, Nsukka +2348069335370 [email protected]

Dept. of Electrical Engineering University of Port Harcourt, Port Harcourt +2340869335370

Dept. of Elect Elect. Engineering Enugu State University of Science & Technology, Enugu [email protected]

[email protected]

compensatory device-flexible alternating current transmission system devices (FACTS) to control the

Abstract This paper presents the analysis and simulation study of

magnitude of the voltage at a particular bus bar in

a three-level voltage source inverter in controlling the

any electric power system, the minimization of these

magnitude

transmission losses is actualized.

of

reactive

power

flow

in

a

given

transmission line. The mathematical modeling of the 3-

This, therefore, formed the basic principles of static

level thyristor controlled voltage source inverter

var compensator devices. A static var compensator

(TCVSI) in the d-q axis with respect to the static var

(SVC) is an electrical device meant for providing

compensator is presented in this work. In line with the

fast-acting reactive power compensation on high-

above analysis is the state space and dynamic equations of the TCVSI in determining the inverter’s optimum performance while the simulation of a unified power flow controller which is aimed at determining the

voltage

electricity

transmission

network,

thus,

regulating the magnitude of the supply voltage and also stabilizing the transmission network during

variation in the rate of reactive power flow across the

transient disturbances [1].

transmission line is also analyzed in this work with the

The SVC is an automated (mechanized) impedance

aid of MATLAB/SIMULINK software package.

matching device, designed to ensure that the transmission line parameters get closer to unity

Key words: Thyristor controlled, Voltage Source Inverter,

power factor. This is realized by the following

Static Var Compensator and Unified Power Flow

underlying principles:

Controller.

If the power systems reactive load is capacitive 1 Introduction

(leading Power factor), the SVC device switches on

Reactive power (VAR) compensation and its control

the reactors to absorb the reactive power from the

have formed an essential part in the analysis of power

system thus lowering the system voltage to the

system and efficient functioning of transmission line

manufacturers default value which is the acceptable

parameters. This is achieved by the minimization of

system operational value.

power transmission losses achieved by maintaining a

For an inductive load condition (Lagging Power

constant supply voltage across the line. It is a well-

factor), the capacitor banks are automatically

established fact that by using reactive power

switched on with the aid of a thyristor-controlled

D. B. NNADI, C. O. OMEJE, C. N. OBETTA

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INTERNATIONAL CONFERENCE ON ELECTRIC POWER ENGINEERING (ICEPENG 2015) OCTOBER 14-16, 2015

VSI, thus, providing a higher but appreciable system

topology. The operational principles of the system

operational voltage magnitude [2].

can be explained by considering per phase of the

2

SVC system. It is observed that from Figure.2, the

Principles of operation of a three-level VSI

based static compensator

inverter output terminal voltage is given by ea, while

The static var compensator which uses a three-level

ia and va are the fundamental components of current

converter is shown in Figure 1. The main circuit

and voltage of the phase “A” a.c mains voltage

consists of twelve power GTO’s thyristors with an

source. The SVC is connected to this a.c main

anti-parallel diodes which is connected to a three

through a reactor L and a resistor R representing the

phase supply through a reactor. Two capacitors are

total loss in the inverter.

connected to the d.c supply voltage of the inverter

Figure 1 Power circuit of three-level VSI static var compensator

By controlling the phase angle α, the amplitude of the fundamental component of the inverter phase voltage and the a.c mains voltage can as well be controlled [3].

∂ib Vb − eb Rib = − ∂t L L ∂ic Vc − ec Ric = − ∂t L L

(2) (3)

3. Mathematical modeling of the 3-level VSI based

Transforming (1), (2) and (3) in matrix form gives

static var compensator (SVC)

rise to (4) as shown below:

Figure 2 represents a simplified equivalent circuit of

voltage law (KVL) across the three phases of the

𝜕𝑖𝑎 −𝑅 𝜕𝑡 𝐿 𝜕𝑖𝑏 = 0 𝜕𝑡 𝜕𝑖𝑐 [ 0 [ 𝜕𝑡 ]

inverter equivalent circuits. Equations (1) - (3) are

The inverter supply voltage which corresponds to the

derived from Figure 2 using KVL;

d.c capacitor voltages are given by:

the 3-levelVSI based static var compensator. The mathematical modeling of the circuit presented below is effectively done by applying the Kirchhoff’s

∂ia Va − ea Ria = − ∂t L L

0 −𝑅 𝐿 0

0

𝑖𝑎 𝑉𝑎 − 𝑒𝑎 1 × [𝑉𝑏 − 𝑒𝑏 ] 0 [𝑖 𝑏 ] + 𝐿 𝑖 𝑉𝑐 − 𝑒𝑐 −𝑅 𝑐 𝐿 ]

(1)

D. B. NNADI, C. O. OMEJE, C. N. OBETTA

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(4)

INTERNATIONAL CONFERENCE ON ELECTRIC POWER ENGINEERING (ICEPENG 2015) OCTOBER 14-16, 2015

∂Uc1

[∂U∂t ] = c2

∂t

1 C

I × [ c1 ] Ic2

Where VL is the r.m.s line voltage The inverter output voltage derived from Figure 2

(5)

above is given by the following equation:

The conventional three phase AC-mains voltage is given by the following expression:

VABC

EABC

105

sin(ωt) 2π VA 2 sin (ωt − ) = [VB ] = √ × VL × (6) 3 3 Vc 2π [sin (ωt + 3 )]

sin(ωt + α) ea 2π 2 sin (wt − + α) = [eb ] = √ × M × × Uc (7) 3 3 ec 2π sin (ωt + + α) [ ] 3

Figure 2: Equivalent circuit of three-level VSI static var compensator

Where M represents the modulation index, Uc

voltage to the two axes (dq) rotating reference frame

represents the inverter source voltage and α

result to (8)

Vqdo = 𝑃 × VABC

represents the thyristor controlled delay angle also known as the firing angle of the thyristor [4]. In transforming (1) – (7) into their d-q-o reference frame, the following assumptions were made: All the

(8)

P operator in (8) represents the improved Park’s transformation matrix given by (9) 𝑃

inverter switches were considered to be ideal so as to prevent the forward voltage associated with other

=√

switches. The source voltages and currents were balanced across the capacitor bus-bar in Figure 2 above. The total losses in the inverter are derived from the three phase lumped resistors. The magnitude of the total harmonic distortion value caused by the switching action of the inverter is considered to be negligible [5]. Transforming the abc a.c mains

2 3 2π 2π + α) cos (ωt + + α) 3 3 2π 2π sin (ωt − + α) sin (ωt + + α) (9) 3 3 1 1 ] √2 √2

cos(ωt + α) cos (ωt − × sin(ωt + α) 1 [

√2

Substituting the values of P and VABC into (8) gives rise to (10) as shown below:

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INTERNATIONAL CONFERENCE ON ELECTRIC POWER ENGINEERING (ICEPENG 2015) OCTOBER 14-16, 2015

cos(ωt + α) 2 Vqdo = √ × sin(ωt + α) 3 1 [ √2

2π 2π + α) cos (ωt + + α) sin(ωt) 3 3 2π 2π 2π 2 sin (ωt − + α) sin (ωt + + α) × √ × VL × sin (ωt − 3 ) 3 3 3 2π 1 1 [sin (ωt + 3 )] ] √2 √2

cos (ωt −

(10)

Expanding (10) gives rise to (11) and this forms the a.c mains supply voltage in q-d-o frame:

Vqdo = P × VABC

Vq VL sin α = [VL cos α] = [Vd ] (11) V0 0

Similarly, the inverter output voltage in q-d-o reference frame is obtained as follows:

Eqdo = P × EABC cos(ωt + α) 2 Eqdo = √ × sin(ωt + α) 3 1 [ √2

(12)

2π 2π + α) cos (ωt + + α) sin(ωt + α) 3 3 2π 2π 2π 2 sin (ωt − + α) sin (ωt + + α) × √ × M × sin (wt − 3 + α) × Uc 3 3 3 2π 1 1 [ sin (ωt + 3 + α) ] ] √2 √2

cos (ωt −

(13)

Expanding (13) result to (14) which form the inverter output voltage in q-d-o reference frame:

0 Eqdo = P × EABC = [M] Uc 0

IC1 + IC2 = 2IC = FIabc sin(ωt + α) Where F = √

Eq = [Ed ] (14) E0

−R L

3

2π 3 2π 3

+ α) (18) + α) ]

to (19): T −T

2IC = F P

1 Vq − eq iq ]×[ ]+ [ ] id L Vd − ed

× M × sin (wt −

Transforming (17) into q-d-o reference frame results

frame gives rise to (15) as shown: −ω

2

[ sin (ωt +

Transforming (4) into their respective q-d-o reference ∂iq −R [ ∂t ] = [ L ∂id ω ∂t

(17)

Iqdo = [0

M

Iq 0] × [Id ] (19) Io

(15) The capacitors voltage is given by (20) which is

Substituting the values of Vq, eq, Vd and ed (11) and

further simplified to (21) by the substitution of (19)

(14) into (15) results to (16) :

into (20).

∂iq −R [ ∂t ] = [ L ∂id ω ∂t

−ω 1 iq ]×[ ] + −R id L L −VL sin α ×[ ] (16) VL cos α − MUc

From the second assumption considered above, it is observed that the inverter supply current which

∂Uc Ic = ∂t C

(20)

∂Uc MId = ∂t 2C

(21)

corresponds to the dc current flowing across the capacitor bus is given as:

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∂Iq

The total reactive power delivered by the thyristor controlled static var compensator (SVC) on the a.c mains via RL load is given by (22)

Qc = Vq Iq + Vd Id

∂t ∂Id

Where𝐗̇(𝐭) =

(22)

∂t ∂Uc

[ ∂t ] −R L

Substituting the values of Vq and Vd from (11) into (22)

Iq ; X(t) = [ Id ] ; Uc

ω

0

The inverter under this condition is forced to operate

VL −R −M A = ω ; B = [L ]; 0 L L M 0 0 0 [ ] 2C C = [−𝑉𝐿 0 0] ; U(t) = ∆α ;

optimally by injecting more reactive power to the a.c lines

The Laplace transformation of (27) and (28) results

to compensate for the drop in voltage on the line. This

to (29) and (30)

results to (23) as shown below:

Qc = −VL sin α Iq + VL cos α Id

(23)

During a transient disturbance along the a.c mains connected to the inverter through a reactor, there is a resultant voltage drop accompanying this line disturbance.

occurs when the control delay angle of the inverter is made equal to 900. Under the above condition, the total output (reactive) power from (23) changes to (24)

107

Qc = −VL Iq

SX(s) − X(0) = AX(s) + BU(s)

(29)

Y(s) = CX(s)

(30)

Assuming

(24)

The state space and the output equation for the above

X (0) = 0,

X(s) = [SI − A]−1 × BU(s)

(31)

analysis is presented in (25) and (26): 𝜕𝐼𝑞 𝜕𝑡 𝜕𝐼𝑑 𝜕𝑡 𝜕𝑈𝑐 [ 𝜕𝑡 ]

Qc=

−𝑅 𝐿 =

𝜔 [ 0

[−VL

0

−𝜔 −𝑅 𝐿 𝑀 2𝐶

Y(s) = C[SI − A]−1 × BU(s)

0

−𝑉𝐿 𝐼𝑞 −𝑀 × [ 𝐼𝑑 ] + [ 𝐿 ] × ∆𝛼 0 𝐿 𝑈𝑐 0 0 ]

Iq 0] × [ Id ] Uc

(25)

(32)

The transfer function of the above equation is presented in (33)

(26)

Qc(s) ∆α(s)

= C[SI − A]−1 × B

(33)

Where Qc(s) = Y(s) and U(s) = ∆α(s) substituting the

Where ∆α represents the incremental change in the inverter

values of ABC and SI into (33) gives (34) where I is

control delay angle corresponding to the transient

identity matrix.

disturbance on the line

Qc(s) = ∆α(s)

The dynamic equations of (25) and (26) give rise to (27)

V2L L

S3 +

2R s2

and (28) respectively [6]:

𝐗̇(𝐭) =

AX(t) + BU(t)

(27)

L

[S2 + R 2

Rs L

+ [( ) + L

+

M2 2LC

M2 2LC

]

+ ω2 ] s +

M2 R

(34)

2L2 C

The values of VL and RLC as well as the frequency used in this analysis are as follows:

Y =

CX(t)

(28)

VL = 415volts, R = 0.4Ω, L =100mH, C = 1000μF, M = 0.8, ω=100π.

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Substituting these values into (34) gives rise to (35)

Where

as follows:

1722250×(𝑠2 +4𝑠 +3200) G(s) = 3 𝑠 +8𝑠2 +101912.044𝑠+128000

(𝑠 2

𝑄𝑐(𝑠) 1722250 × + 4𝑠 + 3200) = 3 ∆𝛼(𝑠) 𝑠 + 8𝑠 2 + 101912.044𝑠 + 128000

(35)

The characteristic equation from control law is

and H(s) = 1 as shown in Figure 3

achieved when 1+G(s) H(s) = 0.

1722250 × (𝑠 2 + 4𝑠 + 3200) 𝑠 3 + 8𝑠 2 + 101912.044𝑠 + 128000

Qc(s)

∆α(s)

Fig.3 Block diagram of the transfer function of SVC This implies that

𝑠 3 + 1722258𝑠 2 + 6990912.044𝑠 + 5511328000 = 0

108

Applying the Routh-Hurwitz stability criterion to the above non-linear polynomial equation gives the

The auxiliary equation from the s2 row is given by:

following [7]:

1722258s2+ 551132800 = 0;

Table: 1 Routh- Hurwitz coefficient of characteristic equation

The value of s from this equation is obtained as:

1

6990912.044

locus plot shown in Fig.4where the two dots

s2

1722258

5511328000

represent +j56.57 and –j56.57 along the vertical

s1

6987711.981

0

s0

5511328000

0

s

3

s = ± j56.57. This value is confirmed in the root-

plane. This positive and negative value of s shows that the control system is marginally stable [8]. Appendix 1 represents the root-locus program.

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Root Locus 0.034

0.024

0.017

0.0115

0.007

0.0035

70 60

60 0.055

50 40

40

30

Imaginary Axis

20

0.12

20 10

0 10 -20

20

0.12

30 -40

40 50

0.055 -60

60 0.034

-3

-2.5

0.024 -2

0.017 -1.5

0.0115

0.007

-1

0.0035

70

-0.5

0

Real A xis

Fig.4: Root-locus plot of a static var compensator 4 Simulation of a Unified Power Flow Controller

capacitor linking the two converters. When there is a

A unified power flow controller (UPFC) consists of

voltage drop due to transient disturbance on the line

two switching power converters connected to each

such as a three phase fault, the inverter is forced to

other back to back through a d.c link capacitor. The

operate to compensate for this drop in voltage by

two converters (Rectifier and Inverter) are connected

injecting reactive power to the system. As the

to the AC supply system by a shunt and series

operation of the inverter continues, the capacitor

transformers. The rectifier is a three phase full bridge

voltage discharges. During this process the rectifier is

converter with six pulses which is designed using

set into operation to recharge the capacitor to its

diode rectifiers. The inverter is a three level inverter

original value; hence maintaining the normal

that is made up of twelve pulses using IGBT as the

operation of the UPFC. In this simulation analysis, a

switching source.

three phase to ground solid fault was applied at two

The principle of operation of the UPFC is analyzed as

separate periods on a transmission line. The results

follows: Under normal operation, the rectifier charges

obtained

are

shown

in

Figures:,5-8

up the d.c 5 Simulation Results of the unified Power Flow Controller under study.

D. B. NNADI, C. O. OMEJE, C. N. OBETTA

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500

300

400 300 200 Fault voltage (volts)

Prefault line voltage (volts)

200

100

0

-100

100 0 -100 -200 -300

-200 -400

-300

-500

0

0.02

0.04

0.06

0.08 0.1 0.12 time(second)

0.14

0.16

0.18

0.2

Figure 5 Pre-fault a.c voltage waveform of UPFC

0

0.02

0.04

0.06

0.08 0.1 0.12 time(second)

0.14

0.16

0.18

0.2

Figure 6 Fault voltage waveform of UPFC

250 400

200

100

200

50

voltage(volts)

Postfaultline voltage(volts)

Prefault voltage Inverter voltage

300

150

0 -50

100 0 -100

-100 -200

-150

-300

-200 -250

0

0.05

0.1 time(second)

0.15

0.2

Figure 7 Post-fault ac voltage waveform

-400

0

0.01

0.02

0.03

0.04 0.05 0.06 time(second)

0.07

0.08

0.09

0.1

Figure 8 Inverter & pre-fault voltage waveform

6 Conclusions

ground solid fault occurred on the transmission line,

This paper presented the equation modeling of a three

thus, reducing the voltage at this interval to a zero

level static var compensator

(SVC) and the

potential. In Figure 8 it is also observed that when the

simulation of a unified power flow controller. The

fault on the line is cleared the voltage on the line

foregoing analysis of the three level SVC using the

tends to build up above the zero level. This is

Routh-Hurwitz stability criterion deduced from the

achieved by the operation of the inverter as it

characteristic equation proved that the system under

discharges the capacitor voltage through the injection

analysis is marginally stable as confirmed from the

of current to the a.c supply which compensates for

root-locus plot in Figure 4.

the drop in the transmission line voltage. During this

The simulation results obtained above show that

process, the output voltage of the inverter tends to

when a three phase to ground solid fault is applied on

decrease as the capacitor discharges as shown in

a transmission line, there is always a drop in the a.c

Figure 9. Additionally, as the capacitor discharges, its

supply voltage of the transmission lines as indicated

voltage also decreases and this process causes the

in Figures 7 - 8. It is observed that within the period

rectifier to act by charging back the capacitor through

of 0.02s to 0.042s and 0.12s to 0.14s a three phase to

the injection of reactive power into the a.c supply.

D. B. NNADI, C. O. OMEJE, C. N. OBETTA

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The waveforms presented in Figure 9 proved that the inverter voltage and the a.c supply voltage are in phase. Thus conforming to the principle of unified power flow controller

References [1]Saadat, H. Power System Anaysis, Mc-Graw Hill Companies, Inc New York. 2202, [2]Weedy, B.M & Cory, B.J. Electric PowerSystems. Fourth Edition, John Wiley & Sons. 1998 [3] Draou, A. Benghanem, M. Tahiri, A. Kttni, L. ‘’ A new Approach to modelling Advanced Static Var Compensator”, Conf. RecIEEE/ CESA April,1998 vol.3,N0.7, 578, Hammamet, Tunisia,

[4] Peng, F.z and Lai, J.S, “A multi-level Voltage-source Inverter for static var generator applications’’, in Journal of Japan IEE, 1994 [5] Watanabe, E.H. Stephen, R.M and Aredes, M. “New concepts of Instantaneous active and reactive powers in electrical systems with generic loads’’, IEEE Trans. Power Deliv., April,1993, Vol.8, N0.2, pp.697-703, [6]Akagi, H. Kanazawa, Y. Nabae, A.,“Generalized Theory of The Instantaneous Reactive Power in Three phase circuit’’, IPEC, Tokyo, 1983, pp.1375-1386. [7]Dass, H.K., Advanced Engineering Mathematics, S.Chand and Company ltd, New Delhi. 2010 [8]Ogata, K., Modern Control Engineering. Fourth Edition. Pearson Education Press. New York. 2003

D. B. NNADI, C. O. OMEJE, C. N. OBETTA

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