Program Assignment 1, EE5352 1. Using the histogram pseudocode ...
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Program Assignment 1, EE5352 1. Using the histogram pseudocode ...
Nsmt, which is related to the amount of histogram smoothing to use. Create
arrays x, y, z with dimensions Nx, Ny, and Ny respectively. GET MAX AND MIN
OF x.
Program Assignment 1, EE5352 1. Using the histogram pseudocode given on the last 3 pages, construct a histogram function which inputs an array x of dimension Nx and a parameter Ny, which is the number of desired histogram bins. The outputs are a histogram array y of dimension Ny and a second array z of dimension Ny. After calculating a histogram, you can plot y versus z. 2. Using a random number generator, generate 1000 pseudorandom numbers uniformly distributed between -.5 and .5 , and store them in an array x. Nx is therefore 1000. Plot the histogram produced if Ny = 20. 3. Generate and plot the histogram of array x1 if x1 is generated as follows. For i = 1 to 999 x1 (i) = x(i) + x(i+1) end 4. Generate and plot the histogram of array x2 if x2 is generated as follows. For i = 1 to 998 x2 (i) = x(i) + x(i+1) + x(i+2) end
Pseudocode for the histogram function is given below. Given: Nx data samples in an array x Ny, which is the desired number of bins in the histogram, and Nsmt, which is related to the amount of histogram smoothing to use Create arrays x, y, z with dimensions Nx, Ny, and Ny respectively GET MAX AND MIN OF x Xm=x(1) Xn=Xm For i = 2 to Nx IF(x(i) > Xm)Xm=x(i) IF(x(i) < Xn)Xn=x(i) End B=(Ny-.02)/(Xm-Xn) A=1.01-B×Xn For i = 1 to Ny y(i)=0. End CALCULATE BIN ARRAY y For i = 1 to Nx II=A+B×x(i) II=floor(II) y(II)=y(II)+1. End SMOOTH y AND PUT IT IN z Xv=1./(2.*Nsmt+1.) I1=Nsmt+1 I2=Ny-Nsmt Np=2×Nsmt+1 For i= I1 to I2 S=0. J1=i-Nsmt-1 For j = 1 to Np
J1=J1+1 S=S+y(J1) End z(i)=XV×S End IF(Nsmt = 0)GO TO 9 Np=1.5×NSMT+.5 XV=1./Np For i=1 to I1-1 S=0. For j= 1 to Np S=S+y(i+j-1) End z(i)=XV×S End For i= I2+1 to Ny S=0. For j=1 to Np S=S+Y(I-J+1) End z(i)=XV×S End PUT SMOOTHED Z BACK INTO Y 9
For i=1 to Ny y(i)=z(i) End PUT X-AXIS INTO Z For i=1 to Ny z(i)=(i-A)/B End NORMALIZE Y SO THAT ITS INTEGRAL IS 1. G=0. For i=1 to Ny G=G+y(i) End V=B/G For i=1 to Ny
y(i)=V×y(i) End The final histogram is y(i) versus z(i) for i= 1 to Ny
