Feb 1, 2018 - Results have been received by EDeQUAL, but will take time to show up fully on your school's password ....
LAUNCH SESSION 1 February 2018
SCHOOL ROUND RESULTS Schools in Karachi, Lahore, Islamabad and Peshawar participated in the School Round − Over 150 private and government schools − Around 7000 students Technology was implemented smoothly by all schools − “It has been a great experience for students as well as our computer technician and of course, me.” Munira Gareeb, Coordinator - Froebel Education Centre Results have been received by EDeQUAL, but will take time to show up fully on your school’s password protected site − Technology automatically sorts results according to school code − In some cases, students put the wrong code so results don’t automatically show − We are manually sorting the data based on school names and these will take a few days to reflect on the website All schools now progress to the preliminary round of the competition - Challenging school round is a learning experience for participants
QUESTIONS AND SOLUTIONS We provided access to sample questions before the School Round via our website − Class 7: www.goo.gl/2GbYgE − Class 8: www.goo.gl/EJHLXz − Class 9: www.goo.gl/r6K2qH − Class 10: www.goo.gl/FGQ4d7 We also provided free access to EDeQUAL’s online assessments for students to test their Math ability − quiz.edequal.com − Choose one of 5 packages: − Copper and Bronze for Pakistan National curriculum − Silver, Gold and Platinum for international/O level curriculum Despite these resources, many students found the quiz questions challenging School Round questions and their worked solutions will be available on quiz.edequal.com
COMPETITION DATES Round 1: School Round
Round 2: Preliminary Round
Round 3: Regional Round
Round 4: Final Round
Conducted within each school computer lab
Conducted at external venue
Conducted at external venue
Conducted at KSBL
Karachi
Setup: 15-21 Jan Test: 22-29 Jan 2018
19 - 21 Feb 2018
22 Feb 2018
24 Feb 2018
Lahore
Setup: 15-21 Jan Test: 22-29 Jan 2018
14 – 15 Feb 2018
15 Feb 2018
Islamabad
Setup: 15-21 Jan Test: 22-29 Jan 2018
16 Feb 2018
16 Feb 2018
Peshawar
Setup: 15-21 Jan Test: 22-29 Jan 2018
17 Feb 2018
17 Feb 2018
FORMAT: PRELIMINARY ROUND • Number of students in team: 2 lower class + 2 higher class = 4 • Pool based competition with 8-9 teams per pool • Format: − Quiz: teams break into two groups (lower class and upper class), and each group must answer 6 questions that are timed (3 min/question). Scores are tallied, no negative marking. − Speedquiz: All teams will be asked 10 questions (2 min/question). Scores are for correct answer, bonus points for first team to answer correctly, and negative marking for incorrect answer. − Total time: 1:30
• Progression to next round:
− Highest scoring team in each pool progresses to next round. In the event of a tie for first position, both teams progress. − Additional teams progress to regional round based on scores, until regional round team requirement is fulfilled.
• Each team will be provided:
− Tablet computer to answer questions − Paper and pens/pencils
FORMAT: REGIONAL ROUND • Number of students in team: 1 lower class + 1 higher class = 2 • Up to 12 competing teams in one pool • Format: − Hotspot: All teams will be asked a question. The first team to hit the buzzer will have 5 seconds to give their answer. If they get it correct, we proceed to the next question. If they get it wrong, the remaining teams get to hit the buzzer and answer the same question. Scoring: for correct answer and negative marking for incorrect answer. − Jeopardy: 24 questions. Each team gets to choose a question from different Math categories. Questions carry different points. Team members are allowed to discuss with each other before answering. The question is displayed on the screen for all the teams. The choosing team has the first go and must answer within 90 seconds. If first team answers correctly, it wins the designated points. If it answers incorrectly or cannot answer, it gets zero points and the question is open to the floor. The first team to buzz is then asked to answer. It has 5 seconds to answer the question. If it answers correctly it gains the points. If it answers incorrectly it loses the same number of points. − Total time: 2:00
FORMAT: REGIONAL ROUND • Progression to next round: − Each regional winner from 3 regions: Karachi, Lahore, and Islamabad/Peshawar. − Highest scoring teams until total teams in final = 12.
• Awards:
− Regional winners
• Each team will be provided: − Tablet computer to answer questions − Paper and pens/pencils
FORMAT: FINAL • Number of students in team: 1 lower class + 1 higher class = 2 • Top 12 teams nationwide compete • Format: − − − −
Speedquiz Hotspot Jeopardy Total time: 2:00
• Awards:
− National Math Champion. − National Runner-up.
• Each team will be provided:
− Tablet computer to answer questions − Paper and pens/pencils
EXAMPLE QUESTION: CLASS 7
EASY
Question: Mir, Suha and Sami decided to share 20 sweets. Mir took 8 sweets and Suha took three times as many sweets as Sami. How many sweets did Sami get? Solution: Total number of sweets = 20 Mir = 8, Sami = x, Suha = 3x 8+x+3x = 20 8 + 4x = 20 4x = 20-8 4x = 12 X=3 Answer: 3 sweets
EXAMPLE QUESTION: CLASS 7
MEDIUM
Question: Two positive integers have a sum of 11. What is the greatest possible product of these two positive integers? Solution: Possible integer pairs are: 10 + 1, 9 + 2, 8 + 3, 7 + 4, 6 + 5 Multiply each pair together Greatest result: 6 x 5 = 30 Answer: 30
EXAMPLE QUESTION: CLASS 7
HARD
Question: A rectangular tank, measured internally, is 4.5 m long, 5.5 m wide and 3 m high. The rate at which the tank is being filled is 1 m3 per second. A small leak in the tank loses water at the rate of 15 m3 per minute. How much time will it take to fill one-third of the tank? Solution: V = 4.5 * 5.5 * 3 = 74.25 m3 Rate of filling tank = 1 m3 per second Rate of leaking water = 15/60 = 0.25 m3 per second Therefore net rate of filling tank = 1 – 0.25 = 0.75 m3 per second Rate = volume per unit time (V / t) 0.75 = 74.25 / t t = 74.25/ 0.75 = 7425/75 = 297/3 = 99 seconds to fill the entire tank Time required to fill one third of the tank = 99/3 = 33 seconds Answer: 33 seconds
EXAMPLE QUESTION: CLASS 8 Question: Solve for x in the diagram below. The diagram is not drawn to scale. Solution: 2x = 5x – 45 3x = 45 x = 15 Answer: 15 o
EASY
EXAMPLE QUESTION: CLASS 8
MEDIUM
Question: A family went on a picnic to the beach. They drove there at an average speed of 45 km/h and returned on the same road at an average speed of 67 km/h. The total driving time was 4 hours 30 min. How far was the beach from their home? Solution: Distance travelled = D going + D returning = 2D Ave speed over total distance = (45 + 67)/2 = 56 km/h Speed = Distance / Time 56 km/h = 2D(km) / 4.5 (hrs) 2D = 56 x 9 / 2 D = 126 km Answer: 126 km
EXAMPLE QUESTION: CLASS 8 Question: The hypotenuses of the 7 right triangles shown are all on the same line AB. What is angle x? Solution: Top triangle’s unknown angle = 180-90-40 = 50 degrees Note that each triangle on the left side of the diagonal AB is congruent Therefore X must be 50 degrees OR Use opposite angles are equal to work out each opposite angle along the diagonal AB Answer: 50 o
HARD
EXAMPLE QUESTION: CLASS 9
EASY
Question: Saba needs to divide Rs. 45 between her two younger siblings such that one sibling gets 25% more than the other sibling. What is the larger share? Solution: If smaller share = x, then larger share = 1.25x x + 1.25x = 45 x = 45 / 2.25 = 45 * 4 / 9 x = 20 1.25x = 25 Answer: 25
EXAMPLE QUESTION: CLASS 9
MEDIUM
Question: In the figure shown, a circle of radius 3 cm is enclosed in a square. Find the total area of the coloured parts. Write your answer correct to the nearest whole number. Take π = 22/7 Solution: Area of quarter square = 3 * 3 = 9 cm2 Area of quarter square minus quarter circle = 9 – (22/7*3*3)/4 Area of quarter square minus quarter circle = 27/14 cm2 Total shaded area = 9 + 27/14 = 11 cm2 (to nearest whole number) Answer: 11 cm2
EXAMPLE QUESTION: CLASS 9
HARD
Question: Asif tells the truth 70% of the time while Bushra tells the truth 80% of the time, independently of each other. They are shown an apple and asked "Is it an apple or a banana?” What is the probability that they will give different answers? Give your answer as a decimal to 2 decimal places. Solution: P (apple and apple) = .7 * .8 = .56 P (banana and banana) = .3 * .2 = .06 P (same fruit) = .56 + .06 = .62 P (different fruit) = 1 - .62 = .38 Answer: 0.38
EXAMPLE QUESTION: CLASS 10 Question: The midpoint of a line segment is (3,6). If one endpoint is (4,7), find: a. The other endpoint b. The equation of the line Solution: Plot line with two points given Difference between one endpoint and midpoint is (1,1) Therefore other endpoint = (3-1, 6-1) = (2,5) Since rise over run = 1/1 = 1 then slope of line = 1 Intercept of line on y axis will be 3 Equation of line y = 1x + 3 Answer: a. (2, 5) b. y = 1x + 3
EASY
EXAMPLE QUESTION: CLASS 10
MEDIUM
Question: A dessert recipe calls for 50% melted chocolate and 50% raspberry puree to make a particular sauce. A chef accidentally makes 15 cups of the sauce with 40% melted chocolate and 60% raspberry puree instead. How many cups of the sauce does he need to remove and replace with pure melted chocolate to make the sauce the proper 50% of each? Give your answer correct to 1 decimal place Solution: Cups of chocolate = 0.4*15=6 cups Cups of puree = 0.6 *15=9 cups Need 7.5 cups of chocolate in 15 cups of mixture Let x be the number of cups that are taken out of the mixture and replaced with pure chocolate 6 - 0.4x + x =7.5 X = 2.5 Answer: 2.5 cups
EXAMPLE QUESTION: CLASS 10
HARD
Question: A wall clock gains 2 mins in 12 hrs, while a table clock loses 2 mins in 36 hrs. Both are set at the correct time at noon today. In how many days, hours and minutes from today at noon will both clocks next show the correct time? Solution: In 36 hours, clock 1 gains 6 minutes and clock 2 loses 2 minutes. Clock 1- clock 2 = 6 - (-2)= 8 minutes in 36 hours. To show the same time, the clocks need to do a 12 hour revolution = 720 minutes. 720 minutes/8 minutes = 90 cycles of 36 hours Number of days = 90*36/24 = 135 days Answer: 135 days 0 hours 0 minutes
QUESTIONS?
